Exterior Angle Theorem
\(∠x\) is the exterior angle.
\(∠x + 92 = 180º\) (linear pair of angles)
\(∠x =\:180-92 = 88º\)
Applying the exterior angle theorem, we get, \(∠y + 41 = 88\)
\(∠y = 88-41= 47º\)
Exercises for Exterior Angle Theorem
- What is the value of \(p\) in the triangle?
- Find \(m∠YDC\).
- Find \(x\) in the given triangle and then find \(m∠ABD\).
- \(\color{blue}{60^{\circ }}\)
- \(\color{blue}{140^{\circ }}\)
- \(\color{blue}{x=5, m∠ABD = 100^{\circ }}\)
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