Word Problems Involving Area of Quadrilaterals and Triangles

In this article, the focus is on teaching you how to solve word problems involving the area of quadrilaterals and triangles.

Word Problems Involving Area of Quadrilaterals and Triangles

A step-by-step guide to word problems involving the area of quadrilaterals and triangles

The word problem is a way of learning the area of quadrilaterals and triangles better.

The area of a parallelogram: \(A=base×height\)

The area of a triangle: \(A=\frac{1}{2}(base×height)\)

The area of a trapezoid: \(A= \frac{1}{2}×\)(Sum of parallel sides)\(×\)(perpendicular distance in between the parallel sides). \(\frac{1}{2}×(AB ̅+DC) ̅×(d)\)

Word Problems Involving Area of Quadrilaterals and Triangles – Examples 1

Solve.
A triangle has an area of 64 square inches and a height of 16 inches. What is the length of the triangle’s base?
Solution:
Since the area of a triangle is \(\frac{1}{2}\)(base\(×\)height), then you must divide 64 by 16 and then multiply the product by 2 to find the length of its base.
\(64÷16=4\)
\(4×2=8\)
So, the length of the triangle’s base is 8 in.

Word Problems Involving Area of Quadrilaterals and Triangles – Examples 2

Solve.
The area of a parallelogram is \(484 ft^2\) and its height is 22 ft. What is the base length?
Solution:
Since the area of a parallelogram is base×height, so you have to divide 484 by 22 to find the base length.
\(484÷22=22\)
So, the base length of the parallelogram is 22 ft.

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