FREE 7th Grade STAAR Math Practice Test

1- What is the slope of a line that is perpendicular to the line \(4x-2y=12\)?

A. \(-\frac{1}{2}\)

B. \(-2\)

C. \(\frac{1}{2}\)

D. \(2\)

2- Simplify \(5(x-2y)+(2-x)^2\) when \(x=3\) and \(y=-2\).

A. \(12\)

B. \(24\)

C. \(36\)

D. \(40\)

3- The average of 50 numbers is 88. If a 94 is replaced by a 69, what is the new average?

A. \(85\)

B. \(86.5\)

C. \(87.5\)

D. \(88\)

4- The width of a rectangular box is one-third of its length, and the height of the box is one-third of its width. If the length of the box is \(27\) cm, what is the volume of the box?

A. \(81\) cm\(^3\)

B. \(162\) cm\(^3\)

C. \(243\) cm\(^3\)

D. \(729\) cm\(^3\)

5- In five successive hours, a car travels 40 km, 45 km, 50 km, 35 km, and 55 km. For the next five hours, it travels at an average speed of 50 km per hour. Find the total distance the car traveled in 10 hours.

A. 425 km

B. 450 km

C. 475 km

D. 500 km

6- The ratio of boys to girls in a school is 2:3. If there are 600 students in a school, how many boys are in the school?____________

7- The perimeter of the trapezoid below is 54 cm. What is its area? _________

8- In 1999, the average worker’s income increased by \($2,000\) per year starting from \($24,000\) annual salary. Which equation represents income more than \(I\), of a worker after \(x\) years of working since 1999?

A. \(I > 2000 x + 24000\)

B. \(I > -2000 x + 24000\)

C. \(I < -2000 x + 24000\)

D. \(I < 2000 x – 24000\)

9- Which of the following graphs represents the compound inequality?

A. Graph 1

B. Graph 2

C. Graph 3

D. Graph 4

10- A football team had $20,000 to spend on supplies. The team spent $14,000 on new balls. New sports shoes cost $120 each. Which of the following inequalities represents how many new shoes the team can purchase?

A. \( 120x+14,000 ≤20,000 \)

B. \(120x+14,000 ≥20,000\)

C. \(14,000x+12,0 ≤20,000 \)

D. \( 14,000x+12,0 ≥20,000 \)

11- Two dice are thrown at the same time. What is the probability of getting a sum of 6 or 9?

A. \(\frac{1}{3}\)

B. \(\frac{1}{4}\)

C. \(\frac{1}{6}\)

D. \(\frac{11}{36}\)

12- A swimming pool holds 2,000 cubic feet of water. The swimming pool is 25 feet long and 10 feet wide. How deep is the swimming pool? __________

13- Which graph corresponds to the following inequalities?
\(y≤ x + 4\)
\(2x + y ≤ – 4\)

A.

B.

C.

D.

14- A bank is offering \(4.5\%\) simple interest on a savings account. If you deposit $8,000, how much interest will you earn in five years?

The Ultimate Middle School Math Bundle Grades 6-8

Download

$109.99 Original price was: $109.99.$54.99Current price is: $54.99.

A. $360

B. $720

C. $1800

D. $3600

15- A card is drawn at random from a standard 52-card deck, what is the probability that the card is of Hearts? (The deck includes 13 of each suit clubs, diamonds, hearts, and spades)

A. \(\frac{1}{3}\)

B. \(\frac{1}{4}\)

C. \(\frac{1}{6}\)

D. \(\frac{1}{52}\)

16- How long does a 420-mile trip take moving at 50 miles per hour (mph)?

A. 4 hours

B. 6 hours and 24 minutes

C. 8 hours and 24 minutes

D. 8 hours and 30 minutes

17- 11 yards, 6 feet and 4 inches is equal to how many inches?

A. 388

B. 468

C. 472

D. 476

18- A shirt costing $200 is discounted \(15\%\). After a month, the shirt is discounted another \(15\%\). Which of the following expressions can be used to find the selling price of the shirt?

A. \((200) (0.70)\)

B. \((200) – 200 (0.30)\)

C. \((200) (0.15) – (200) (0.15)\)

D. \((200) (0.85) (0.85)\)

19- Which of the following points lies on the line \(2x + 4y = 10\)

A. \((2, 1)\)

B. \((–1, 3)\)

C. \((–2, 2)\)

D. \((2, 2)\)

20- \(5 + 8 × (–2) – [4 + 22 ×5] ÷ 6 = \)?

A. \(-30\)

B. \(-20\)

C. \(-10\)

D. 0

Best 7th Grade STAAR Math Prep Resource for 2027

Answers:

2- C
Simplify: \(5(x-2y)+(2-x)^2 = (5x-10y)+(4-4x+x^2) = x -10y +4 +x^2\)
When \(x=3\) and \(y=-2\),therefore:
\(x -10y +4 +x^2 =3+20+4+9 =36\)

3- C
\(average (mean) = \frac{sum \space of \space terms }{number \space of \space terms}⇒ 88 = \frac{sum \space of \space terms}{50}⇒ sum = 88 × 50 = 4400\)
The difference of 94 and 69 is 25. Therefore, 25 should be subtracted from the sum.
\(4400 – 25 = 4375\)
\(mean =\frac{sum \space of \space terms}{number \space of \space terms}⇒ mean = \frac{4375 }{50}= 87.5\)

4- D
If the length of the box is 27, then the box’s width is one-third of it, 9, and the height of the box is 3 (one-third of the width). The volume of the box is:
\(V = l.w.h = (27) (9) (3) = 729\)

5- C
Add the first 5 numbers. \(40 + 45 + 50 + 35 + 55 = 225\)
To find the distance traveled in the next 5 hours, multiply the average by number of hours.
\(Distance = Average × Rate = 50 × 5 = 250\)
Add both numbers.
\(250 + 225 = 475\)

6- 240
The ratio of boys to girls is 2:3. Therefore, there are 2 boys out of 5 students. To find the answer, first, divide the total number of students by 5, then multiply the result by 2.
\(600 ÷ 5 = 120 ⇒ 120 × 2 = 240\)

7- 130
The perimeter of the trapezoid is 54 cm.
Therefore, the missing side (height) is \(= 54 – 18 – 12 – 14 = 10\)
Area of a trapezoid:
\( A = \frac{1}{2}h (b_1 + b_2) = \frac{1}{2}(10) (12 + 14) = 130\)

8- A
Let \(x\) be the number of years. Therefore, $2,000 per year equals 2000\(x\).
starting from $24,000 annual salary means you should add that amount to 2000\(x\).
Income more than that is:
\(I > 2000x + 24000\)

9- D
Solve for \(x\).
\(-2≤2x-4<8 \)⇒ (add 4 all sides)\( -2+4≤2x-4+4<8+4 \)
\(⇒ 2≤2x<12 \)
⇒ (divide all sides by 2)\( 1≤x<6\)
\(x\) is between 1 and 6.

10- A
Let \(x\) be the number of new shoes the team can purchase. Therefore, the team can purchase 120 \(x\).
The team had $20,000 and spent $14000. Now the team can spend on new shoes $6000 at most.
Now, write the inequality:
(120x+14,000 ≤20,000)

11- B
For Sum 6: (1 & 5) and (5 & 1), (2 & 4) and (4 & 2), (3 & 3), so we have 5 options.
For sum 9: (3 & 6) and (6 & 3), (4 & 5) and (5 & 4), we have 4 options.
To get a sum of 6 or 9 for two dice: \(5+4=9\)
Since we have \(6 × 6 = 36\) total options, the probability of getting a sum of 6 and 9 is 9 out of 36 or \(\frac{1}{4}\).

12- 8
Use formula of rectangle prism volume.
\(V = (length) (width) (height) ⇒ 2000 = (25) (10) (height)\)
\( ⇒ height = 2000 ÷ 250 = 8\)

13- A
For each option, choose a point in the solution part and check it on both inequalities.
A. Point \((–4, –4)\) is in the solution section. Let’s check the point in both inequalities.
\(-4 ≤ – 4 + 4, \space It \space works\)
\(2 (–4) + (–4) ≤ –4 ⇒ – 12 ≤ – 4\) it works (this point works in both)
B. Let’s choose this point \((0, 0)\)
\(0 ≤ 0 + 4, \space It \space works\)
\(2 (0) + (0) ≤ –4, \space \space That’s \space not \space true!\)
C. Let’s choose this point \((–5, 0)\)
\(0 ≤ -5 + 4, \space That’s \space not \space true!\)
D. Let’s choose this point \((0, 5)\)
\(5 ≤ 0 + 4, \space That’s \space not \space true!\)

14- C
Use simple interest formula:
I=prt
(I = interest, p = principal, r = rate, t = time)
\(I=(8000)(0.045)(5)=1800\)

15- B
The probability of choosing a Hearts is \(\frac{13}{52}=\frac{1}{4}\)

16- C
Use distance formula:
\(Distance = Rate × time ⇒ 420 = 50 × T\)
divide both sides by 50.
\(\frac{420}{50} = T ⇒ T = 8.4 \space hours\)
Change hours to minutes for the decimal part.
\(0.4 \space hours = 0.4 × 60 = 24 \space minutes\)

17- C
\(11 × 36 + 6 × 12 + 4 = 472\)

18- D
To find the discount, multiply the number by (\(100\% – \)Rate of discount).
Therefore, for the first discount we get:
\((200) (100\% – 15\%) = (200) (0.85) = 170\)
For the next \(15%\) discount: \((200) (0.85) (0.85)\)

19- B
Input \((-1, 3)\) in the \(2x + 4y = 10\) formula instead of \(x\) and y. So we have:
\( 2(-1) + 4(3) = 10\)
\(-2 + 12 = 10\)

20- A
Use PEMDAS (order of operation):
\(5 + 8 × (–2) – [4 + 22 ×5] ÷ 6 = 5 + 8 × (–2) – [4 + 110] ÷ 6 = 5 + 8 × (–2) – [114] ÷ 6 = 5 + (–16) – 19 = 5 + (–16) – 19 = –11 – 19 = –30\)

Looking for the best resource to help you succeed on the Grade 7 STAAR Math test?

The Best Books to Ace the 7th Grade STAAR Math Test

STAAR Grade 7 Math Comprehensive Prep Bundle A Perfect Resource for STAAR Math Test Takers

Download

$69.99 Original price was: $69.99.$45.49Current price is: $45.49.

Rated 4.42 out of 5 based on 172 customer ratings

Satisfied 160 Students

Recommended EffortlessMath Books

For a STAAR-focused workbook to use alongside this test, the STAAR Grade 7 Math for Beginners (resource currently unavailable) walks through every TEKS topic with worked examples. For more grade-7 STAAR-format practice, see the 10 Full-Length STAAR Grade 7 Math Practice Tests.

What the Redesigned Grade 7 STAAR Math Test Looks Like

Since the 2023 redesign, STAAR is given mainly online, and the old griddable questions are gone. TEA’s grade 7 practice test shows the kinds of questions students now meet:

Multiselect questions trip up many students. One correct pick is not enough, so read how many answers the question wants.

On timing, TEA expects most students to finish within three to four hours. A student who needs more time may keep working until the end of the school day.

Using This Test with TEA’s Released Grade 7 Forms

TEA posts released grade 7 math forms for 2024, 2025 and 2026 on its practice test site, along with answer keys and item rationales that explain each answer. A simple plan:

1. Take our 20 questions on paper and mark every miss.
2. Review the worked solution for each miss and redo the problem a day later.
3. Take one TEA released form online, using the on-screen reference sheet and no calculator.
4. Read the item rationale for every question you missed or guessed.
5. Save a second released form for the week before the test.

Frequently Asked Questions

What is on the 7th grade STAAR math reference sheet?

The grade 7 STAAR reference sheet lists the formulas students are expected to use but not memorize, such as area and circumference of a circle, area of triangles and trapezoids, volume of prisms and pyramids, and interest formulas. Since grade 7 students get no calculator, have your student practice finding a formula on the sheet and then doing the arithmetic by hand.

Is there a 7th grade STAAR test practice PDF?

TEA no longer posts released STAAR tests as PDFs. Released grade 7 math forms are taken online through the Texas practice test site, while the answer keys and item rationales are still PDFs. For printable practice, you can copy the 20 questions above onto paper and check the worked solutions afterward.

Where can I find a free STAAR practice test?

TEA offers free released tests and practice tests on its online Texas assessment practice site, and they show the real question types. The 20-question grade 7 test above is another free option with worked solutions. A good plan is to take the TEA released form first to see the format, then use this test to drill the topics your student missed.

Is there an answer key for the 7th grade math STAAR practice test?

Yes. Every question in the practice test above has a worked solution, so your student can see each step, not just the letter. For example, question 3 asks for a new average: 50 × 88 = 4,400, then 4,400 − 94 + 69 = 4,375, and 4,375 ÷ 50 = 87.5. TEA also posts answer keys and item rationales for its released forms.

What is on the 7th grade math STAAR test?

The test follows the grade 7 TEKS: operations with rational numbers, proportional relationships such as ratios, percents, scale drawings and probability, one-variable equations and inequalities, geometry and measurement like circles and volume, and data analysis. Questions mix multiple choice with multiselect, drop-down and typed answers, so practice entering answers, not just picking letters.

When is the 7th grade STAAR test given?

Grade 7 STAAR math is given in the spring during a state testing window that TEA sets each school year, so the exact dates change from year to year. Check TEA’s student assessment calendar or ask your school for this year’s date. Starting practice tests about six to eight weeks ahead gives time to fix weak topics without cramming.

Related EffortlessMath Lessons

If a topic on this page feels rusty, these short lessons go deeper:

• Add and subtract rational numbers
• Solve ratio and proportion problems
• How to solve linear equations
• Area and perimeter
• Order of operations (PEMDAS)