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00:00 - 00:59 | in this question we argue that let ABC be three events is the probability of exactly what he went out of a and b is 1 - out of b - 81 and out and a 1 - X and that of 33 event simultaneous place at the square then we need to prove that the probability that at least one out of ABC will occur is greater than one by two not understand what does this mean rocking exactly one event out of A and B letter support that this would be a and b and b b show the event of acquiring exactly one of a and D will be this person this can also be written as a union B minus a intersection b show the probability |

01:00 - 01:59 | of Aakhri exactly one event out of the and B can be written as the probability of a union b - probability of a intersection b now we know that probability of a union B K written as probability of a + probability of b - probability of 8MB probability of a union b is equals to probability of a plus probability of the probability of a minus b have probability of a intersection b so we got the required probability that exactly one out of a and b blocker is equals to probability of a plus probability of B minus 2 into probability of a intersection b this is given as equals to 1 - X to be called the value of |

02:00 - 02:59 | 1 - similarly we can write that the probability of population of exactly one of the minus 3 equal to 1 minus 2 X will be equal to the value plus probability of 3 - 2 into probability of intersection C also we are given that probability of occurrence of exactly one of sea and 81 - 6 for this is one minus equal to probability of C plus probability of a minus 2 into probability of C intersection pay now we are also given that probability that his three events will simultaneously or queries x square so we are given that probability of a intersection b intersection C |

03:00 - 03:59 | is equals to x square and we need to find the probability that at least one out of ABC milakar so is probability can be written as probability of a union b union c to find this Probability and we know that the formula of gravity of a + probability of P + probability of C - probability of a intersection b minus probability of intersection C - probability of intersection + probability of A and B intersection C letter simplified is related with David multiply and divide with two so multiplied |

04:00 - 04:59 | to with pay it will Bittu let's to PB less to PC -2 probability of a intersection b minus 2 probability of B intersection C -2 probability of intersection a + b have less probability of a intersection b intersection C this can be written as probability of a less probability of be taken one from this 2 - probability of two into probability of a intersection b that is system + probability of be Sofia beauty lies topi topi b |

05:00 - 05:59 | + probability of the minus 2 into probability of B intersection C so we have utilised system also and finally plus a so we have utilised disturb plus PC Sophia beauty lies disturb -2 probability of C intersection a and plus we have plus probability of a intersection b intersection C now we know the value of 50 terms from here to hear from here to share and from here to hear the value of this term is equals to 1 - X square + of this will write on 1 - this will be close to half 1 - X + the value of this term is equal to 1 |

06:00 - 06:59 | minus 2 X so this will be plus one minus 2 X and the value of this term is equal to 1 -2 I will die Don 1 - 1 - x square given that provide duty of a intersection b intersection please x square so I will right now x square now a simplified so here we have 3 -4 x 3 - 4 x divided by 2 + x square is equals to x square - 2 X + 3 by 2 this can be written as x square - 2 X + 1 + 3 by 2 so this will be equals to this will not be 3 by 2 this will be |

07:00 - 07:59 | one by two since 1 + 1 by 2 is equal to 3 by 2 so this will be equal to x minus 1 whole square + 1 by 2 so we are getting a required at x minus 1 whole square + 1 by 2 now this is a square suggest will always be greater than equal to zero so this whole town will always be greater than equal to half and this is what we needed to prove |