GED Math FREE Sample Practice Questions

C.

D.

5- Last week 24,000 fans attended a football match. This week three times as many bought tickets, but one-sixth of them canceled their tickets. How many are attending this week?

A. 48,000

B. 54,000

C. 60,000

D. 72,000

6- The square of a number is \(\frac{25}{64} \). What is the cube of that number?

A. \(\frac{5}{8} \)

B. \(\frac{25}{254}\)

C. \(\frac{125}{512}\)

D. \(\frac{125}{64}\)

7- In the \(xy\)-plane, the point (4,3) and (3,2) are on line A. Which of the following points could also be online A?

A. \((-1, 2)\)

B. \((5, 7)\)

C. \((3, 4)\)

D. \((-1, -2)\)

8- What is the missing term in the given sequence? ____________
2, 3, 5, 8, 12, 17, 23, _, 38

9- What is the equivalent temperature of \(104^{\circ}\) F in Celsius?
C \(= \frac{5}{9} \) (F \(- 32\))

A. 32

B. 40

C. 48

D. 52

10- If \(150\%\) of a number is 75, then what is the \(90\%\) of that number?

A. 45

B. 50

C. 70

D. 85

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Answers:

1- B
The diagonal of the square is 8. Let \(x\) be the side.

Use Pythagorean Theorem: \(a^2 + b^2 = c^2 \)
\(x^2 + x^2 = 8^2 {\Rightarrow} 2x^2 = 82 {\Rightarrow} 2x^2 = 64 {\Rightarrow}x^2 = 32 {\Rightarrow}x= {\sqrt{32}}\)
The area of the square is:
\({\sqrt{32}} {\times} {\sqrt{32}} = 32\)

2- B
The perimeter of the trapezoid is \(36 cm\).
Therefore, the missing side (height) is \(= 36 – 8 – 12 – 6 = 10\)
Area of a trapezoid: A \(= \frac{1}{2} h ({b_{1} + b_{2}}) = \frac{1}{2} (10) (6 + 8) = 70\)

3- B
Use simple interest formula:
\(I=prt\)
(I = interest, p = principal, r = rate, t = time)
\(I=(12000)(0.035)(2)=840$\)

4- D
Solve for \(x\).
\(-2 {\leq} 2x-4 < 8 ⇒\) (add 4 all sides) \(-2+4 {\leq} 2x-4+4 < 8+4 {\Rightarrow}\)
\(2{\leq}2x<12 {\Rightarrow}\) (divide all sides by 2) 1 \({\leq}x < 6\)
\(x\) is between 1 and 6.

5- C
Three times 24,000 is 72,000. One-sixth of them canceled their tickets.
One sixth of 72,000 equals \(12,000 (\frac{1}{6}) (\times ) 72000 = 12000\).
\(60,000 (72000 – 12000 = 60000)\) fans are attending this week

6- C
The square of a number is \(\frac{25}{64}\), then the number is the square root of \(\frac{25}{64}\)
\(\sqrt{\frac{25}{64}}=\frac{5}{8}\)
The cube of the number is:
\(({\frac{5}{8}})^3 = \frac{125}{512}\)

7- D
The equation of a line is in the form of \(y=mx+b\), where m is the slope of the line and b is the \(y\)-intercept of the line.
Two points (4,3) and (3,2) are on line A. Therefore, the slope of the line A is:
slope of line A\(=\frac{(y_2- y_1)}{(x_2 – x_1 ) } =\frac{2-3}{3-4} = \frac{-1}{-1} \)
The slope of line A is 1. Thus, the formula of line A is:
\(y=mx+b=x+b\), choose a point and plug in the values of \(x\) and \(y\) in the equation to solve for b. Let’s choose points (4, 3). Then:
\(y=x+b \rightarrow 3=4+b\rightarrow b=3-4=-1\)
The equation of line A is: \(y=x-1\)
Now, let’s review the choices provided:
A. \((-1,2) \ \ y=x-1\rightarrow 2=-1-1=-2\) (This is not true.)
B. \((5,7) \ \ y=x-1\rightarrow 7=5-1=4\) (This is not true.)
C. \((3,4) y=x-1 \ \ \rightarrow 4=3-1=2\) (This is not true.)
D. \((-1,-2) y=x-1 \ \ \rightarrow -2=-1-1=-2\) (This is true!)

8- 30
The difference of 2 and 3 is 1, 3 and 5 is 2, 5 and 8 is 3, 8 and 12 is 4, 12 and 17 is 5, 17 and 23 is 6, 23 and next number should be 7. The number is 23 + 7 = 30

9- B
Plugin 104 for F and then solve for C.
C \(= \frac{5}{6}\) (F \(- 32) {\Rightarrow}\) C \(= \frac{5}{9} (104 – 32) {\Rightarrow} C = \frac{5}{9} (72) = 40\)

10- A
First, find the number.
Let \(x\) be the number. Write the equation and solve for \(x\).
\(150\%\) of a number is 75, then:
\(1.5{\times}x=75 {\Rightarrow} x=75{\div}1.5=50\)
\(90\%\) of 50 is:
\(0.9 {\times} 50 = 45\)

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