Algebra Puzzle – Challenge 57

Algebra Puzzle – Challenge 57

This mathematical puzzle requires some kind of math to solve. Let’s challenge your brain with a great math challenge!

Challenge:

The sum of three positive integers is 4000. The ratio of the first number to the second number is \(\frac{2}{3}\) and the ratio of the first number to the third number is \(\frac{6}{5}\). What is the third number?

A- 800

B- 1000

C- 1200

D- 1600

E- 2000

The Absolute Best Book to challenge your Smart Student!

The correct answer is B.

Let X, Y and Z represent the three numbers. So,
X + Y + Z = 4000 and
\(X = \frac{2}{3} Y → Y = \frac{3}{2}X\)
\(X = \frac{6}{5} Z → Z = \frac{5}{6}X\)
Replace the values of Y and Z in the first equations with their values in the second and third equations:
\(X + \frac{3}{2}X + \frac{5}{6}X = 4000 →X = 1200\)
\(Y = \frac{3}{2}X → Y = \frac{3}{2} (1200) = 1800\)
\(Z = \frac{5}{6}X → Z = \frac{5}{6}(1200) = 1000\)
The third number, Z, is 1000.

Related to "Algebra Puzzle – Challenge 57"

Other Topics Puzzle – Challenge 100
Other Topics Puzzle – Challenge 100
Other Topics Puzzle – Challenge 99
Other Topics Puzzle – Challenge 99
Other Topics Puzzle – Challenge 98
Other Topics Puzzle – Challenge 98
Other Topics Puzzle – Challenge 97
Other Topics Puzzle – Challenge 97
Other Topics Puzzle – Challenge 96
Other Topics Puzzle – Challenge 96
Other Topics Puzzle – Challenge 95
Other Topics Puzzle – Challenge 95
Other Topics Puzzle – Challenge 94
Other Topics Puzzle – Challenge 94
Intelligent Math Puzzle – Challenge 93
Intelligent Math Puzzle – Challenge 93
Intelligent Math Puzzle – Challenge 92
Intelligent Math Puzzle – Challenge 92
Intelligent Math Puzzle – Challenge 91
Intelligent Math Puzzle – Challenge 91

Leave a Reply

Your email address will not be published. Required fields are marked *