How to Graph Linear Inequalities? (+FREE Worksheet!)
How to Graph Linear Inequalities
Graphing a linear inequality is graphing a line, then shading the side that makes it true. Two small decisions, dashed or solid boundary, and which side to shade, are the whole game. We’ll nail both with a test point. Solver, drills, and a worksheet maker a tap away.
Graph Linear Inequalities: what to notice and how to work it
What to notice first
Common student mistake
Key formulas and cues
A reliable path
- Solve the boundaryTemporarily treat the inequality like an equation.
- Choose the sideUse the sign or test a number if the direction is not obvious.
- Graph the solutionUse the correct endpoint and shade the values that work.
Worked examples
Flip the sign
- Divide both sides by -3.
- Reverse the inequality sign.
- Simplify 12 divided by -3.
Keep the sign
- Subtract 5 from both sides.
- No negative multiplication or division happened.
- Keep the sign direction.
Try one before moving on
Graph Linear Inequalities: pop-up practice

To graph a linear inequality, you do two things: draw the boundary line, then shade the side of the plane that makes the inequality true. Every point in the shaded region is a solution, which means a linear inequality has infinitely many solutions, a whole region of them. Two small choices decide everything, and a single “test point” settles both. Get these two right and every inequality graph works the same way.
Boundary Line + Shaded Region
A linear inequality like \(y < 2x - 1\) splits the coordinate plane into two halves with a boundary line. One half makes the inequality true; you shade it.
How to graph a linear inequality (3 steps):
- Graph the boundary line \(y = mx + b\). Use a dashed line for \(<\) or \(>\) (boundary not included) and a solid line for \(\le\) or \(\ge\) (boundary included).
- Pick a test point not on the line, \((0,0)\) is easiest when the line doesn’t pass through it.
- If the test point makes the inequality true, shade its side; if false, shade the other side.
Graphing \(y < 2x - 1\)
The boundary \(y = 2x – 1\) is dashed (strict \(<\)). Test \((0,0)\): is \(0 < 2(0)-1 = -1\)? No, so \((0,0)\) is not in the region, and we shade the other side, below the line (away from the origin). The shaded half is the solution.
Graph an inequalityThe Two Decisions
Dashed or solid?
Is the boundary itself included?
\(\le\) or \(\ge\) → solid (included).
Which side?
Let a test point decide.
Predict, then verify
When it’s solved for \(y\):
Worked Examples
A. Strict, dashed line
Graph \(y < 2x - 1\).
Dashed boundary (strict). Test \((0,0)\): \(0 < -1\) is false, so shade the side away from the origin. Dashed line, shade below the line.
B. Inclusive, solid line
Graph \(y \ge -x + 3\) (see graph below).
Solid boundary (\(\ge\)). Test \((0,0)\): is \(0 \ge -0+3 = 3\)? No, the origin is out, so shade the other side (above the line). Solid line, shade above.
C. Through the origin
Graph \(y > x\).
The line passes through \((0,0)\), so test a different point like \((0,2)\): \(2 > 0\) is true. Dashed boundary, shade above the line. Pick a test point off the line.
D. A vertical boundary
Graph \(x \le 3\).
The boundary is the vertical line \(x=3\), drawn solid (\(\le\)). Test \((0,0)\): \(0 \le 3\) is true, so shade everything to the left. Here a test point is the only reliable method.
Where This Shows Up
Regions show up whenever there’s a limit with two variables. If hot dogs cost $2 and drinks $3 and you have at most $12, then \(2x + 3y \le 12\), and every point in the shaded region is a combination you can afford. Businesses use these shaded “feasible regions” to plan production within budget and time limits. The graph turns a money rule into a picture of every choice that works.
Easy Points to Lose
- Wrong boundary style. Strict (\(<\), \(>\)) is dashed; inclusive (\(\le\), \(\ge\)) is solid. Mixing these up is the most common deduction.
- Shading the wrong side. Always test a point. Don’t guess from the sign alone, especially if the inequality isn’t solved for \(y\).
- Testing a point on the line. The test point must be off the boundary, or it can’t tell you anything. Pick \((0,0)\) unless the line goes through it.
- Forgetting to flip when solving for \(y\). If you divide by a negative to isolate \(y\), flip the inequality first, then graph.
Your Turn: Boundary and Shading
For each inequality, state whether the boundary is dashed or solid and whether \((0,0)\) is in the solution. Reveal to check.
- \(y \le x + 1\)
- \(y > 2x\)
- \(y < -x + 2\)
Show answers
- \(\color{blue}{\text{solid; } (0,0): 0\le 1 \text{ true → shade the side with the origin}}\)
- \(\color{blue}{\text{dashed; } (0,0)\text{ on line, test }(0,1): 1>0 \text{ true → shade above}}\)
- \(\color{blue}{\text{dashed; } (0,0): 0<2 \text{ true → shade the side with the origin}}\)
Make Your Own Inequality-Graphing Worksheet
Generate fresh inequalities to graph, with a full answer key, print or save as a PDF.
Frequently Asked Questions
When is the boundary line dashed vs. Solid?
Dashed for strict inequalities (\(<\) or \(>\)) because the points on the line are not solutions. Solid for \(\le\) or \(\ge\) because the boundary points are included.
How do I know which side to shade?
Pick a test point that isn’t on the line (usually \((0,0)\)) and plug it in. If the inequality is true, shade that point’s side; if false, shade the opposite side.
What if the boundary passes through the origin?
Then \((0,0)\) is on the line and can’t be a test point. Choose any other off-line point, like \((0,1)\), and test that instead.
How is this different from graphing a line?
You still graph the line, but you also decide dashed vs. Solid and shade a whole half-plane. The solution is a region of points, not just the line.
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Continue Your Study
Ready for the next step? Pick up right where this lesson leaves off:
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