HSPT Math Practice Test Questions
Preparing for the HSPT Math test? Try these free HSPT Math Practice questions. Reviewing practice questions is the best way to brush up on your Math skills. Here, we walk you through solving 10 common HSPT Math practice problems covering the most important math concepts on the HSPT Math test. For additional educational resources, visit the U.S. Department of Education website.
These HSPT Math practice questions are designed to be similar to those found on the real HSPT Math test. They will assess your level of preparation and will give you a better idea of what to study for your exam. For additional educational resources, visit the U.S. Department of Education website.
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rac{5}{11},\frac{3}{8},\frac{5}{7}\)
C. \(\frac{1}{7},\frac{3}{8},\frac{5}{11},\frac{5}{7}\)
D. \(\frac{3}{8},\frac{1}{7},\frac{5}{11},\frac{5}{7}\)
7- A boat sails \(120\) miles south and then \(50\) miles east. How far is the boat from its start point?
A. \(45\) miles
B. \(130\) miles
C. \(160\) miles
D. \(170\) miles
8- The ratio of boys and girls in a class is \(4:7\). If there are \(55\) students in the class, how many more boys should be enrolled to make the ratio \(1:1\)?
A. 8
B. 10
C. 15
D. 20
9- Sophia purchased a sofa for \($530.20\). The sofa is regularly priced at \($631\). What was the percent discount Sophia received on the sofa?
A. \(12\%\)
B. \(16\%\)
C. \(20\%\)
D. \(25\%\)
10- The score of Emma was half that of Ava, and the score of Mia was twice that of Ava. If the score of Mia was \(40\), what is the score of Emma?
A. 5
B. 10
C. 20
D. 40
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Answers:
1- C
\(3x+2y=11\). Plug in the values of \(x \) and \(y\) from the choices provided. Then:
☐A. \((-1,3) \ \ \ 3x+2y=11→3(-1)+2(3)=11→-3+6=11\) NOT true!
☐B. \((2,3) \ \ \ 3x+2y=11→3(2)+2(3)=11→6+6=11\) NOT true!
☐C. \((-1,7) \ \ \ 3x+2y=11→3(-1)+2(7)=11→-3+14=11\) Bingo!
☐D. \((0,2) \ \ \ 3x+2y=11→3(0)+2(2)=11→0+4=11\) Nope!
2- C
Let \(x\) be the number. Write the equation and solve for \(x\).
\(\frac{2}{3}×9= \frac{2}{5 } . x ⇒ \frac{2×9}{3}= \frac{2x}{5}\) , use cross multiplication to solve for \(x\).
\(5×18=2x×3 ⇒90=6x ⇒ x=15\) For education statistics and research, visit the National Center for Education Statistics.
3- B
To find the discount, multiply the number by (\(100\%-\)rate of discount).
Therefore, for the first discount we get: \((D) (100\%-15\%) = (D) (0.85) = 0.85 D\)
For increase of \(10\%: (0.85 D) (100\%+10\%)=(0.85 D) (1.10)=0.93D =93\%\) of D For education statistics and research, visit the National Center for Education Statistics.
4- B
Use the formula for Percent of Change \(\frac{New \ Value-Old \ Value}{Old \ Value}×100\% \)
\(\frac{28-45}{45}×100\%=-37.7\%\) (Negative sign here means that the new price is less than the old price). For education statistics and research, visit the National Center for Education Statistics.
5- D
Some of prime numbers are: \(2,3,5,7,11,13\). Find the product of two consecutive prime numbers: \(2×3=6\) (not in the options),\(3×5=15\) (not in the options),\(5×7=35\) (bingo!),
\(7×11=77\) (not in the options) For education statistics and research, visit the National Center for Education Statistics.
6- C
Let’s compare each fraction:\(\frac{1}{7} < \frac{3}{8} < \frac{5}{11} < \frac{5}{7}\). Only choice C provides the right order. For education statistics and research, visit the National Center for Education Statistics.
7- B
Use the information provided in the question to draw the shape.
Use Pythagorean Theorem: \(a^2+ b^2=c^2 \)
\(120^2+50^2=c^2 ⇒ 14400+2500= c^2 ⇒ 16900=c^2 ⇒ c=130 \) For education statistics and research, visit the National Center for Education Statistics.
8- C
The ratio of boys to girls is \(4:7\). Therefore, there are \(4\) boys out of \(11\) students. To find the answer, first, divide the total number of students by \(11\), then multiply the result by \(4. 55÷11=5 ⇒ 4×5=20\). There are \(20\) boys and \(35 (55-20) \)girls. So, \(15\) more boys should be enrolled to make the ratio \(1:1\) For education statistics and research, visit the National Center for Education Statistics.
9- B
The question is this: \(530.20\) is what percent of \(631\)? Use the percent formula:
part\(=\frac{percent}{100}×\)whole. \(530.20=\frac{percent}{100}×631 ⇒ 530.20= \frac{percent ×631}{100} ⇒ 53020 =\)percent \(×631 ⇒\) percent\(=\frac{53020}{631}=84.02≅84\) .
\(530.20\) is \(84\%\) of \(631\). Therefore, the discount is: \(100\%-84\%=16\%\)
10- B
If the score of Mia was \(40\), therefore the score of Ava is \(20\). Since the score of Emma was half that of Ava, therefore, the score of Emma is \(10\).
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