# How to Solve Linear Inequalities?

Inequalities are mathematical expressions in which both sides are not equal. In the following guide, you will learn more about linear inequality and solving it.

In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

**Related Topics**

**Step by step guide to** **solving linear inequalities**

Polynomial inequalities are inequalities that can be expressed as polynomials on one side and zeros on the other. There are many types of polynomial inequalities, but the most important are:

- Linear Inequalities
- Quadratic Inequalities

**Solving linear inequalities**

A linear inequality is an inequality that can be expressed by a linear expression on one side and a \(0\) on the other. Solving linear inequalities is like solving linear equations, but only the rules for solving inequalities must be observed.

**Solving one-step inequalities**

Consider an inequality of \(3x<6\). To solve it, just one step is enough to divide both sides by \(3\). Then we get \(x<2\). Therefore, the solution to the inequality is \(x < 2\) or \((-∞, 2)\).

**Solving two-step inequalities**

Consider an inequality \(-2x + 3> 6\). To solve this, we need two steps. The first step is subtracting \(3\) from both sides, which gives \(-2x > 3\). Then we need to divide both sides by \(-2\) and it results in \(x < -\frac{3}{2}\) (note that we have changed the sign of the inequality). So the solution of the inequality is \(x < -\frac{3}{2}\) or \((-∞, -\frac{3}{2})\).

**Solving compound inequalities**

Compound inequalities refer to the set of inequalities with either “**and**” or “**or**” in-between them. For solving inequalities, in this case, just solve each inequality independently and then find the final solution according to the following rules:

- The final solution is the intersection of the solutions of independent inequalities if we have “and” between them.
- The final solution is the union of the solutions of the independent inequalities if we have “or” between them.

**Solving Linear Inequalities** **– Example 1:**

Solve the compound inequality \(2x + 3< -5\) and \(x + 6 < 3\).

**Solution:**

By first inequality:

\(2x + 3 < -5\)

\(2x < -8\)

\(x < -4\)

By second inequality,

\(x + 6 < 3\)

\(x < -3\)

Since we have “and” between them, we have to find the intersection of the sets \(x< -4\) and \(x<-3\). Then the final solution is: \(x< -4\) or \((-∞, -4)\).

**Exercises for ****Solving Linear Inequalities**

**Solve each inequality and write the answer in the interval notation.**

- \(\color{blue}{-21< 2x+3\le17}\)
- \(\color{blue}{7x-5\ge 65\:or\:-3x-2\ge -2}\)
- \(\color{blue}{3x+1\le 3\:\:and\:-2x\le 6}\)
- \(\color{blue}{-20<\frac{1}{4}x+2\le 8}\)

- \(\color{blue}{(-12,7]}\)
- \(\color{blue}{(-\infty \:,\:0]\cup \:[10,\:\infty \:)}\)
- \(\color{blue}{\:\left[-3,\:\frac{2}{3}\right]}\)
- \(\color{blue}{\:(-88,\:24]}\)

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