How to Solve Multi-Step Inequalities? (+FREE Worksheet!)

How to Solve Multi-Step Inequalities? (+FREE Worksheet!)
Algebra 1

How to Solve Multi-Step Inequalities

A multi-step inequality is solved almost exactly like a multi-step equation — distribute, combine like terms, gather the variable — with one rule on top: if you multiply or divide both sides by a negative, flip the inequality sign. We’ll work through it carefully, with a solver, drills, and a worksheet maker a tap away.

Illustration of students learning How to Solve Multi-Step Inequalities

If you can solve a multi-step equation, you’re most of the way to solving a multi-step inequality. You do the same moves — distribute, combine like terms, get the variable by itself — but you carry an inequality sign along instead of an equals sign, and there’s one rule that catches almost everyone: multiply or divide by a negative, and the sign flips. The reward is an answer that’s a whole range of values, not a single number.

In short: simplify both sides, gather the variable, then isolate it — and flip the inequality whenever you multiply or divide both sides by a negative. For example, \(3x + 2 > x + 10\) becomes \(x > 4\).

The big idea

Solve Like an Equation, Watch for the Flip

Adding or subtracting never changes the direction of an inequality. Multiplying or dividing by a positive doesn’t either. The only move that reverses the sign is multiplying or dividing both sides by a negative number — because that mirrors every value across zero, reversing their order.

How to solve (4 steps):

  1. Distribute to clear parentheses.
  2. Combine like terms on each side.
  3. Gather the variable on one side; move constants to the other.
  4. Divide to isolate the variable — and flip the sign if you divided by a negative.
Tutor tip: One way to dodge the flip entirely: move the variable to whichever side keeps its coefficient positive. For \(5 – 3x \ge x + 9\), adding \(3x\) to both sides avoids ever dividing by a negative.

Worked Examples

Same moves as a multi-step equation — then read the range off the number line.

Example A — Variables on both sides

Solve \(3x + 2 > x + 10\).

  1. Subtract \(x\) from both sides to gather the variable: \(2x + 2 > 10\).
  2. Subtract 2: \(2x > 8\).
  3. Divide by 2 (positive, no flip): \(x > 4\). Graph: open circle at 4, arrow right.

Answer: \(x > 4\)

-7-6-5-4-3-2-101234567

Example B — Distribute first

Solve \(2(x – 1) \le 8\).

  1. Distribute the 2: \(2x – 2 \le 8\).
  2. Add 2 to both sides: \(2x \le 10\).
  3. Divide by 2: \(x \le 5\). Graph: closed circle at 5, arrow left.

Answer: \(x \le 5\)

-8-7-6-5-4-3-2-1012345678

Example C — Divide by a negative (flip!)

Solve \(-2x + 3 < 7\).

  1. Subtract 3 from both sides: \(-2x < 4\).
  2. Divide by \(-2\) — dividing by a negative, so flip: \(x > -2\).
  3. Graph: open circle at \(-2\), arrow right.

Answer: \(x > -2\)

-6-5-4-3-2-10123456

Example D — Negative after gathering

Solve \(5 – 3x \ge x + 9\).

  1. Subtract \(x\) and 5 from both sides: \(-4x \ge 4\).
  2. Divide by \(-4\) and flip: \(x \le -1\).
  3. Graph: closed circle at \(-1\), arrow left.

Answer: \(x \le -1\)

-6-5-4-3-2-10123456

Where You’ll Use It

Multi-step inequalities show up whenever a real situation involves a limit and a few moving parts: staying within a budget after a setup fee, keeping a grade above a cutoff, or making sure a load stays under a weight cap. Solving one tells you the full set of values that keep you on the right side of the line.

Easy Points to Lose

  • Forgetting to flip. The classic miss — dividing or multiplying by a negative without reversing the sign.
  • Flipping when you shouldn’t. Adding or subtracting (even a negative) never flips the sign; only multiplying/dividing by a negative does.
  • Distributing to one term. \(2(x – 1)\) is \(2x – 2\); multiply both terms inside.
  • Reading the final direction wrong. After a flip, double-check which way the symbol points before you graph it.

Your Turn: Solve

Solve each, flipping when needed, then reveal the answers.

  1. \(4x – 1 < 2x + 7\)
  2. \(3(x + 2) \ge x + 10\)
  3. \(-x + 4 \le 2x – 5\)
  4. \(2x + 9 > 5x\)
  5. \(10 – 2x \le 4\)
  6. \(\dfrac{x}{2} + 1 > 3\)
Show answers (with graphs)
  1. \(\color{blue}{x<4}\)
  2. \(\color{blue}{x\ge 2}\)
  3. \(\color{blue}{x\ge 3 \text{ (flipped)}}\)
  4. \(\color{blue}{x<3 \text{ (flipped)}}\)
  5. \(\color{blue}{x\ge 3 \text{ (flipped)}}\)
  6. \(\color{blue}{x>4}\)
1. \(x < 4\)
-7-6-5-4-3-2-101234567
2. \(x \ge 2\)
-6-5-4-3-2-10123456
3. \(x \ge 3\)
-6-5-4-3-2-10123456
4. \(x < 3\)
-6-5-4-3-2-10123456
5. \(x \ge 3\)
-6-5-4-3-2-10123456
6. \(x > 4\)
-7-6-5-4-3-2-101234567
Keep practicing

Make Your Own Inequalities Worksheet

Generate fresh multi-step inequalities with a full answer key — print or save as a PDF.

New problems every click — never the same sheet twice
Step-by-step answer key so you can self-check
⚖️

Frequently Asked Questions

When do I flip the inequality sign?

Only when you multiply or divide both sides by a negative number. Adding or subtracting never flips it.

How is this different from a multi-step equation?

The steps are identical — distribute, combine, isolate — except you keep an inequality sign and flip it when dividing or multiplying by a negative. The answer is a range, not one value.

How can I avoid flipping at all?

Move the variable to the side that keeps its coefficient positive. Then you only ever divide by a positive number, so the sign never flips.

How do I check my answer?

Pick a number inside your solution range and plug it into the original inequality; it should be true. Test one outside the range to confirm it’s false.

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