Geometry Puzzle – Challenge 71
This is a fun and engaging math puzzle to challenge even the smartest students and help them develop logic skills. For additional educational resources, . For additional educational resources
[include_netrun_products_block from-products="product/the-ultimate-middle-school-math-bundle/" product-list-class="bundle-products float-left" product-item-class="float-left" product-item-image-container-class="p-0 float-left" product-item-image-container-size="col-2" product-item-image-container-custom-style="" product-item-container-size="" product-item-add-to-cart-class="btn-accent btn-purchase-ajax" product-item-button-custom-url="{{url}}/?ajax-add-to-cart={{id}}" product-item-button-custom-url-if-not-salable="{{productUrl}} product-item-container-class="" product-item-element-order="image,title,purchase,price" product-item-title-size="" product-item-title-wrapper-size="col-10" product-item-title-tag="h3" product-item-title-class="mt-0" product-item-title-wrapper-class="float-left pr-0" product-item-price-size="" product-item-purchase-size="" product-item-purchase-wrapper-size="" product-item-price-wrapper-class="pr-0 float-left" product-item-price-wrapper-size="col-10" product-item-read-more-text="" product-item-add-to-cart-text="" product-item-add-to-cart-custom-attribute="title='Purchase this book with single click'" product-item-thumbnail-size="290-380" show-details="false" show-excerpt="false" paginate="false" lazy-load="true"]
Challenge:
The total weight of a box and the candies it contains is 12 pounds. After \(\frac{2}{3}\) of the candies are eaten, the box and the remaining candies weigh 5 pounds. What is the weight of the empty box in pounds?
A- \(\frac{2}{3}\)
B- 1
C- \(\frac{3}{2}\)
D- \(2\frac{1}{2}\)
E- 5
The Absolute Best Book to challenge your Smart Student!
The correct answer is C.
Let “B” be the weight of the box and “C” be the weight of the candies. So:
B + C = 12
After \(\frac{2}{3}\) of the candies are eaten, the box and the remaining candies weigh 5 pounds. So,
B + \(\frac{1}{3}\) C = 5
Solve the system of two equations:
B + C = 12 → B = 12 – C
B + \(\frac{1}{3}\) C = 5 → 12 – C + \(\frac{1}{3}\) C = 5 → 12 – \(\frac{2}{3}\) C = 5 → C = 10.5
B = 12 – C → B = 12 – 10.5 = 1.5
The weight of the box is 1.5 pounds.The Best Books to Ace Algebra
Original price was: $27.99.$17.99Current price is: $17.99.
Related to This Article
More math articles
- Expert Advice on Making Math Fun
- Word Problems of Converting Percent, Fractions, and Decimals
- Unlocking the Mystery: How to Add Fractions with Different Denominators Using Visual Models
- Word Problems Involving Area of Quadrilaterals and Triangles
- Is ALEKS a Good Mathematics Program?
- How to Solve Word Problems of Counting Bills and Coins
- The Ultimate ISEE Upper-Level Math Course (+FREE Worksheets & Tests)
- FREE CLEP College Math Practice Test
- Geometry Puzzle – Challenge 59
- How to Unraveling the Transitive Property: A Key to Understanding Mathematical Relationships
What people say about "Geometry Puzzle – Challenge 71 - Effortless Math: We Help Students Learn to LOVE Mathematics"?
No one replied yet.