Top 10 8th Grade OST Math Practice Questions

Top 10 8th Grade OST Math Practice Questions

Top 10 8th Grade OST Math Practice Questions is a multiple-choice math challenge from Effortless Math. Read the problem, choose from the answer options below, then open the solution to see the full step-by-step working and check your reasoning against it.

Math diagram
Math diagram

C.

Math diagram

D.

Math diagram

5- In the rectangle below, if (y>5) cm and the area of a rectangle is 50 cm(^2) and the perimeter of the rectangle is 30 cm, what are the values of x and y, respectively?

A. (4, 11)

B. (5, 11)

C. (5, 10)

D. (4, 10)

6- A football team had $40,000 to spend on supplies. The team spent $22,000 on new balls. New sports shoes cost $240 each. Which of the following inequalities represents how many new shoes the team can purchase?

A. (240x+22,000 ≤40,000 )

B. (240x+22,000 ≥40,000)

C. (22,000x+240 ≤40,000)

D. (22,000x+240 ≥40,000)

7- Right triangle ABC has two legs of lengths 6 cm (AB) and 8 cm (AC). What is the length of the third side (BC)?

A. 4 cm

B. 6 cm

C. 8 cm

D. 10 cm

8- If (3x-5=8.5), What is the value of (5x+3)?

A. 13

B. 15.5

C. 20.5

D. 25.5

9- A bank is offering (4.5%) simple interest on a savings account. If you deposit $8,000, how much interest will you earn in five years?

A. $360

B. $720

C. $1800

D. $3600

10- In a party, 10 soft drinks are required for every 12 guests. If there are 252 guests, how many soft drinks is required?

Original price was: $109.99.Current price is: $54.99.

A. 21

B. 105

C. 210

D. 2510

Best 8th Grade OST Math Prep Resource for 2026

Answers:

1- C
The weight of 12.2 meters of this rope is: (12.2 × 600 g = 7320 g)
(1 kg = 1000 g)
therefore,
(7320 g ÷ 1000 = 7.32 kg)

2- 600
The ratio of boys to girls is (3:7).
Therefore, there are 3 boys out of 10 students. To find the answer, first, divide the number of boys by 3, then multiply the result by 10.
(180 ÷ 3 = 60 ⇒ 60 × 10 = 600)

3- C
the population is increased by (15%) and (20%). (15%) increase changes the population to (115%) of the original population.
For the second increase, multiply the result by (120%).
((1.15) × (1.20) = 1.38 = 138%)
38 percent of the population is increased after two years.

4- B
A linear equation is a relationship between two variables, (x) and (y), that can be put in the form (y = mx + b).
A non-proportional linear relationship takes on the form (y=mx + b), where (b ≠ 0) and its graph is a line that does not cross through the origin.

5- C
The perimeter of the rectangle is: (2x+2y=30→x+y=15→x=15-y )
The area of the rectangle is: (x×y=50→(15-y)(y)=50→y^2-15y+50=0)
Solve the quadratic equation by the factoring method.
((y-5)(y-10)=0→y=5 )
(Unacceptable, because y must be greater than 5) or (y=10)
If ( y=10 →x×y=50→x×10=50→x=5)

6- A
Let (x) be the number of new shoes the team can purchase. Therefore, the team can purchase (240 x).
The team had $40,000 and spent $22,000. Now the team can spend on new shoe ($18,000) at most.
Now, write the inequality: ( 120x+22.000 ≤40.000)

7- D
Use Pythagorean Theorem:
(a^2 + b^2 = c^2)
(6^2 + 8^2 = c^2 ⇒ 100 = c^2 ⇒ c = 10)

8- D
(3x-5=8.5→3x=8.5 + 5=13.5→x = frac{13.5}{3}= 4.5)
Then;
(5x+3=5 (4.5)+3=22.5+3=25.5)

9- C
Use simple interest formula:
(I=prt)
((I = interest, p = principal, r = rate, t = time))
(I=(8000)(0.045)(5)=1800)

10- C
Let (x) be the number of soft drinks for 252 guests. Write the proportion and solve for (x).
(frac{10 soft drinks}{12 guests}=frac{x}{252 guests})
(x = frac{252×10}{12}⇒x=210)

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