Geometry Puzzle – Challenge 71
This is a fun and engaging math puzzle to challenge even the smartest students and help them develop logic skills.

Challenge:
The total weight of a box and the candies it contains is 12 pounds. After \(\frac{2}{3}\) of the candies are eaten, the box and the remaining candies weigh 5 pounds. What is the weight of the empty box in pounds?
A- \(\frac{2}{3}\)
B- 1
C- \(\frac{3}{2}\)
D- \(2\frac{1}{2}\)
E- 5
The Absolute Best Book to challenge your Smart Student!

The correct answer is C.
Let “B” be the weight of the box and “C” be the weight of the candies. So:
B + C = 12
After \(\frac{2}{3}\) of the candies are eaten, the box and the remaining candies weigh 5 pounds. So,
B + \(\frac{1}{3}\) C = 5
Solve the system of two equations:
B + C = 12 → B = 12 – C
B + \(\frac{1}{3}\) C = 5 → 12 – C + \(\frac{1}{3}\) C = 5 → 12 – \(\frac{2}{3}\) C = 5 → C = 10.5
B = 12 – C → B = 12 – 10.5 = 1.5
The weight of the box is 1.5 pounds.
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