Using a set of valuable questions for your students to further practice can be effective in preparing for the 6th Grade MEAP Math test. Using the top 10 6th Grade MEAP Math Practice questions provided in this article, your students can test their skills. These updated questions cover math concepts and topics found in the actual 6th Grade MEAP Math test. Full answers and explanations of the questions also are provided at the end of the post.

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## 6th Grade MEAP Math Practice Questions

1- Which expression is equivalent to \(5(12x-16)\)?

A. \(-20\)

B. \(-20x\)

C. \(60x – 16\)

D. \(60x – 80\)

2- To produce a special concrete, for every 13 kg of cement, 3 liters of water is required. Which of the following ratios is the same as the ratio of cement to liters of water?

A. 91: 21

B. 14: 4

C. 39: 6

D. 9: 39

3- What is the value of \(x\) in the following equation: \(-60=115-x\)

A. 175

B. \(-175\)

C. 55

D. \(-55\)

4- Which of the following graphs represents the following inequality?

\(-8≤5x-8≤2\)

A.

B.

C.

D.

5- The ratio of boys to girls in a school is 4:5. If there are 765 students in the school, how many boys are in the school?

A. 612

B. 510

C. 425

D. 340

6- Martin earns $20 an hour. Which of the following inequalities represents the amount of time Martin needs to work per day to earn at least $100 per day?

A. \(20t≥100\)

B. \(20t≤100\)

C. \(20+t≥100\)

D. \(20+t≤100\)

7- \((55+5)÷12\) is equivalent to …

A. \(60÷3.4\)

B. \( \frac{55}{12}+5\)

C. \((2×2×3×5)÷(3×4)\)

D. \( (2×2×3×5)÷3+4\)

8- What is the value of the expression \(6(2x-3y)+(3-2x)^2\), when \(x=2 \) and \(y=-1\)?

A. \(-23\)

B. 41

C. 43

D. 49

9- Round \(\frac{215}{7}\) to the nearest tenth.

A. 31

B. 30.8

C. 30.7

D. 30

10- A chemical solution contains \(6\%\) alcohol. If there is 45 ml of alcohol, what is the volume of the solution?

A. 270 ml

B. 420 ml

C. 750 ml

D. 1,200 ml

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## Answers:

1- **D**

\(5(12x-16)=(5×12x)-(5×16)=(5×12)x-(5×16)=60x-80\)

2- **A**

\(91 : 21 = 13 : 3\)

\(13×7=91\)

And \( 3×7=21\)

3- **A**

\(-60 = 115 – x\)

First, subtract 115 from both sides of the equation. Then:

\(-60 – 115=115 – 115- x→-175 = – x\)

Multiply both sides by \((-1)\):

\(→x = 175\)

4- **B**

\(-8≤5x-8<2 →\) (add 8 all sides)\(-8+8≤5x-8+8<2+8 →0≤5x<10→\) (divide all sides by 5) \(0≤x<2\)

5- **D**

The ratio of boy to girls is 4:5. Therefore, there are 4 boys out of 9 students. To find the answer, first divide the total number of students by 9, then multiply the result by 4.

\(765 ÷ 9 = 85 ⇒ 85 × 4 = 340\)

6- **A**

For one hour he earns $20, then for t hours he earns $20t. If he wants to earn at least $100, therefor, the number of working hours multiplied by 20 must be equal to 100 or more than 100.

\(20t≥100\)

7- **C**

\((55+5)÷(12)=(60)÷(12)\)

The prime factorization of 60 is: \(2×2×3×5 \)

The prime factorization of 12 is: \( 3×4 \)

Therefore: \((60)÷(12)=(2×2×3×5)÷(3×4)\)

8- **C**

Plug in the value of \(x\) and \(y\) and use order of operations rule.

\(x=2\) and \(y=-1\)

\(6(2x-3y)+(3-2x)^2=6(2(2)-3(-1))+(3-2(2))^2=6(4+3)+(-1)^2 = 42+1=43\)

9- **C**

\(\frac{215}{7} ≅ 30.71 ≅ 30.7\)

10- **C**

\(6\%\) of the volume of the solution is alcohol. Let \(x\) be the volume of the solution.

Then: \(6\% \space of \space x = 45 \space ml ⇒ 0.06 x = 45 ⇒ x = 45 ÷ 0.06 = 750\)

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