6th Grade MEAP Math FREE Sample Practice Questions

The area of the trapezoid is: area\(= \frac{(base 1+base 2)}{2}×\)height\(= (\frac{10 + 16}{2})x = A\)
\( →13x = A→x = \frac{A}{13}\)

\(\frac{104}{8}=13, \frac{1352}{104}=13, \frac{17576}{1352}=13\)
Therefore, the factor is 13

Simplify each option provided.
A. \(-20-(3×10)+(6×40)=-20-30+240=190\)
B. \((\frac{15}{8})×72 + (\frac{125}{5}) =135+25=160\)
C. \(((\frac{30}{4} + \frac{15}{2})×8) – \frac{11}{2} + \frac{222}{4} = ((\frac{30 + 30}{4})×8)- \frac{11}{2}+ \frac{111}{2}=(\frac{60}{4})×8) + \frac{100}{2}= 120 + 50 = 170\)
this is the answer
D. \(\frac{481}{6} + \frac{121}{3}+50= \frac{481+242}{6}+50=120.5+50=170.5\)

1 yard \(= 3\) feet
Therefore, \(3,768 ft × \frac{1 \space yd }{3 \space ft}=1,256 \space yd\)

3,400 out of 74,800 equals to \(\frac{3,400}{74,800}=\frac{17}{374}=\frac{1}{22}\)

Prime factorizing of \(20=2×2×5\)
Prime factorizing of \(12=2×2×3\)
LCM\(=2×2×3×5=60\)

Plugin the value of \(x\) into the function f. First, plug-in 3.1 for\( x\).
A. \(f=2x-\frac{3}{10}=2(3.1)-\frac{3}{10}=5.9≠8.6\)
B. \(f=x+\frac{3}{10}=3.1+\frac{3}{10}=3.4≠10.8\)
C. \(f=2x+2 \frac{2}{5}=2(3.1)+2 \frac{2}{5}=6.2+2.4=8.6\)
This is correct!
Plug in other values of \(x. (x=4.2)\)
\(f=2x+2\frac{2}{5} =2(4.2)+2.4=10.8 \)
This one is also correct.
\(x=5.9\)
\(f=2x+2 \frac{2}{5}=2(5.9)+2.4=14.2 \)
This one works too!
D. \(2x+\frac{3}{10}=2(3.1)+\frac{3}{10}=6.5≠8.6\)

1 kg\(= 1000\) g and 1 g \(= 1000\) mg
\(96\) kg\(= 96 × 1000\) g \(= 96 × 1000 × 1000 = 96,000,000\) mg

The diameter of a circle is twice the radius. Radius of the circle is \(\frac{25}{2}\).
Area of a circle = \(πr^2=π(\frac{25}{2})^2=156.25π=156.25×3.14=490.625≅491\)

Average (mean) \(=\frac{sum \space of \space terms}{number \space of \space terms}= \frac{10+11+15+14+15+17+12.5}{7}=13.5\)