The best way to prepare for your GED Math test is to work through as many GED Math practice questions as possible. Here are the top 10 GED Math practice questions to help you review the most important GED Math concepts. These GED Math practice questions are designed to cover mathematics concepts and topics that are found on the actual test. The questions have been fully updated to reflect the latest 2020 GED guidelines. Answers and full explanations are provided at the end of the post.

Start your GED Math test prep journey right now with these sample GED Math questions.

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## GED Math Practice Questions

1- What is the value of the expression \((5(x-2y)+(2-x))^2 \) when \(x=3\) and \(y=-2\) ?

☐A. 20

☐B. 50

☐C. 1,156

☐D. 36

2- What is the slope of a line that is perpendicular to the line \(4x-2y=12\)?

☐A. \(-2\)

☐B. 4

☐C. 2

☐D. \(-\frac{1}{2}\)

3- Which of the following is equal to the expression below?

\((2x+2y)(2x-y)\)

☐A. \(4x^2- 2y^2\)

☐B. \(2x^2+6xy-2y^2\)

☐C. \(24x^2+2xy-2y^2\)

☐D. \(4x^2+2xy-2y^2\)

4- What is the product of all possible values of \(x\) in the following equation?

\(|x-10| = 3\)

☐A. \(3\)

☐B. \(7\)

☐C. \(13\)

☐D. \(91\)

5- The average weight of girls in a class is and the average weight of boys in the same class is . What is the average weight of all the students in that class?

☐A. \(111\)

☐B. \(-112\)

☐C. \(-122\)

☐D. \(-144\)

6- What is the value of \(x\) in the following system of equations?

\(2x+5y=11\)

\(4x-2y=-14\)

☐A. \(-1\)

☐B. \(1\)

☐C. \(4\)

☐D. \(-2\)

7- What is the median of these numbers? \(2, 27, 28, 19, 67, 44, 35\)

☐A. \(19\)

☐B. \(28\)

☐C. \(44\)

☐D. \(35\)

8- A swimming pool holds \(2,000\) cubic feet of water. The swimming pool is \(25\) feet long and 10 feet wide. How deep is the swimming pool? ________

9- The area of a circle is \(64 π\). Which of the following is the circumference of the circle?

☐A. \(8π\)

☐B. \(12π\)

☐C. \(16π\)

☐D. \(64π\)

10- What is the value of \(3^6 \)? _________

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## Answers:

1- **C**

Plug in the value of \(x\) and \(y\).

\(x=3 \space and \space y=-2\)

\((5(x-2y)+(2-x))^2=(5(3-2(-2))+(2-3))^2=(5(3+4)+(-1))^2 = (34)^2=1,156\)

2- **D**

The equation of a line in slope intercept form is: \(y=mx+b\)

Solve for \(y\).

\(4x-2y=12 {\Rightarrow} -2y=12-4x {\Rightarrow} y=(12-4x){\div}(-2) {\Rightarrow} y=2x-6\)

The slope of this line is \(2\).

The product of the slopes of two perpendicular lines is \(-1\).

Therefore, the slope of a line that is perpendicular to this line is:

\(m_{1} {\times} m_{2} = -1 {\Rightarrow} 2 {\times} m_{2} = -1 {\Rightarrow} m_{2} = \frac{-1}{2}\)

3- **D**

Use FOIL method.

\((2x+2y)(2x-y) = 4x^2-2xy+4xy-2y^2=4x^2+2xy-2y^2\)

4- **D**

To solve absolute values equations, write two equations.

\(x-10\) could be positive \(3\), or negative \(3\). Therefore,

\(x-10=3 \Rightarrow x=13\)

\(x-10=-3 \Rightarrow x=7\)

Find the product of solutions: \((7 \times 13 = 91 )\)

5- **C**

Use PEMDAS (order of operation):

\([6 {\times} (- 24) + 8] – (- 4) + [4 × 5] {\div} 2 \)

\( [- 144 + 8] – (- 4) + [20] {\div} 2 = [- 144 + 8] – (- 4) + 10\)

\([- 136] – (- 4) + 10 = [- 136] + 4 + 10 = – 122\)

6- **D**

Solving Systems of Equations by Elimination

Multiply the first equation by \((-2)\), then add it to the second equation.

\({-2(2x+5y= 11) \ 4x-2y=-14} {\Rightarrow} {-4x-10y= -22 \ 4x-2y=-14} {\Rightarrow} {-12y= -36} {\Rightarrow} {y= 3}\)

Plug in the value of \(y\) into one of the equations and solve for \(x\).

\(2x+5(3)= 11 {\Rightarrow} 2x+15= 11 {\Rightarrow} 2x= -4 {\Rightarrow} x= -2\)

7- **B**

Write the numbers in order:

\(2, 19, 27, 28, 35, 44, 67\)

Median is the number in the middle. So, the median is \(28\)

8- **8**

Use formula of rectangle prism volume.

\(V = (length) (width) (height) {\Rightarrow} 2000 = (25) (10) (height){\Rightarrow} height = 2000 {\div} 250 = 8\)

9- **C**

The area of the circle is 16 π. Use the formula of areas of circles.

Area\( = πr^2 ⇒ 64 π> πr^2⇒ 64 > r^2⇒ r < 8\)

The radius of the circle is \(8\). Let’s put \(8\) for the radius. Now, use the circumference formula:

Circumference \(=2πr=2π (8)=16π\)

10- **729**

\(3^6 = 3 × 3 × 3 × 3 × 3 × 3 = 729\)

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