# 10 Most Common 3rd Grade IAR Math Questions Although math has always been a challenging subject for 3rd-grade students, familiarity with common test questions can greatly help students succeed in the IAR Math Test.

The 10 Most Common 3rd Grade IAR Math Questions prepared in this article are designed to be very similar in structure and complexity to the IAR Math Test questions. Our team has collected these math questions with great sensitivity and delicacy along with its step-by-step guide and put them at the service of 3rd-grade students to strengthen their math skills.

Make sure to follow some of the related links at the bottom of this post to get a better idea of what kind of mathematics questions your students need to practice.

## 10 Sample 3rd Grade IAR MathPractice Questions

1- Classroom $$A$$ contains $$8$$ rows of chairs with $$4$$ chairs per row. If classroom $$B$$ has three times as many chairs, which number sentence can be used to find the number of chairs in classroom $$B$$?

A. $$8 × 4 + 3$$

B. $$8 + 4 × 3$$

C. $$8 × 4 × 3$$

D. $$8 + 4 + 3$$

2- A cafeteria menu had spaghetti with meatballs for $$8$$ and bean soup for $$6$$. How much would it cost to buy three plates of spaghetti with meatballs and three bowls of bean soup? __________

3- There are $$7$$ days a week. There are $$24$$ hours in a day. How many hours are in a week?

A. $$48$$

B. $$96$$

C. $$168$$

D. $$200$$

4- Emily described a number using these clues:
Three-digit odd numbers that have a $$6$$ in the hundreds place and a $$3$$ in the tens place

A. $$627$$

B. $$637$$

C. $$632$$

D. $$636$$

5- This clock shows a time after $$12:00 PM$$. What time was it $$1$$ hour and $$30$$ minutes ago?

A. $$12:45 PM$$

B. $$1:45 PM$$

C. $$1:15 PM$$

D. $$12:15 PM$$

6- Olivia has $$84$$ pastilles. She wants to put them in boxes of $$4$$ pastilles. How many boxes does she need?

A. $$20$$

B. $$21$$

C. $$24$$

D. $$28$$

7- A football team is buying new uniforms. Each uniform costs $$20$$. The team wants to buy $$11$$ uniforms.
Which equation represents a way to find the total cost of the uniforms?

A. $$(20 × 10) + (1 × 11) = 200 + 11$$

B. $$(20 × 10) + (10 × 1) = 200 + 10$$

C. $$(20 × 10) + (20 × 1) = 200 + 20$$

D. $$(11 × 10) + (10 × 20) = 110 + 200$$

8- There are $$92$$ students from Lexington Elementary school at the library on Tuesday. The other $$54$$ students in the school are practicing in the classroom. Which number sentence shows the total number of students in Riddle Elementary school?

A. $$92 + 54$$

B.$$92 -54$$

C. $$92 × 54$$

D. $$92 ÷54$$

9- Use the picture below to answer the question.

Which fraction shows the shaded part of this square?

A. $$\frac{92}{100}$$

B. $$\frac{92}{10}$$

C. $$\frac{90}{100}$$

D. $$\frac{8}{100}$$

10- Which number correctly completes the number sentence $$90 × 25 =$$ ?

A. $$225$$

B. $$900$$

C. $$1,250$$

D. $$2,250$$

## Best 3rd Grade IAR Math Prep Resource for 2022

1- C
$$3$$ times of $$8$$ rows of chairs with $$4$$ chairs per day are: $$3 × 8 × 4$$

2- 42
$$3$$ spaghetti with meatballs cost: $$3 × 8 = 24$$
$$3$$ bowls of bean soup cost: $$3 × 6 = 18$$
$$3$$ spaghetti with meatballs $$+ 3$$ bowls of bean soup cost: $$24 +  18 = 42$$

3- C
$$1$$ day: $$24$$ hours so $$7$$ days $$= 7 × 24 = 168$$ hours

4- B
Three-digit odd numbers that have a $$6$$ in the hundreds place and a $$3$$ in the tens place is $$637$$, $$632$$ and $$636$$ are even numbers.

5- A
Subtract hours: $$14– 1 = 13$$
Subtract the minutes: $$15 – 30 = -15$$
The minutes are less than $$0$$, so:
• Add $$60$$ to minutes ( $$-15 +60 =45$$ minutes)
• Subtract $$1$$ from hours $$(13 – 1 =12)$$

6- B
Olivia wants to divide $$84$$ pastilles into boxes of $$4$$ pastilles, so $$84 ÷ 4 = 21$$ is the number of boxes.

7- C
The football team should buy $$11$$ uniforms that each uniform cost $$20$$ so they should pay$$(11×20) 220$$.
Therefore, choice C is correct answer:
$$(20 × 10) + (20 × 1) = 20(10+1) =20×11=220$$

8- A
Add $$92$$ and $$54$$ students to know the whole number of students.

9- A
The model for the fraction is divided into $$100$$ equal parts. We shade $$92$$ parts of these $$100$$ parts that it’s equal to $$\frac{92}{100}$$

10- D
$$90 × 25 =2,250$$