Using Distributive Property to Factor Variable Expressions
The distributive property works in two directions: you can use it to expand a product into a sum, or you can run it in reverse to factor a sum back into a product. Factoring with the distributive property means identifying the greatest common factor (GCF) of all terms and pulling it outside parentheses. This skill is tested directly on the GED Math exam and is the foundation of all algebra simplification.
What Is the Distributive Property?
The distributive property states: \(\color{blue}{a(b + c) = \text{ ab } + \text{ ac }}\).
Running it in reverse: \(\color{blue}{\text{ ab } + \text{ ac } = a(b + c)}\) — this is factoring. You identify the common factor \(\color{blue}{a}\) and pull it out, leaving the remaining terms inside parentheses.
How to Factor Using the Distributive Property
Step 1: Identify the GCF of all terms
Look at the coefficients and variables of every term. The GCF is the largest value that divides evenly into all of them.
- \(\color{blue}{12x + 8}\): GCF of 12 and 8 is \(\color{blue}{4}\).
- \(\color{blue}{15y – 10}\): GCF of 15 and 10 is \(\color{blue}{5}\).
- \(\color{blue}{6x^{2} + 9x}\): GCF is \(\color{blue}{3x}\) (common coefficient factor 3, common variable factor x).
Step 2: Divide each term by the GCF
These quotients become the terms inside the parentheses.
Step 3: Write the factored form
\(\color{blue}{\text{ GCF }(\frac{\text{ term }1}{\text{ GCF }} + \frac{\text{ term }2}{\text{ GCF }} + \ldots )}\)
Step 4: Verify by expanding
Distribute the GCF back through the parentheses and check you recover the original expression.
Step-by-Step Summary
- List the terms of the expression.
- Find the GCF of all coefficients and the lowest power of any shared variables.
- Divide each term by the GCF.
- Write: \(\color{blue}{\text{ GCF }(&\text{ bull }; + &\text{ bull }; \pm &\text{ bull };)}\).
- Expand to verify correctness.
Watch: The Distributive Property Step-by-Step (Math with Mr. J)
Math with Mr. J explains both expanding and factoring using the distributive property:
Worked Examples
Example 1: Factor \(\color{blue}{12x + 8}\).
\(\color{blue}{\text{ GCF }(12, 8) = 4}\). Divide: \(\color{blue}{12x \div 4 = 3x}\), \(\color{blue}{8 \div 4 = 2}\).
Factored: \(\color{blue}{4(3x + 2)}\). Check: \(\color{blue}{4 \times 3x + 4 \times 2 = 12x + 8}\) ✓
Example 2: Factor \(\color{blue}{15y – 10}\).
\(\color{blue}{\text{ GCF }(15, 10) = 5}\). Divide: \(\color{blue}{15y \div 5 = 3y}\), \(\color{blue}{10 \div 5 = 2}\).
Factored: \(\color{blue}{5(3y – 2)}\). Check: \(\color{blue}{5 \times 3y – 5 \times 2 = 15y – 10}\) ✓
Example 3: Factor \(\color{blue}{6x^{2} + 9x}\).
\(\color{blue}{\text{ GCF } = 3x}\). Divide: \(\color{blue}{6x^{2} \div 3x = 2x}\), \(\color{blue}{9x \div 3x = 3}\).
Factored: \(\color{blue}{3x(2x + 3)}\). Check: \(\color{blue}{3x \times 2x + 3x \times 3 = 6x^{2} + 9x}\) ✓
Example 4: Factor \(\color{blue}{20n – 12n^{2}}\).
\(\color{blue}{\text{ GCF } = 4n}\). Divide: \(\color{blue}{20n \div 4n = 5}\), \(\color{blue}{12n^{2} \div 4n = 3n}\).
Factored: \(\color{blue}{4n(5 – 3n)}\). Check: \(\color{blue}{4n \times 5 – 4n \times 3n = 20n – 12n^{2}}\) ✓
More Practice: Factoring Algebraic Expressions (Khan Academy)
Khan Academy provides additional factoring examples with a focus on identifying the GCF:
Exercises
Factor each expression by pulling out the GCF.
- \(\color{blue}{6a + 10}\)
- \(\color{blue}{8b – 20}\)
- \(\color{blue}{9x + 12}\)
- \(\color{blue}{4y^{2} + 6y}\)
- \(\color{blue}{18m – 24}\)
- \(\color{blue}{10p^{2} + 15p}\)
Answers
- \(\color{blue}{2(3a + 5)}\)
- \(\color{blue}{4(2b – 5)}\)
- \(\color{blue}{3(3x + 4)}\)
- \(\color{blue}{2y(2y + 3)}\)
- \(\color{blue}{6(3m – 4)}\)
- \(\color{blue}{5p(2p + 3)}\)
Frequently Asked Questions
What is factoring with the distributive property?
It is the reverse of expanding. Instead of multiplying a factor into a parenthesis, you identify the common factor in each term and pull it outside. The result is a product of the GCF and the remaining terms in parentheses.
What if no common factor exists?
If the GCF is 1, the expression is already fully factored (it is said to be “prime” with respect to common factor factoring). You cannot pull out anything meaningful.
Can variables be part of the GCF?
Yes. If every term contains a variable, that variable (at its lowest power appearing in any term) is part of the GCF. For example, in \(\color{blue}{4x^{3} + 6x^{2}}\), the GCF is \(\color{blue}{2x^{2}}\), giving \(\color{blue}{2x^{2}(2x + 3)}\).
Related Topics
Related to This Article
More math articles
- Supermarket Sweep: How to Choose the Better Coupon in Aisle 7!
- Hawaii Algebra 1 Free Worksheets: Printable Algebra 1 Practice Worksheets with Worked Solutions
- Top 10 SSAT Lower Level Math Practice Questions
- Free Grade 8 English Worksheets for Wyoming Students
- How to Solve Zero and Negative Exponents? (+FREE Worksheet!)
- Full-Length SSAT Lower Level Math Practice Test
- A Guide to the Different Types of Continuity in Functions
- The Ultimate 6th Grade MCAP Math Course (+FREE Worksheets)
- Overview of the HSPT Mathematics Test
- Free Grade 6 English Worksheets for Montana Students






































What people say about "Using Distributive Property to Factor Variable Expressions - Effortless Math: We Help Students Learn to LOVE Mathematics"?
No one replied yet.