Top 10 ALEKS Math Practice Questions

Top 10 ALEKS Math Practice Questions

Preparing for the ALEKS Math test? The best way to prepare for your ALEKS Math test is to work through as many ALEKS Math practice questions as possible. Here are the top 10 ALEKS Math practice questions to help you review the most important ALEKS Math concepts. These ALEKS Math practice questions are prepared by test prep experts to cover mathematics concepts and topics that are found on the actual test. The questions have been fully updated to reflect the latest 2022 ALEKS guidelines. Answers and full explanations are provided at the end of the post.

Start your ALEKS Math test prep journey right now with these sample ALEKS Math questions.

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ALEKS Math Practice Questions

1- \((x + 7) (x + 5) =\) __________


2- If \(x\) is a positive integer divisible by \(6\), and \(x < 60\), what is the greatest possible value of \(x\)? __________


3- \( x^2 – 81 = 0 \) , What is (are) the positive value of \(x\)? __________


4-If \(a = 8\), what is the value of \(b\) in this equation?
\(b = \frac {a^2}{4 }+ 4\) ____________


5- The ratio of boys to girls in a school is \(2:3\). If there are \(600\) students in a school, how many boys are in the school? __________


6- What is the area of an isosceles right triangle that has one leg that measures \(6 cm\)? __________


7- Simplify:\( 10 \ – \frac{2}{3} x ≥ 12 \) __________


8- What is a common factor of both \(x^2 – 2x – 8 \) and \( x^2 – 6x + 8? \)_________


9- \( \frac{1}{6b^2} + \frac{1}{6b} = \frac{1}{b^2} \), then \(b =\) ? __________


10- If two angles in a triangle measure \(53\) degrees and \(45\) degrees, what is the value of the third angle? __________


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Answers:

1- \(x^2+12x+35\)
Use FOIL (First, Out, In, Last) \((x + 7) (x + 5) = x^2 + 5x + 7x + 35 = x^2 + 12x + 35\)

2- 54
\( \frac{54}{6}=\frac{27}{6}=9\)
\(\frac{48}{6}=\frac{24}{3}=8\)
\(\frac{36}{6}=\frac{18}{3}=6\)
\(\frac{59}{6}=\frac{59}{6}\)
\(59\) is prime number

3- 9
\( x^2 – 81 = 0 ⇒ x^2 = 81 ⇒ x = 9\)

4- 20
If \(a = 8\) then \(b = \frac {8^2}{4}+ 4 ⇒ b = \frac {64}{4} + 4 ⇒b = 16 + 4 = 20\)

5- 240
The ratio of boys to girls is \(2:3\). Therefore, there are \(2\) boys out of \(5\) students. To find the answer, first, divide the total number of students by \(5\), then multiply the result by \(2\).
\(600 ÷ 5 = 120 ⇒ 120 × 2 = 240\)

6- 18
\(a=6\)⇒ area of triangle is \( =\frac{1}{2} (6×6)=\frac{36}{2}=18\) \(cm\)

7- \(x\leq-3\)
Simplify. \( 10 – \frac{2}{3} x ≥ 12 ⇒ –\frac{2}{3} x ≥ 2 ⇒ – x ≥ 3 ⇒ x ≤ – 3\)

8- \(x-4\)
Factor each trinomial \( x^2 – 2x – 8 \) and \( x^2 – 6x + 8 \)
\(x^2 – 2x – 8 ⇒ (x – 4)(x + 2) \)
\(x^2 – 6x + 8 ⇒ (x – 2)(x – 4)\) The common Factor is: \((x – 4)\)

9- 5
\( \frac{1+b}{6b^2}=\frac{1}{b^2} ⇒(b≠0)\)
\(b^2+b^3=6b^2⇒b^3-5b^2=0⇒b^2 (b-5)=0⇒b-5=0⇒b=5 \)

10- \(82^\circ\)
\(53^\circ + 45^\circ = 98^\circ\)
\(180^\circ – 98^\circ = 82^\circ\)
The value of the third angle is \(82^\circ\).

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