# Full-Length GED Math Practice Test-Answers and Explanations

Did you take the GED Math Practice Test? If so, then it’s time to review your results to see where you went wrong and what areas you need to improve.

## GED Mathematical Reasoning Practice Test Answers and Explanations

1- **Choice A is correct**

Plug in the value of \(x\) and \(y\): \(2x(y-2x)+(2y-x)^2\) when \(x=-1\) and \(y=2⇒2(-1)(2-2(-1))+(2(2)-(-1))^2=-8+25=17\)

2- **Choice C is correct**

The equation of a line in slope intercept form is: \(y=mx+b\). Solve for \(y\).

\(-4x-y=8⇒y=-8-4x\). The slope of line is \(-4\). Therefore, the slope of a line that is perpendicular to this line is \(m^{‘}=-\frac{1}{m}=\frac{1}{4}\)

3- **Choice B is correct**

To solve absolute values equations, write two equations.

\( 2x-6\) can equal positive 12, or negative 12. Therefore, \(\begin{cases}-2x-4=-8 \\ -2x-4=8 \end{cases}\).

\(\begin{cases}-2x=-4 \\ -2x=12 \end{cases} ⇒?=\frac{−8}{−4}=2, ?=\frac{12}{−2}=−6\)

Find the product of solutions: \(2×(-6)=-12\)

4-** Choice C is correct**

A. \((2, -8) ⇒ 2(2)-3(-8)=28≠13 \)

B. \((-2, -3) ⇒2(-2)-3(-3)=5≠13 \)

C. \((2, -3) ⇒2(2)-3(-3)=13=13 \)

D. \((2,3) ⇒2(2)-3(3)=-5≠13\)

5- **Answer is -27**

Use PEMDAS (order of operation):\( -2×|-4|+3×(-2)-[10-6×(-7)]÷4=-8-6-13=-27\)

6- **Choice D is correct**

Use simple interest formula: I=prt

I = interest, p = principal, r = rate, t = time.

I=\((25000)(0.029)(3)=2175\)

7- **Choice A is correct**

Let x be all expenses, then \(\frac{23}{100} x=$575 →x=\frac{100×$575}{23}=$2500\)

He spent for his rent: \(\frac{34}{100}×$2500=$850\)

8- **Choice B is correct**

Write the numbers in order:\(4,12,15,19,21,25,34\). Median is the number in the middle. So, the median is 19. The range is \(34-4=30\)

9- **Choice D is correct **

To get a sum of 8 for two dice, we can get 5 different options: \((6, 2), (5, 3), (4, 4), (3, 5), (2, 6)\) To get a sum of 10 for two dice, we can get 3 different options: \((6, 4), (5, 5), (4, 6)\) Therefore, there are 8 options to get the sum of 8 or 10. Since, we have \(6 × 6 = 36\) total options, the probability of getting a sum of 5 and 3 is 8 out of 36 or \(\frac{8}{36}=\frac{2}{9}\).

10- **Answer is 118**

The area of the square is 870.25. Therefore, the side of the square is the square root of the area. \(\sqrt{870.25}=29.5\)

Four times the size of the square is the perimeter: \(4 × 29.5 = 118\)

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11- **Choice A is correct**

The perimeter of the trapezoid is 42 cm.

Therefore, the missing side (height) is \(= 45 – 15 – 9 – 5 = 13\).

Area of a trapezoid: \(A = \frac{1}{2} h (b_1 + b_2) = \frac{1}{2} (13) (5 + 9) = 91\)

12- **Answer is 4 **

Use formula of rectangle prism volume.

V = (length) (width) (height) \(⇒ 924 = (21) (11)\) (height) ⇒ height \(= 924 ÷ 231 = 4\)

13- **Choice D is correct**

Change the numbers to decimal and then compare.

\(38\%=0.38 , 0.52=0.52, \frac{1}{10}=0.1, \frac{2}{5}=0.4\) Therefore \(\frac{1}{10}<38\%<\frac{2}{5}<0.52\).

14- **Choice A is correct**

Use the formula of areas of circles.

Area \(= πr^2 ⇒ 36 π> πr^2⇒ 36 > r^2⇒ r < 6\)

The radius of the circle is less than 6. Let’s put 6 for the radius. Now, use the circumference formula: Circumference \(=2πr=2π (6)=12 π\)

Since the radius of the circle is less than 6. Then, the circumference of the circle must be less than \(12π\).

15- **Choice D is correct**

Volume of a box \(=\) length \(×\) width \(×\) height \(= 6 × 5.5 × 9 = 297\)

16- **Choice C and D is correct**

(If you selected 3 choices and 2 of them are correct, then you get one point. If you answered 2 or 3 choices and one of them is correct, you receive one point. If you selected more than 3 choices, you won’t get any point for this question.) First, find the sum of five numbers.

average \(= \frac{sum of terms }{number of terms} ⇒ 32 = \frac{sum of 5 numbers}{5} ⇒ \)sum of 5 numbers \(= 32 × 5 = 160 \)

The sum of 5 numbers is 160. If a sixth number that is greater than 50 is added to these numbers, then the sum of 6 numbers must be greater than 210.

\(160 + 50 = 210 \)

If the number was 50, then the average of the numbers is:

average \(=\frac{sum of terms }{number of terms}=\frac{210}{6}=35\)

Since the number is bigger than 50. Then, the average of six numbers must be greater than 35. Choices C and D are greater than 35.

17- **Choice C is correct**

If the length of the box is 45, then the width of the box is one-fifth of it, 9, and the height of the box is 4.5 (one second of the width). The volume of the box is: \(V \(=\) lwh \(= (45) (9) (4.5) = 1822.5\)

18- **Choice B is correct**

Write the equation and solve for \(B: 0.50 A = 0.80 B\), divide both sides by 0.80, then: \(\frac{0.50}{0.80} A = B\), therefore: \(B = 0.625 A\), and \(B\) is 0.625 times of \(A\) or it’s \(62.5\%\) of \(A\).

19- **Choice B is correct **

Plugin 95 for F and then solve for C.

C \(= \frac{5}{9} (F – 32) ⇒\) C \(= \frac{5}{9} (95 – 32) ⇒\) C \(= \frac{5}{9} (63) = 35\)

20- **Choice A is correct**

Use simple interest formula: =prt (I = interest,p = principal,r = rate,t = time).

I=\((75,00)(0.0325)(6)=1462.5\)

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21- **Answer is 144**

\(\frac{6^4}{3^2} =\frac{6×6×6×6}{3×3}=144\)

22- **Choice B is correct**

Use percent formula: part\(=\frac{percent}{100}×\)whole

\(57=\frac{percent}{100}×95 ⇒ 57=\frac{percent ×95}{100} ⇒\) multiply both sides by 100.

\(5700=\)percent\(×95\), divide both sides by 95. \(60=\)percent

23- **Choice D is correct**

Area of a trapezoid: \(A = \frac{1}{2} h (b_1 + b_2)\). Therefore, the missing side is height(h). First, we should find \(x,h\)

\(x=\frac{32-20}{2}=4\). And \(10^2=x^2+h^2⇒h=\sqrt{10^2-x^2}\)

\(h=\sqrt{10^2-4^2}=\sqrt{64}=8\).

\(A=\frac{1}{2} h(b_1+b_2 )=\frac{1}{2}×8×(20+32)=208\)

24- **Choice A is correct**

Solving Systems of Equations by Elimination Add two equations.

\(\begin{cases}4x+2y=-9 \\ -2x-2y=-7 \end{cases} ⇒ 2x=-16 ⇒ x=-8 \)

Plug in the value of x into one of the equations and solve for \(y\).

\(4x+2y=-9⇒4(-8)+2y=-9⇒-32+2y=-9⇒2y=23⇒y=\frac{23}{2}\)

25- **Choice B is correct**

The equation of a line is in the form of \(y=mx+b\), where m is the slope of the line and b is the y-intercept of the line.

Two points \((1,0)\) and \((0,1)\) are on line A. Therefore, the slope of the line A is:

slope of line A\(=\frac{y_2- y_1}{x_2 – x_1} = \frac{1-0}{0-1}=\frac{1}{-1}=-1 \)

The slope of line A is \(-1\). Thus, the formula of the line A is: \(y=mx+b=-x+b\), choose a point and plug in the values of \(x\) and \(y\) in the equation to solve for b. Let’s choose point \((0, 1)\). Then:

\(y=x+b→1=0+b→b=1\)

The equation of line A is: \(y=-x+1\)

Now, let’s review the choices provided:

A.\((1,2) ⇒2=-1+1\). This is not true

B. \((-1,2)⇒2=1+1=2\). This is true

C. \((2,1)⇒1=-2+1=-1\). This is not true

D. \((3,1)⇒1=-3+1=-2\). This is not true

26- **Choice A is correct**

Use distance formula: Distance \(=\) Rate \(×\) time \(⇒ 540 = 75 ×\) T, divide both sides by \(\frac{75. 540 }{75} =\) T ⇒ T \(= 7.2\) hours.

Change hours to minutes for the decimal part. 0.2 hours \(= 0.2 × 60 = 12\) minutes

27- **Choice D is correct**

Let \(x\) be the number. Write the equation and solve for \(x\).

\(\frac{3}{5} ×22= \frac{3}{7}. x ⇒ \frac{3×22}{5}= \frac{3x}{7} \), use cross multiplication to solve for \(x\).

\(7×22=5x ⇒154=5x ⇒ x=30.8\)

28- **Choice B is correct**

To find the discount, multiply the number by (\(100\% –\) rate of discount).

Therefore, for the first discount we get: \((D) (100\% – 15\%) = (D) (0.85) = 0.85 D\)

For increase of \(10 \%: (0.85 D) (100\% + 10\%) = (0.85 D) (1.10) = 0.935 D = 93.5\%\) of \(D\)

29- **Choice C is correct**

Use the formula for Percent of Change: \(\frac{New Value-Old Value}{Old Value} × 100 \% \)

\(\frac{34-45}{45} × 100 \% = –24.44 \%\) (negative sign here means that the new price is less than old price).

30- **Choices D and E are correct**

(If you selected 3 choices and 2 of them are correct, then you get one point. If you answered 2 or 3 choices and one of them is correct, you receive one point. If you selected more than 3 choices, you won’t get any point for this question.) Some of the prime numbers are: \(2, 3, 5, 7, 11, 13\)

Find the product of two consecutive prime numbers:

\(2 × 3 = 6\) (not in the options)

\(3 × 5 = 15\) (Choice D)

\(5 × 7 = 35\) (Choice E)

\(7 × 11 = 77\) (not in the options)

Choices D and E are correct.

31- **Answer is 249**

The ratio of boys to girls is \(3:5\). Therefore, there are 3 boys out of 8 students. To find the answer, first, divide the total number of students by 8, then multiply the result by

\(3. 664 ÷ 8 = 83 ⇒ 83 × 3 = 249\)

32- **Choice A is correct**

The question is this: 440 is what percent of 550?

Use percent formula: part \(= \frac{percent}{100} ×\) whole

\(440 = \frac{percent}{100} × 550 ⇒ 440= \frac{percent ×550}{100} ⇒44000 =\) percent \(×550\) percent \(= \frac{44000}{550} = 80. 440\) is \(80 \%\) of 550. Therefore, the discount is: \(100\% – 80\% = 20\%\)

33- **Choice B is correct**

If the score of Mia was 48, therefore the score of Ava is 16. Since the score of Emma was half as that of Ava, therefore, the score of Emma is 8.

34- **Choice A is correct**

The sample space S of the experiment described is as follows:

\(S={(1,H),(2,H),(3,H),(4,H),(5,H),(6,H),(1,T),(2,T),(3,T),(4,T),(5,T),(6,T)} \)

Let E be the event “the die shows an odd number and the coin shows ahead”. Event E may be described as follows.

\(E={(1, H),(3,H),(5,H)}\)

The probability P(E) is given by P(E) \(= \frac{n(E)}{n(S)} = \frac{3 }{12} = \frac{1}{4}\)

35- Choice A is correct

Let \(x\) be the smallest number. Then, these are the numbers:

\(x, x+1, x+2, x+3, x+4\)

average \(= \frac{sum of terms}{number of terms} ⇒ = \frac{x+(x+1)+(x+2)+(x+3)+(x+4)}{5}⇒30=\frac{5x+10}{5} ⇒ 150=5x+10 ⇒ 140=5x ⇒ x=28\)

36- **Choice D is correct**

The area of the floor is: \(8\) cm \(× 20\) cm \(= 160\) cm\(^2\) The number of tiles needed \(= 160 ÷ 10 = 16\)

37- **Choice B is correct **

The weight of 9.6 meters of this rope is: \(9.6 × 500\)g \(= 4800\) g \(1\) kg \(= 1,000\) g, therefore, \(4800\) g \(÷ 1000 = 4.8\)kg

38- **Choice B is correct**

\(2.5\%\) of the volume of the solution is alcohol. Let \(x\) be the volume of the solution. Then:

\(2.5\%\) of \(x = 30\) ml \(⇒ 0.025 x = 30 ⇒ x = 30 ÷ 0.025 = 1200\) ml

39- **Choice C is correct **

average \(= \frac{sum of terms}{number of terms}\)

The sum of the weight of all girls is: \(15 × 62 = 930\) kg

The sum of the weight of all boys is: \(28 × 70 = 1960\) kg

The sum of the weight of all students is: \(930 + 1960 = 2890\) kg

average \(= \frac{2890}{43} = 67.21\)

40- **Choice C is correct**

Let \(x\) be the original price. If the price of a laptop is decreased by \(12\%\) to \($385\), then:

\(88 \%\) of \(x=385⇒ 0.88x=385 ⇒ x=385÷0.88=$437.5\)

41-** Choice A is correct**

Write the numbers in order: \(14,14,15,16,18,22,62\) Since we have 7 numbers (7 is odd), then the median is the number in the middle, which is 16.

42- **Choice A is correct**

Surface area of cone formula is : A\(=πr(r+\sqrt{h^2+r^2})\). For r\(=17\) and h\(=20\) A\(=π(17)(17+\sqrt{20^2+17^2} )≈2309.79\)

43- **Choice D is correct **

Let \(x\) be the number of years. Therefore, \($2,100\) per year equals \(2100x\).

starting from \($22,000\) annual salary means you should add that amount to \(2100x\).

Income more than that is: \(I > 2100x + 22000\)

44- **Choice B is correct**

The question is this: 1.65 is what percent of 1.05?

Use percent formula: part \(= \frac{percent}{100} ×\) whole

\(1.65 = \frac{percent}{100} × 1.05 ⇒ 1.65=\frac{percent ×1.05}{100} ⇒165=\)percent \(×1.05 ⇒\) percent\(=\frac{165}{1.05}=157\%\)

45- **Choice D is correct**

Use the information provided in the question to draw the shape.

Use Pythagorean Theorem: \(a^2 + b^2 = c^2\)

\(20^2 + 15^2 = c^2 ⇒ 400 + 225 = c^2 ⇒ 625 = c^2 ⇒ c = 25\)

46- **Choice A is correct**

For each option, choose a point in the solution part and check it on both inequalities.

\(y>2x ,y≥-x+2\)

A. Point \((0, 5)\) is in the solution section. Let’s check the point in both inequalities.

\(5>0\), It works

\(5≥0+2\), it works (this point works in both)

B. Let’s choose this point \((5, 0)\)

\(0>10\) That’s not true!

\(0≥-5+2\), it works

C. Let’s choose this point

\((–5, 0) 0>-10\), it works

\(0≥10+2\) That’s not true!

D. Let’s choose this point

\((0, 5) 5>0\), That’s not true!

\(5≥0+2\) it works

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