How to Solve a Quadratic Equation? (+FREE Worksheet!)
How to Solve a Quadratic Equation
Solving a quadratic equation \(ax^2 + bx + c = 0\) means finding the x-values that make it true. Its roots. You can factor, use the square root for simple cases, or fall back on the quadratic formula when nothing factors. We’ll cover each path, with a solver and a worksheet maker a tap away.
Solve a Quadratic Equation: what to notice and how to work it
What to notice first
Common student mistake
Key formulas and cues
A reliable path
- Read the formFactored, standard, and vertex forms reveal different features.
- Choose the methodFactor when friendly, complete the square for structure, or use the formula when needed.
- Connect to the graphRoots are x-intercepts and the vertex is the minimum or maximum point.
Worked examples
Factor and solve
- Factor into (x – 3)(x – 4).
- Set each factor equal to zero.
- Solve both small equations.
Find the axis
- Use x = -b/(2a).
- Here a = 2 and b = -8.
- Compute 8/4.
Try one before moving on
Solve a Quadratic Equation: pop-up practice

Solving a quadratic equation, \(ax^2 + bx + c = 0\), means finding the x-values that make it true, called its roots or solutions. A quadratic can have two solutions, one, or none (real), and there are three reliable tools to find them: factoring, the square-root method, and the quadratic formula. The trick is choosing the right tool for the equation in front of you.
In short: set the equation to \(0\), then factor (if it factors), take square roots (if there’s no middle term), or use the quadratic formula \(x = \dfrac{-b \pm \sqrt{b^2 – 4ac}}{2a}\) (always works). For \(x^2 – 5x + 6 = 0\), the roots are \(2\) and \(3\).
Three Ways to Find the Roots
Every method finds the same answers; they just suit different equations.
Worked Examples
The roots are exactly where each parabola crosses the x-axis, shown on every graph below.
Example A, Factoring
Solve \(x^2 – 5x + 6 = 0\).
- Find two numbers that multiply to 6 and add to \(-5\): \(-2\) and \(-3\).
- Factor: \((x – 2)(x – 3) = 0\).
- Set each factor to zero: \(x = 2\) or \(x = 3\).
Answer: \(x = 2\) or \(3\)
Example B, Square-root method
Solve \(x^2 – 9 = 0\).
- No middle term, add 9: \(x^2 = 9\).
- Take the square root of both sides, keeping \(\pm\).
- \(x = \pm 3\).
Answer: \(x = \pm 3\)
Example C, Leading coefficient
Solve \(2x^2 – 7x + 3 = 0\).
- Factor: \((2x – 1)(x – 3) = 0\).
- Set each factor to zero: \(2x – 1 = 0\) or \(x – 3 = 0\).
- Solve: \(x = \tfrac12\) or \(x = 3\).
Answer: \(x = \tfrac12\) or \(3\)
Example D, One repeated root
Solve \(x^2 – 4x + 4 = 0\).
- Recognize the perfect square: \((x – 2)^2 = 0\).
- Both factors are \(x – 2\), so they give the same value.
- One double root: \(x = 2\), the vertex sits right on the x-axis.
Answer: \(x = 2\)
Where You’ll Use It
Quadratic equations answer “when does it hit zero?”, when a thrown ball lands, when a profit becomes zero (break-even), when an area reaches a target. Setting a quadratic model equal to a value and solving is one of the most common tasks in algebra, physics, and engineering.
Slip-Ups That Cost Easy Points
- Not setting it to zero first. Factoring and the formula need \(ax^2 + bx + c = 0\); move everything to one side.
- Forgetting the \(\pm\). A square root gives two answers: \(x^2 = 9\) means \(x = 3\) and \(-3\).
- Sign errors in the formula. Watch \(-b\) and the \(-4ac\); a single sign flip changes everything.
- Reporting only one root. Most quadratics have two solutions, give both unless it’s a perfect square.
Your Turn: Solve
Find all roots, then reveal the answers.
- \(x^2 – 7x + 10 = 0\)
- \(x^2 – 16 = 0\)
- \(x^2 + 5x + 6 = 0\)
- \(x^2 – 4x + 4 = 0\)
- \(3x^2 – 5x – 2 = 0\)
- \(x^2 – 2x – 15 = 0\)
Show answers
- \(\color{blue}{x = 2, 5}\)
- \(\color{blue}{x = \pm 4}\)
- \(\color{blue}{x = -2, -3}\)
- \(\color{blue}{x = 2}\)
- \(\color{blue}{x = -\tfrac13, 2}\)
- \(\color{blue}{x = -3, 5}\)
Make Your Own Quadratics Worksheet
Generate fresh solve-the-quadratic problems with a full answer key, print or save as a PDF.
Frequently Asked Questions
What are the ways to solve a quadratic equation?
Factoring (fastest when it factors), the square-root method (for equations with no middle term), and the quadratic formula (which always works). All give the same roots.
How many solutions does a quadratic have?
Up to two real solutions. A perfect square gives one (a repeated root), and some quadratics have no real solutions, the discriminant tells you which.
When should I use the quadratic formula?
When the quadratic doesn’t factor with simple integers, or you want a method that always works. Just plug \(a\), \(b\), and \(c\) into \(x = \tfrac{-b \pm \sqrt{b^2 – 4ac}}{2a}\).
Why must I set the equation to zero first?
Factoring relies on the zero-product property (if a product is 0, a factor is 0), and the formula is defined for \(ax^2 + bx + c = 0\). Both need a zero on one side.
Related Topics
Continue Your Study
Ready for the next step? Pick up right where this lesson leaves off:
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