How to Solve a Quadratic Equation? (+FREE Worksheet!)
How to Solve a Quadratic Equation
Solving a quadratic equation \(ax^2 + bx + c = 0\) means finding the x-values that make it true — its roots. You can factor, use the square root for simple cases, or fall back on the quadratic formula when nothing factors. We’ll cover each path, with a solver and a worksheet maker a tap away.
Solve a Quadratic Equation: what to notice and how to work it
What to notice first
Common student mistake
Key formulas and cues
A reliable path
- Read the formFactored, standard, and vertex forms reveal different features.
- Choose the methodFactor when friendly, complete the square for structure, or use the formula when needed.
- Connect to the graphRoots are x-intercepts and the vertex is the minimum or maximum point.
Worked examples
Factor and solve
- Factor into (x – 3)(x – 4).
- Set each factor equal to zero.
- Solve both small equations.
Find the axis
- Use x = -b/(2a).
- Here a = 2 and b = -8.
- Compute 8/4.
Try one before moving on
Solve a Quadratic Equation: pop-up practice

Solving a quadratic equation — \(ax^2 + bx + c = 0\) — means finding the x-values that make it true, called its roots or solutions. A quadratic can have two solutions, one, or none (real), and there are three reliable tools to find them: factoring, the square-root method, and the quadratic formula. The trick is choosing the right tool for the equation in front of you.
In short: set the equation to \(0\), then factor (if it factors), take square roots (if there’s no middle term), or use the quadratic formula \(x = \dfrac{-b \pm \sqrt{b^2 – 4ac}}{2a}\) (always works). For \(x^2 – 5x + 6 = 0\), the roots are \(2\) and \(3\).
Three Ways to Find the Roots
Every method finds the same answers; they just suit different equations.
Worked Examples
The roots are exactly where each parabola crosses the x-axis — shown on every graph below.
Example A — Factoring
Solve \(x^2 – 5x + 6 = 0\).
- Find two numbers that multiply to 6 and add to \(-5\): \(-2\) and \(-3\).
- Factor: \((x – 2)(x – 3) = 0\).
- Set each factor to zero: \(x = 2\) or \(x = 3\).
Answer: \(x = 2\) or \(3\)
Example B — Square-root method
Solve \(x^2 – 9 = 0\).
- No middle term — add 9: \(x^2 = 9\).
- Take the square root of both sides, keeping \(\pm\).
- \(x = \pm 3\).
Answer: \(x = \pm 3\)
Example C — Leading coefficient
Solve \(2x^2 – 7x + 3 = 0\).
- Factor: \((2x – 1)(x – 3) = 0\).
- Set each factor to zero: \(2x – 1 = 0\) or \(x – 3 = 0\).
- Solve: \(x = \tfrac12\) or \(x = 3\).
Answer: \(x = \tfrac12\) or \(3\)
Example D — One repeated root
Solve \(x^2 – 4x + 4 = 0\).
- Recognize the perfect square: \((x – 2)^2 = 0\).
- Both factors are \(x – 2\), so they give the same value.
- One double root: \(x = 2\) — the vertex sits right on the x-axis.
Answer: \(x = 2\)
Where You’ll Use It
Quadratic equations answer “when does it hit zero?” — when a thrown ball lands, when a profit becomes zero (break-even), when an area reaches a target. Setting a quadratic model equal to a value and solving is one of the most common tasks in algebra, physics, and engineering.
Slip-Ups That Cost Easy Points
- Not setting it to zero first. Factoring and the formula need \(ax^2 + bx + c = 0\); move everything to one side.
- Forgetting the \(\pm\). A square root gives two answers: \(x^2 = 9\) means \(x = 3\) and \(-3\).
- Sign errors in the formula. Watch \(-b\) and the \(-4ac\); a single sign flip changes everything.
- Reporting only one root. Most quadratics have two solutions — give both unless it’s a perfect square.
Your Turn: Solve
Find all roots, then reveal the answers.
- \(x^2 – 7x + 10 = 0\)
- \(x^2 – 16 = 0\)
- \(x^2 + 5x + 6 = 0\)
- \(x^2 – 4x + 4 = 0\)
- \(3x^2 – 5x – 2 = 0\)
- \(x^2 – 2x – 15 = 0\)
Show answers
- \(\color{blue}{x = 2, 5}\)
- \(\color{blue}{x = \pm 4}\)
- \(\color{blue}{x = -2, -3}\)
- \(\color{blue}{x = 2}\)
- \(\color{blue}{x = -\tfrac13, 2}\)
- \(\color{blue}{x = -3, 5}\)
Make Your Own Quadratics Worksheet
Generate fresh solve-the-quadratic problems with a full answer key — print or save as a PDF.
Frequently Asked Questions
What are the ways to solve a quadratic equation?
Factoring (fastest when it factors), the square-root method (for equations with no middle term), and the quadratic formula (which always works). All give the same roots.
How many solutions does a quadratic have?
Up to two real solutions. A perfect square gives one (a repeated root), and some quadratics have no real solutions — the discriminant tells you which.
When should I use the quadratic formula?
When the quadratic doesn’t factor with simple integers, or you want a method that always works. Just plug \(a\), \(b\), and \(c\) into \(x = \tfrac{-b \pm \sqrt{b^2 – 4ac}}{2a}\).
Why must I set the equation to zero first?
Factoring relies on the zero-product property (if a product is 0, a factor is 0), and the formula is defined for \(ax^2 + bx + c = 0\). Both need a zero on one side.
Related Topics
Continue Your Study
Ready for the next step? Pick up right where this lesson leaves off:
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