How to Solve a Quadratic Equation? (+FREE Worksheet!)

How to Solve a Quadratic Equation? (+FREE Worksheet!)
Algebra 1

How to Solve a Quadratic Equation

Solving a quadratic equation \(ax^2 + bx + c = 0\) means finding the x-values that make it true — its roots. You can factor, use the square root for simple cases, or fall back on the quadratic formula when nothing factors. We’ll cover each path, with a solver and a worksheet maker a tap away.

Tutor-style math help

Solve a Quadratic Equation: what to notice and how to work it

Quadratics skill
Quadratic topics connect an equation, a parabola, roots, and a turning point. Read the form first because each form reveals a different feature.

What to notice first

Standard form helps with formulas, factored form shows roots, and vertex form shows the turning point. A good solution starts by using the form you have.

Common student mistake

Do not assume every quadratic has two real x-intercepts. The discriminant tells whether the real graph crosses the x-axis twice, once, or not at all.

Key formulas and cues

\(ax^2+bx+c=0\)
\(x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)
\(x=-\frac{b}{2a}\)
\(y=a(x-h)^2+k\)
vertex axis

A reliable path

  1. Read the formFactored, standard, and vertex forms reveal different features.
  2. Choose the methodFactor when friendly, complete the square for structure, or use the formula when needed.
  3. Connect to the graphRoots are x-intercepts and the vertex is the minimum or maximum point.

Worked examples

Factor and solve

Example: \(x^2-7x+12=0\)
  1. Factor into (x – 3)(x – 4).
  2. Set each factor equal to zero.
  3. Solve both small equations.
Answer: \(x=3\) or \(x=4\)

Find the axis

Example: \(y=2x^2-8x+5\)
  1. Use x = -b/(2a).
  2. Here a = 2 and b = -8.
  3. Compute 8/4.
Answer: \(x=2\)
Try one before moving on
Try: Find the axis of symmetry of \(y=x^2-6x+2\).
Answer: \(x=3\).
Next step: do the matching worksheet or quiz while the method is still fresh, then come back and explain the first step in your own words.
Illustration of students learning How to Solve a Quadratic Equation

Solving a quadratic equation — \(ax^2 + bx + c = 0\) — means finding the x-values that make it true, called its roots or solutions. A quadratic can have two solutions, one, or none (real), and there are three reliable tools to find them: factoring, the square-root method, and the quadratic formula. The trick is choosing the right tool for the equation in front of you.

In short: set the equation to \(0\), then factor (if it factors), take square roots (if there’s no middle term), or use the quadratic formula \(x = \dfrac{-b \pm \sqrt{b^2 – 4ac}}{2a}\) (always works). For \(x^2 – 5x + 6 = 0\), the roots are \(2\) and \(3\).

The big idea

Three Ways to Find the Roots

Every method finds the same answers; they just suit different equations.

FactoringFast when it factors into nice integers.
Square rootBest when there’s no \(x\) term (like \(x^2 = 9\)).
Quadratic formulaAlways works, even when nothing factors.
Tutor tip: Try factoring first — it’s quickest. If two numbers won’t multiply to \(c\) and add to \(b\), reach for the quadratic formula instead of forcing it.

Worked Examples

The roots are exactly where each parabola crosses the x-axis — shown on every graph below.

Example A — Factoring

Solve \(x^2 – 5x + 6 = 0\).

  1. Find two numbers that multiply to 6 and add to \(-5\): \(-2\) and \(-3\).
  2. Factor: \((x – 2)(x – 3) = 0\).
  3. Set each factor to zero: \(x = 2\) or \(x = 3\).

Answer: \(x = 2\) or \(3\)

vertex (5/2, -1/4)

Example B — Square-root method

Solve \(x^2 – 9 = 0\).

  1. No middle term — add 9: \(x^2 = 9\).
  2. Take the square root of both sides, keeping \(\pm\).
  3. \(x = \pm 3\).

Answer: \(x = \pm 3\)

vertex (0, -9)

Example C — Leading coefficient

Solve \(2x^2 – 7x + 3 = 0\).

  1. Factor: \((2x – 1)(x – 3) = 0\).
  2. Set each factor to zero: \(2x – 1 = 0\) or \(x – 3 = 0\).
  3. Solve: \(x = \tfrac12\) or \(x = 3\).

Answer: \(x = \tfrac12\) or \(3\)

vertex (7/4, -25/8)

Example D — One repeated root

Solve \(x^2 – 4x + 4 = 0\).

  1. Recognize the perfect square: \((x – 2)^2 = 0\).
  2. Both factors are \(x – 2\), so they give the same value.
  3. One double root: \(x = 2\) — the vertex sits right on the x-axis.

Answer: \(x = 2\)

vertex (2, 0)

Where You’ll Use It

Quadratic equations answer “when does it hit zero?” — when a thrown ball lands, when a profit becomes zero (break-even), when an area reaches a target. Setting a quadratic model equal to a value and solving is one of the most common tasks in algebra, physics, and engineering.

Slip-Ups That Cost Easy Points

  • Not setting it to zero first. Factoring and the formula need \(ax^2 + bx + c = 0\); move everything to one side.
  • Forgetting the \(\pm\). A square root gives two answers: \(x^2 = 9\) means \(x = 3\) and \(-3\).
  • Sign errors in the formula. Watch \(-b\) and the \(-4ac\); a single sign flip changes everything.
  • Reporting only one root. Most quadratics have two solutions — give both unless it’s a perfect square.

Your Turn: Solve

Find all roots, then reveal the answers.

  1. \(x^2 – 7x + 10 = 0\)
  2. \(x^2 – 16 = 0\)
  3. \(x^2 + 5x + 6 = 0\)
  4. \(x^2 – 4x + 4 = 0\)
  5. \(3x^2 – 5x – 2 = 0\)
  6. \(x^2 – 2x – 15 = 0\)
Show answers
  1. \(\color{blue}{x = 2, 5}\)
  2. \(\color{blue}{x = \pm 4}\)
  3. \(\color{blue}{x = -2, -3}\)
  4. \(\color{blue}{x = 2}\)
  5. \(\color{blue}{x = -\tfrac13, 2}\)
  6. \(\color{blue}{x = -3, 5}\)
Keep practicing

Make Your Own Quadratics Worksheet

Generate fresh solve-the-quadratic problems with a full answer key — print or save as a PDF.

New problems every click — never the same sheet twice
Step-by-step answer key so you can self-check
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Frequently Asked Questions

What are the ways to solve a quadratic equation?

Factoring (fastest when it factors), the square-root method (for equations with no middle term), and the quadratic formula (which always works). All give the same roots.

How many solutions does a quadratic have?

Up to two real solutions. A perfect square gives one (a repeated root), and some quadratics have no real solutions — the discriminant tells you which.

When should I use the quadratic formula?

When the quadratic doesn’t factor with simple integers, or you want a method that always works. Just plug \(a\), \(b\), and \(c\) into \(x = \tfrac{-b \pm \sqrt{b^2 – 4ac}}{2a}\).

Why must I set the equation to zero first?

Factoring relies on the zero-product property (if a product is 0, a factor is 0), and the formula is defined for \(ax^2 + bx + c = 0\). Both need a zero on one side.

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