Number Properties Puzzle – Challenge 20
Looking for maths puzzles with answers? If so, you are in the right place. The solution is beneficial when trying to solve a hard puzzle like this one.
Challenge:
If n is a perfect cube number and n = 2700m, what is one possible value of m?
The Absolute Best Book to Challenge Your Smart Student!
$11.99
Satisfied 123 Students
The correct answer is 10.
Factorize 2700:
\(2700 = 2^2 × 3^3 × 5^2\)
The product of two perfect cube numbers is another perfect cube number. For example 8 and 27 are perfect cube numbers. The product of 8 and 27 is 216, which is another perfect cube number. (8 × 27 = 216 and \(6^3 = 216\))
To make 2700m a perfect cube number we need the product of 5 and 2.
\(2700 = 2^2 × 3^3 × 5^2\)
\(2700 × 10 = 2^3 × 3^3 × 5^3\), therefore, m = 10
The Absolute Best Books to Ace Algebra
$14.99
Satisfied 1 Students
$14.99
Satisfied 92 Students
$15.99
Satisfied 125 Students
Related to This Article
More math articles
- How to Master Motion: A Comprehensive Guide to Understanding the Distance Formula in Real-World Problems
- Top 10 PSAT/NMSQT Math Practice Questions
- How to Identify the Change, Price, or Amount Paid
- The Math Game Show: How to Find Probability of Simple and Opposite Events
- 4th Grade MEAP Math FREE Sample Practice Questions
- How to Solve Coterminal Angles and Reference Angles? (+FREE Worksheet!)
- Top 10 3rd Grade IAR Math Practice Questions
- How to Unraveling the Transitive Property: A Key to Understanding Mathematical Relationships
- How to Prepare for the 8th Grade STAAR Math Test?
- 5th Grade LEAP Math Worksheets: FREE & Printable
What people say about "Number Properties Puzzle – Challenge 20 - Effortless Math: We Help Students Learn to LOVE Mathematics"?
No one replied yet.