# Number Properties Puzzle – Challenge 20 Looking for maths puzzles with answers? If so, you are in the right place. The solution is very useful when trying to solve a hard puzzle like this one.

## Challenge:

If n is a perfect cube number and n = 2700m, what is one possible value of m?

### The Absolute Best Book to challenge your Smart Student!

Factorize 2700:
$$2700 = 2^2 × 3^3 × 5^2$$
The product of two perfect cube numbers is another perfect cube number. For example 8 and 27 are perfect cube numbers. The product of 8 and 27 is 216, which is another perfect cube number. (8 × 27 = 216 and $$6^3 = 216$$)
To make 2700m a perfect cube number we need the product of 5 and 2.
$$2700 = 2^2 × 3^3 × 5^2$$
$$2700 × 10 = 2^3 × 3^3 × 5^3$$, therefore, m = 10 ## How Does It Work? ### 1. Find eBooks

Locate the eBook you wish to purchase by searching for the test or title.  ### 3. Checkout

Complete the quick and easy checkout process. ## Why Buy eBook From Effortlessmath? Save up to 70% compared to print  Help save the environment  Over 2,000 Test Prep titles available Over 80,000 happy customers Over 10,000 reviews with an average rating of 4.5 out of 5  