Number Properties Puzzle – Challenge 20
Looking for maths puzzles with answers? If so, you are in the right place. The solution is beneficial when trying to solve a hard puzzle like this one.
![Number Properties Puzzle – Challenge 20](https://www.effortlessmath.com/wp-content/uploads/2020/04/20-512x240.jpg)
Challenge:
If n is a perfect cube number and n = 2700m, what is one possible value of m?
The Absolute Best Book to Challenge Your Smart Student!
![](https://www.effortlessmath.com/wp-content/uploads/2020/04/answer.png)
The correct answer is 10.
Factorize 2700:
\(2700 = 2^2 × 3^3 × 5^2\)
The product of two perfect cube numbers is another perfect cube number. For example 8 and 27 are perfect cube numbers. The product of 8 and 27 is 216, which is another perfect cube number. (8 × 27 = 216 and \(6^3 = 216\))
To make 2700m a perfect cube number we need the product of 5 and 2.
\(2700 = 2^2 × 3^3 × 5^2\)
\(2700 × 10 = 2^3 × 3^3 × 5^3\), therefore, m = 10
The Absolute Best Books to Ace Algebra
Related to This Article
More math articles
- How to Solve Point-Slope Form of Equations?
- Growing Patterns
- Other Topics Puzzle – Challenge 96
- Top 10 Tips to Create an ACCUPLACER Math Study Plan
- How to Prepare for the SIFT Math Test?
- Convert Units of Measurement
- Full-Length ACT Math Practice Test
- 5th Grade ISASP Math Worksheets: FREE & Printable
- How to Define Sine, Cosine, and Tangent
- TASC Math Formulas
What people say about "Number Properties Puzzle – Challenge 20 - Effortless Math: We Help Students Learn to LOVE Mathematics"?
No one replied yet.