Number Properties Puzzle – Challenge 20
Looking for maths puzzles with answers? If so, you are in the right place. The solution is beneficial when trying to solve a hard puzzle like this one.
Challenge:
If n is a perfect cube number and n = 2700m, what is one possible value of m?
The Absolute Best Book to Challenge Your Smart Student!
Original price was: $16.99.$11.99Current price is: $11.99.
Satisfied 123 Students
The correct answer is 10.
Factorize 2700:
\(2700 = 2^2 × 3^3 × 5^2\)
The product of two perfect cube numbers is another perfect cube number. For example 8 and 27 are perfect cube numbers. The product of 8 and 27 is 216, which is another perfect cube number. (8 × 27 = 216 and \(6^3 = 216\))
To make 2700m a perfect cube number we need the product of 5 and 2.
\(2700 = 2^2 × 3^3 × 5^2\)
\(2700 × 10 = 2^3 × 3^3 × 5^3\), therefore, m = 10
The Absolute Best Books to Ace Algebra
Original price was: $29.99.$19.99Current price is: $19.99.
Original price was: $29.99.$14.99Current price is: $14.99.
Original price was: $29.99.$14.99Current price is: $14.99.
Satisfied 1 Students
Original price was: $24.99.$14.99Current price is: $14.99.
Satisfied 92 Students
Original price was: $24.99.$15.99Current price is: $15.99.
Satisfied 125 Students
Related to This Article
More math articles
- The Best School Supplies for Learning Math
- 7 Best PSAT Math Study Guides
- Other Topics Puzzle – Challenge 94
- 5th Grade MAP Math Worksheets: FREE & Printable
- How to Solve Multi-Step Word Problems
- 7th Grade MCAP Math Worksheets: FREE & Printable
- Introduction to Matrix Inverse
- Model Magic: Visualizing Division with Two-digit Divisors
- How to Multiply and Divide Integers? (+FREE Worksheet!)
- How is the FTCE General Knowledge Test Scored?
What people say about "Number Properties Puzzle – Challenge 20 - Effortless Math: We Help Students Learn to LOVE Mathematics"?
No one replied yet.