# Top 10 CBEST Math Practice Questions

Are you preparing for the CBEST Math Test? The surest way to succeed on the CBEST Math test is to work through as many CBEST Math practice questions as possible. Here are the top 10 CBEST Math practice questions to help you review the most common CBEST Math concepts. These CBEST Math practice questions are designed to cover mathematics concepts and topics that are found on the actual test. The questions have been fully updated to reflect the latest 2022 CBEST guidelines. Answers and full explanations are provided at the end of the post.

Start your CBEST Math test prep journey right now with these sample CBEST Math questions.

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**CBEST Math Practice Questions**

1- A number is chosen at random from \(1\) to \(25\). Find the probability of not selecting a composite number.

A. \(\frac{1}{25}\)

B. \(25\)

C. \(\frac{9}{25}\)

D. \(1\)

E. \(0\)

2- Removing which of the following numbers will change the average of the numbers to \(6\)?

\(1, 4, 5, 8, 11, 12\)

A. \(1\)

B. \(4\)

C. \(5\)

D. \(11\)

E. \(12\)

3- A rope weighs \(600\) grams per meter in length. What is the weight in kilograms of \(12.2\) meters of this rope? \((1 kilograms = 1000 grams\))

A. \(0.0732\)

B. \(0.732\)

C. \(7.32\)

D. \(7320\)

E. \(73200\)

4- If \(y = 4ab + 3b^3\), what is \y\) when \(a = 2\) and \(b = 3\)?

A. \(24\)

B. \(31\)

C. \(36\)

D. \(51\)

E. \(105\)

5- If \(f(x) = 5 + x\) and \(g(x) = – x^2 – 1 – 2x\), then find \((g – f)(x)\)?

A. \( x^2 – 3x – 6\)

B. \( x^2 – 3x +6\)

C. \( -x^2 – 3x +6\)

D. \( -x^2 – 3x – 6\)

E. \( -x^2 +3x – 6\)

6- The marked price of a computer is \(D\) dollar. Its price decreased by \(20\%\) in January and later increased by \(10 \%\) in February. What is the final price of the computer in \(D\) dollars?

A. \(0.80 D\)

B. \(0.88 D\)

C. \(0.90 D\)

D. \(1.20 D\)

E. \(1.40D\)

7-The number \(940.5\) is \(1,000\) times greater than which of the following numbers?

A. \(0.405\)

B. \(0.0405\)

C. \(0.0450\)

D. \(0.00405\)

E. \(0.000405\)

8- David’s current age is \(42\) years, and Ava’s current age is \(6\) years. In how many years David’s age will be \(4\) times Ava’s age?

A. \(4\)

B. \(6\)

C. \(8\)

D. \(10\)

E. \(14\)

9-How many tiles of \(8 cm^2\) are needed to cover a floor of dimension \(6 cm\) by \(24 cm\)?

A.\(6\)

B.\(12\)

C. \(18\)

D. \(24\)

E. \(36\)

10-What is the median of these numbers? \(4, 9, 13, 8, 15, 18, 5\)

A. \(8\)

B. \(9\)

C. \(13\)

D. \(15\)

E. \(20\)

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## Answers:

1- **C**

Set of number that are not composite between \(1\) and \(25: A= {2, 3, 5, 7, 11, 13, 17, 19, 23}\)

\(Probability =\frac{number \space of \space desired \space outcomes}{number \space of \space total \space outcomes}=\frac{9}{25}\)

2- **D **

Check each option provided:

A.\( \frac{(4+5+8+11+12)}{5}=\frac{40}{5}=8\)

B. \(\frac{(1+5+8+11+12)}{5}=\frac{37}{5}=7.4\)

C. \(\frac{(1+4+8+11+12)}{5}=\frac{36}{5}=7.2\)

D. \(\frac{1+4+5+8+12}{5}=\frac{30}{5}=6\)

E. \(\frac{1+4+5+8+11}{5}=\frac{29}{5}=5.8\)

3- **C**

The weight of \(12.2\) meters of this rope is: \(12.2 × 600 g = 7320\) g

\(1 kg = g\), therefore, \(7320 g\) \(÷ 1000 = 7.32 kg\)

4- **E**

\(y = 4ab + 3b^3\)

Plug in the values of \(a\) and \(b\) in the equation: \(a = 2\) and \(b = 3\)

\(y = 4 (2) (3) + 3 (3)3 = 24 + 3(27) = 24 + 81 = 105\)

5- **D**

\((g – f)(x) = g(x) – f(x) = (– x^2 – 1 – 2x) – (5 + x)

– x^2 – 1 – 2x – 5 – x = – x^2 – 3x – 6\)

6- **B**

To find the discount, multiply the number by \((100\% –\) rate of discount).

Therefore, for the first discount we get: \((D) (100\% – 20%\)) \(=\) \((D) (0.80) = 0.80\) \(D\)

For increase of \(10%\): \((0.80 D)\) \((100\% +\) \(10\%\)) \(= (0.80 D) (1.10) = 0.88 D = 88\% of D\)

7- **B**

1000 times the number is \(40.5\). Let \(x\) be the number, then:

\(1000x=40.5\)

\(x =\frac{40.5}{1000}=0.0405\)

8- **B**

Let’s review the options provided.

A. \(4\). In \(4\) years, David will be \(46\) and Ava will be \(10. 46\) is not \(4\) times \(10\).

B. \(6\). In \(6\) years, David will be \(48\) and Ava will be \(12. 48\) is \(4\) times \(12\)!

C. \(8\). In \(8\) years, David will be \(80\) and Ava will be \(14. 50\) is not \(4\) times \(14\).

D. \(10\). In \(10\) years, David will be \(52\) and Ava will be \(16. 52\) is not \(4\) times \(16\).

E. \(14\). In \(14\) years, David will be \(56\) and Ava will be \(20. 56\) is not \(4\) times \(20\).

9- **C**

The area of the floor is: \(6 cm × 24 cm = 144 cm\)

The number is tiles needed \(= 144 ÷ 8 = 18\)

10- **B**

Write the numbers in order:

\(4, 5, 8, 9, 13, 15, 18\)

Since we have \(7\) numbers (\(7\) is odd), then the median is the number in the middle, which is \(9\).

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