Top 10 AFOQT Math Practice Questions
Preparing for the AFOQT Math test? Need some sample practice questions to measure your exam readiness? The best way to prepare for your AFOQT Math test is to work through as many AFOQT Math practice questions as possible. Here are the top 10 AFOQT Math practice questions to help you review the most important AFOQT Math concepts. These AFOQT Math practice questions are designed to cover mathematics concepts and topics that are found on the actual test. The questions have been fully updated to reflect the latest 2026 AFOQT guidelines. Answers and full explanations are provided at the end of the post.
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x^2+2xy-2y^2\)
D. \(4x^2+2xy-2y^2\)
7- Each year, a cyber café charges its customers a base rate of $15, with an additional $0.20 per visit for the first 40 visits, and $0.10 for every visit after that. How much does the cyber café charge a customer for a year in which 60 visits are made?
A. $25
B. $29
C. $35
D. $39
8- What is the product of all possible values of \(x\) in the following equation?
\(|x-10| = 3\)
A. 3
B. 7
C. 13
D. 91
9- What is the value of \(x\) in the following system of equations?
\(2x+5y=11\)
\(4x-2y=-14\)
A. \(-1\)
B. 1
C. 4
D. \(-2\)
10- While at work, Emma checks her email once every 90 minutes. In 9−hour, how many times does she check her email?
A. 4 Times
B. 5 Times
C. 7 Times
D. 6 Times
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Answers:
1- B
\(36 ÷ 3 = 12\) hours for one course
\(12 × 25 = 300 ⇒ $300\)
2- D
Plug in the value of \(x\) and \(y\).
\(x=3\) and \(y=-2\)
\((5(x-2y)+(2-x))^2=(5(3-2(-2))+(2-3))^2=(5(3+4)+(-1))^2 = (34)^2=36\) For additional educational resources, . For additional educational resources
3- D
Michelle \(=\) Karen \(– 9\)
Michelle \(=\) David \(– 4\)
Karen \(+\) Michelle \(+\) David \(= 82\)
Karen \(+ 9 =\) Michelle ⇒ Karen \(=\) Michelle \(– 9\)
Karen \(+\) Michelle \(+\) David \(= 82\)
Now, replace the ages of Karen and David by Michelle. Then:
Michelle \(+ 9 +\) Michelle + Michelle \(+ 4 = 82\)
\(3\)Michelle \(+ 13 = 82\) ⇒ 3Michelle \(= 82 – 13\)
\(3\)Michelle \(= 69\)
Michelle \(= 23\) For additional educational resources, .
4- D
The equation of a line in slope intercept form is: \(y=mx+b\)
Solve for \(y\).
\(4x-2y=12 {\Rightarrow} -2y=12-4x {\Rightarrow} y=(12-4x){\div}(-2) {\Rightarrow} y=2x-6\)
The slope of this line is \(2\).
The product of the slopes of two perpendicular lines is \(-1\).
Therefore, the slope of a line that is perpendicular to this line is:
\(m_{1} {\times} m_{2} = -1 {\Rightarrow} 2 {\times} m_{2} = -1 {\Rightarrow} m_{2} = \frac{-1}{2}\) For additional educational resources, .
5- B
Since Julie gives \(8\) pieces of candy to each of her friends, then, the number of pieces of candies must be divisible by 8.
A. \(187 ÷ 8 = 23.375\)
B. \( 216 ÷ 8 = 27\)
C. \( 343 ÷ 8 = 42.875\)
D. \(223 ÷ 8 = 27.875\)
Only choice B gives a whole number. For additional educational resources, .
6- D
Use FOIL method.
\((2x+2y)(2x-y) = 4x^2-2xy+4xy-2y^2=4x^2+2xy-2y^2\) For additional educational resources, .
7- A
The base rate is \($15\).
The fee for the first \(40\) visits is: \(40×0.20=8\)
The fee for the visits \(41\) to \(60\) is: \(20×0.10=2\)
Total charge: \(15 + 8 + 2 = 25\) For additional educational resources, .
8- D
To solve absolute values equations, write two equations.
\(x-10\) could be positive \(3\), or negative \(3\). Therefore,
\(x-10=3 \Rightarrow x=13\)
\(x-10=-3 \Rightarrow x=7\)
Find the product of solutions: \(7 \times 13 = 91 \) For additional educational resources, .
9- D
Solving Systems of Equations by Elimination
Multiply the first equation by \((-2)\), then add it to the second equation.
\({-2(2x+5y= 11) \ 4x-2y=-14} {\Rightarrow} {-4x-10y= -22 \ 4x-2y=-14} {\Rightarrow} {-12y= -36} {\Rightarrow} {y= 3}\)
Plug in the value of y into one of the equations and solve for \(x\).
\(2x+5(3)= 11 {\Rightarrow} 2x+15= 11 {\Rightarrow} 2x= -4 {\Rightarrow} x= -2\) For additional educational resources, .
10- D
Change \(9\) hours to minutes, then: \(9 × 60 = 540\) minutes
\(\frac{540}{90}=6\) For additional educational resources, .
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