How to Find Discontinuities of Rational Functions?
How to find discontinuities of rational functions, step by step: the rule in plain language, solved examples worked one line at a time, and practice questions so you can try it yourself before moving on.
Discontinuities of rational functions occur when the denominator is (0). Read this post to know more about finding discontinuities of rational functions.
Whenever we want to discover the point of discontinuity of any function, we just have to set the denominator to zero.
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A step-by-step guide to the discontinuities of rational functions
In rational functions, points of discontinuity refer to fractions that are undefined or have zero denominators. When the denominator of a fraction is (0), it becomes undefined and appears as a whole or a break in the graph.
To find discontinuities of rational functions, follow these steps:
- Obtain a function’s equation. Note that if the numerator and denominator expressions have any similar factors, they should be wiped out.
- Rewrite the denominator expression as a zero-valued equation.
- Solve the equation for the denominator.
The Discontinuities of Rational Functions, Example 1:
Find the discontinuities of (f(x)=frac{x-1}{x^2-x-6}).
First, setting the denominator equal to zero: (x^2-x-6=0).
Then factoring it out: (x^2-x-6=0) ⇒ ((x+2)(x-3)=0)
(x+2=0 ⇒ x=-2)
(x-3=0 ⇒x=3)
Now, (f) is discontinuous at (x=-2) and (x=3).
The Discontinuities of Rational Functions, Example 2:
Find the discontinuities of (f(x)=frac{1}{x^2-4}).
First, setting the denominator equal to zero: (x^2-4=0).
Then factoring it out: (x^2-4=0) ⇒ ((x+2)(x-2)).
(x+2=0) ⇒ (x=-2)
(x-2=0) ⇒ (x=2)
Now, (f) is discontinuous at (x=-2) and (x=2).
Exercises for the Discontinuities of Rational Functions
Find the discontinuities of rational functions.
- (color{blue}{f(x)=frac{x+2}{x^2-5x-6}})
- (color{blue}{f(x)=frac{x-2}{x^2-2x-35}})
- (color{blue}{f(x)=frac{x^2-6x+8}{x-5}})
- (color{blue}{f(x)=frac{x+10}{x^2-10x+21}})
- (color{blue}{x=-1, x=6})
- (color{blue}{x=7, x=-5})
- (color{blue}{x=5})
- (color{blue}{x=3, x=7})
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