ALEKS Math Practice Test Questions
These ALEKS Math practice questions are designed to be similar to those found on the real ALEKS Math test. They will assess your level of preparation and will give you a better idea of what to study for your exam. For additional educational resources, .
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Answers:
1- \(x^2 – 3x – 6\)
\((g – f)(x) = g(x) – f(x) = (– x^2 – 1 – 2x) – (5 + x) – x^2 – 1 – 2x – 5 – x = \ – x^2 – 3x – 6\)
2- \(-38≤x≤32\)
\(\frac{|3+x|}{7}≤5⇒|3+x|≤35⇒-35≤3+x≤35⇒-35-3≤x≤35-3⇒ -38≤x≤32 \)
3- \(–\frac {\sqrt{3}}{3} \)
\( tan (– \frac{π}{6}) = \ –\frac {\sqrt{3}}{3} \)
4- \(4a^2\sqrt{b} \)
\( \frac{\sqrt{32a^5 b^3}}{\sqrt{2ab^2} } = )( \frac{4a^2 \sqrt{2ab}}{b\sqrt{2a} } = 4a^2\sqrt{b} \)
5- 57,000 loss
\(c(3)=(3)^2+10(3)+30=9+30+30=69 4×3=12⇒12-69=-57⇒57,000 loss\)
6- \(\frac{4}{5}\)
\( sinB=\frac{Opposite Side}{Hypotenuse}=\frac{4}{5}\)
7- \(y=\frac{6}{7} x+\frac{12}{7}\)
\(-7y=-6x-12⇒y=\frac{-6}{-7} x-\frac{12}{-7}⇒y=\frac{6}{7} x+\frac{12}{7}\)
8- \(0, -2, -3\)
Frist factor the function: \(x (x+2)(x+3)\) To find the zeros, \(f(x)\) should be zero. \(f(x)=x (x+2)(x+3)=0\) Therefore, the zeros are: \(x=0 (x+2)=0 ⇒ x= -2 (x+3)=0 ⇒ x= -3\)
9- \((1,4)\)
\(\begin{cases}5x+y=9\\10x-7y=-18\end{cases}\)⇒ Multiply the first equation by\( -2 ⇒\) \(\begin{cases}-10x-2y=-18\\10x-7y=-18\end{cases}\) Add two equations \(⇒ –9y = –36 ⇒ y = 4\) then: \(x = 1\)
10- 4
\((x – h)^2 + (y – k)^2 = r^2 ⇒\) center: \((h,k)\) and radius: \(r\)
\((x – 3)^2 + (y + 6)^2 = 12 ⇒\) center: \((3,-6)\) and radius: \(\sqrt{16}=4\)
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