AFOQT Math Practice Test Questions

3- C
\(average (mean) =\frac{(sum \space of \space terms)}{(number \space of \space terms)} {\Rightarrow} 88 = \frac{(sum \space of \space terms)}{50} {\Rightarrow} sum = 88 {\times} 50 = 4400\)
The difference of 94 and 69 is 25. Therefore, 25 should be subtracted from the sum.
\(4400 – 25 = 4375\)
\(mean = \frac{(sum of terms)}{(number of terms)} ⇒ mean = \frac{(4375)}{50}= 87.5\) For additional educational resources, .

4- B
\(5(a–6)=22 ⇒ 5a-30=22 ⇒5a=22+30=52\)
\(⇒ 5a=52⇒a=\frac{52}{5}= 10.4 \) For additional educational resources, .

5- D
Use exponent multiplication rule:
\(x^a . x^b = x^{a + b}\)
Then:
\(3^{24}=3^8× 3^x=3^{8+x}\)
\(24 = 8 + x ⇒x=24-8=16\) For additional educational resources, .

6- C
The distance between Jason and Joe is 9 miles. Jason running at 5.5 miles per hour and Joe is running at the speed of 7 miles per hour. Therefore, every hour the distance is 1.5 miles less. \(9 \div 1.5 = 6\) For additional educational resources, .

7- C
The failing rate is 11 out of \(55 = \frac{11}{55} \)
Change the fraction to percent:
\(\frac{11}{55} {\times} 100\%=20\% \)
20 percent of students failed. Therefore, 80 percent of students passed the exam. For additional educational resources, .

8- C
To factor the expression \(x^2 + 5 – 6\), we need to find two numbers whose sum is 5 and their product is \(-6\).
Those numbers are 6 and \(-1\). Then:
\(x^2+5-6=(x+6)(x-1)\) For additional educational resources, .

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9- B
Slope of a line:\(\frac{y_2- y_1}{x_2 – x_1}=\frac{rise}{run}\)
\(\frac{y_2- y_1}{x_2 – x_1}=\frac{3- 7}{5 – 6}=\frac{-4}{-1}= 4\) For additional educational resources, .

10- A
The difference of 2 and 3 is 1, 3 and 5 is 2, 5 and 8 is 3, 8 and 12 is 4, 12 and 17 is 5, 17 and 23 is 6, 23 and next number should be 7. The number is \(23 + 7 = 30\) For additional educational resources, .

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