Ratio, Proportion and Percentages Puzzle – Challenge 25
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Challenge:
20 liters of 40 percent antifreeze in fuel are mixed with 40 liters of 10 percent antifreeze in fuel. The percentage of antifreeze in the new solution is:
A- \(15\%\)
B- \(20\%\)
C- \(25\%\)
D- \(30\%\)
E- \(35\%\)
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The correct answer is B.
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The total amount of the mixture of two fuels is 60 liters. (20 liter plus 40 liters) Let’s find the total of the antifreeze.
The sum of \(40\%\) of 20 liters and \(10\%\) of 40 liters is:
\(0.40 × 20 + 0.10 × 40 = 8 + 4 = 12\)
Of 60 liters of the mixture, 12 liters are antifreeze. So, the percentage of antifreeze in the new solution is:
\(12 ÷ 60 = 0.20 = 20\%\)
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