Top 10 CLEP College Mathematics Practice Questions

B. \(y = 5x\)

C. \(y≥x\)

D. \(y+4x=z\)

9- The perimeter of the trapezoid below is (64). What is its area?

A. \(252 cm^2\)

B. \(234cm^2\)

C. \(216cm^2\)

D. \(260cm^2\)

10- Two third of \(15\) is equal to \(\frac{2}{5}\) of what number?

A. 12

B. 20

C. 25

D. 60

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Answers:

2- B
Use distance formula: Distance\(=\)Rate\(×\) time\(⇒420=65×T\), divide both sides by \(65.420÷65=T⇒T= 6.4\) hours. Change hours to minutes for the decimal part. \(0.4 \) hours\(=0.4×60=24\) minutes.

3- D
Use Pythagorean Theorem: \(a^2+b^2=c^2⇒5^2+12 ^2=c^2⇒169=c^2⇒c=13\)

4- D
The ratio of boys to girls is \(2:3\). Therefore, there are \(2\) boys out of\(5\) students. To find the answer, first, divide the total number of students by\(5\), then multiply the result by \(2\).
\(500÷5=100 ⇒100 × 2=200\)

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5- D
Use FOIL (First, Out, In, Last).\((7x+2y)(5x+2y)= \)
\(35x^2+14xy+10xy+4y^2=\)
\(35x^2+ 24xy+4y^2\)

6- D
Use distributive property: \(5x(4+2y)=20x+10xy\)

7- D
\(y=5ab+3b^3\). Plug in the values of a and b in the equation: \(a=2\) and \(b=3\)
\(y=5 (2)(3)+3 (3)^3=30+3(27)=30+81=111\)

8- D
\(x\) and \(z\) are colinear. \(y\) and \(5x\) are colinear. Therefore,
\(x+z=y+5x\),subtract \(x\) from both sides,then,\(z=y+4x\)

9- D
The perimeter of the trapezoid is \(64\). Therefore, the missing side (height) is
\(=64-18-12-14=20\). Area of the trapezoid: \(A= \frac{1}{2} h (b_{1}+b_{2 })=
\frac{1}{2} (20) (12+14)=260\)

10- C
Let \(x\) be the number. Write the equation and solve for \(x\). \(\frac{2}{3} ×15= \frac{2}{5}\).
\(x⇒\frac{2×15}{3}=\frac{2x}{5}\), use cross multiplication to solve for \(x\).
\(5×30=2x×3⇒150=6x⇒x=25\)

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