How to Solve Work-Rate Word Problems: Step-by-Step Guide for 2026

How to Solve Work-Rate Word Problems: Step-by-Step Guide for 2026

Work-rate problems show up under different costumes. Two painters paint a house together. Two pipes fill a pool. One worker takes three hours; another takes five; how long together? The phrasing changes; the math does not. Every work-rate problem in Algebra 1 boils down to one formula and a single equation.

This guide explains the formula, walks through every sub-type with examples, and ends with the four mistakes that trip up most students.

The Universal Work-Rate Formula

If person A takes a hours to do a job and person B takes b hours, then together they take t hours, where:

\[\frac{1}{a} + \frac{1}{b} = \frac{1}{t}\]

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The fractions 1/a and 1/b represent rates: the fraction of the job each does per hour. Their rates add when they work together.

That’s the entire formula. Most problems are just plugging in.

Example 1: Two Workers

Anna can paint a fence in 6 hours. Ben can paint the same fence in 4 hours. How long does it take them together?

How to Solve Work-Rate Word Problems: Step-by-Step Guide for 2026 illustration A

1/6 + 1/4 = 1/t.

Common denominator: 12. 2/12 + 3/12 = 5/12.

5/12 = 1/t → t = 12/5 = 2.4 hours.

Sanity check: working together should be faster than the faster worker alone (4 hours). 2.4 hours is faster. Good.

Example 2: Three Workers

Three painters can do a job in 6, 9, and 12 hours respectively. How long together?

1/6 + 1/9 + 1/12 = 1/t.

Common denominator: 36. 6/36 + 4/36 + 3/36 = 13/36.

t = 36/13 ≈ 2.77 hours.

The combined time is always less than any individual time, no matter how many workers.

Example 3: Pipes Filling a Tank

Pipe A fills a tank in 3 hours. Pipe B fills the same tank in 5 hours. How long with both pipes open?

1/3 + 1/5 = 1/t.
5/15 + 3/15 = 8/15.
t = 15/8 = 1.875 hours = 1 hour 52.5 minutes.

Original price was: $109.99.Current price is: $54.99.

Example 4: A Pipe That Drains

A drain works against fill pipes. Subtract its rate.

Pipe A fills the tank in 4 hours. Drain D empties it in 6 hours. With both open, how long to fill?

1/4 − 1/6 = 1/t.
3/12 − 2/12 = 1/12.
t = 12 hours.

The tank fills, but slowly. If the drain were faster than the fill, the tank would never fill.

Example 5: Solving for an Unknown Rate

Together, two workers finish a job in 4 hours. Alone, worker A takes 6 hours. How long does worker B take alone?

1/6 + 1/b = 1/4.
1/b = 1/4 − 1/6.
Common denominator: 12. 1/b = 3/12 − 2/12 = 1/12.
b = 12 hours.

Example 6: One Worker Stops Early

Maria starts painting a fence; her rate is 1/8 (job per hour). After 2 hours, Sam joins her at a rate of 1/12 per hour. How much longer until the job is done?

In the first 2 hours, Maria completes 2 × 1/8 = 1/4 of the job.

Remaining: 3/4 of the job.

Together their rate: 1/8 + 1/12 = 3/24 + 2/24 = 5/24 per hour.

Time to finish: (3/4) / (5/24) = (3/4) × (24/5) = 72/20 = 3.6 hours.

Total elapsed time: 2 + 3.6 = 5.6 hours.

Example 7: Mixed Units

Watch units. Convert minutes to hours, or rate to “per minute,” consistently.

Original price was: $109.99.Current price is: $54.99.
How to Solve Work-Rate Word Problems: Step-by-Step Guide for 2026 illustration B

One photocopier prints 60 pages per minute. Another prints 90 pages per minute. How long to print 1,500 pages together?

Combined rate: 60 + 90 = 150 pages per minute.
Time: 1,500 / 150 = 10 minutes.

When rates are given in items per time, you can add them directly. The 1/t formula is for jobs that are “one whole job.”

A Quick Chart for Work-Rate Setup

Situation Equation
Two workers together 1/a + 1/b = 1/t
Three workers together 1/a + 1/b + 1/c = 1/t
Worker plus drain 1/a − 1/d = 1/t
Find one worker’s solo time given combined 1/a + 1/b = 1/t, solve for the unknown
One worker stops early Compute fraction done; subtract from 1; divide by combined rate

The Sanity Check Every Time

The combined time t must be less than the slowest worker (and less than every worker, actually). If your t comes out larger than one of the individual times, you set the equation up wrong, probably by adding times instead of rates.

Wrong: “Two workers, 6 and 4 hours each, combined is 6 + 4 = 10 hours.” Adding times is the most common mistake on these problems.

Common Mistakes

  1. Adding times instead of rates. 1/6 + 1/4 = 1/t, not 6 + 4 = t.
  2. Forgetting to flip the result. After computing the combined rate (say, 5/12), the time is 12/5, not 5/12.
  3. Skipping a unit conversion. If one worker is timed in minutes and the other in hours, convert before combining.
  4. Treating a drain as a worker. Drains subtract from the rate; they do not add.

A Memorable Pattern

“Rates add. Times do not.”

Tape that under your desk. Almost every error on these problems traces back to that one fact.

Frequently Asked Questions

Are work-rate problems on the SAT?
Occasionally. They are more common on ACT and on state tests.

Why does adding rates work?
Because rate is the fraction of the job per hour. If A does 1/6 of the job per hour and B does 1/4 per hour, together they do 1/6 + 1/4 per hour. That sum equals 1/t, where t is the combined time.

Can the formula handle more than two workers?
Yes. Just add another 1/c term.

What if the workers are at different paces during different intervals?
Compute the fraction of the job done in each interval and add. See Example 6 for the template.

Does this work for pumps and drains together?
Yes. Pumps add to the rate; drains subtract. If the net rate is negative, the tank empties; if positive, it fills.

Closing Thought

Work-rate problems are a one-line formula and a four-word rule (rates add, times do not). Use the formula, sanity-check that the combined time is less than every individual time, and the topic stops costing you points. Drill ten problems and the setup becomes automatic.

For more practice, browse our Algebra 1 worksheets and our full Math Topics library. When you are ready for a structured workbook, our Algebra 1 collection covers every word-problem type above.

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