10 Most Common TASC Math Questions

D
Write the equation and solve for B: 0.60 A=0.20 B, divide both sides by 0.20, then:
\(\frac{0.60}{0.20 } A=B\), therefore: B=3A, and B is 3 times of A or it’s \(300\%\) of A.

B
Use this formula: Percent of Change \(\frac{New \ Value-Old \ Value}{Old \ Value}×100\% \)
\(\frac{15000-20000}{20000}×100\%=-25\%\) and \(\frac{11200-15000}{15000}×100\%=-25\% \)

D
If the length of the box is 45, then the width of the box is one-third of it, 15, and the height of the box is 5 (one-third of the width). The volume of the box is:
V=lwh =(45)(15)(5)=3375

D
To find the number of possible outfit combinations, multiply the number of options for each factor: \(6×3×5=90\)

C
Use simple interest formula: I=prt (I=interest,p=principal,r=rate,t=time)
I=(8,000)(0.045)(5)=1,800

B
\(6^4\)=6×6×6×6=1,296

C
\(x=\frac{15}{20}=0.75=75\% \)

C
The perimeter of the trapezoid is 56. Therefore, the missing side (height) is =56-18-12-14=12. Area of a trapezoid: \(A=\frac{1}{2 } h (b_{1}+b_{2})=\frac{1}{2}(12)(12+14)=156\)

C
Add the first 5 numbers. 40+45+50+35+55=225
To find the distance traveled in the next 5 hours, multiply the average by the number of hours.
Distance=Average×Rate = 65×5 =325
Add both numbers. 325+225=550

C
Use distance formula: Distance =Rate×time ⇒ 420=65×T, divide both sides by \(65. 420÷65=T ⇒ T=6.4\) hours. Change hours to minutes for the decimal part. 0.4 hours =0.4×60 =24 minutes.