10 Most Common 7th Grade STAAR Math Questions

B
Write the numbers in order:
\(2, 19, 28, 28, 35, 44, 67\)
Since we have 7 numbers (7 is odd), then the median is the number in the middle, which is 28.

C
Three times of 24,000 is 72,000. One-sixth of them canceled their tickets.
One sixth of 72,000 equals 12,000 \((\frac{1}{6}) × 72000 = 12000\).
60,000 \(72000 – 12000 = 60000\) fans are attending this week

A
It’s needed to have a ratio to find the value of \(x\).
\(\frac{45}{40}=\frac{2x+4}{16}⇒ 40(2x+4)=45×16 ⇒ x=7\)

C
\(8 (4-(-8))=96\)

A
\(\frac{1}{3}x + \frac{1}{6}x + \frac{1}{4}x + 12= x\)
\((\frac{1}{3} + \frac{1}{6} + \frac{1}{4}) x+ 12= x\)
\((\frac{9}{12})x+ 12 = x\)
\(x = 48\)
In a bag of small balls \(\frac{1}{6}\) are white then: \(\frac{48}{6} = 8\)

B
Use the information provided in the question to draw the shape.
Use Pythagorean Theorem: \(a^2 + b^2 = c^2\)
\(40^2 + 30^2 = c^2 ⇒ 1600 + 900 = c^2 ⇒ 2500 = c^2 ⇒ c = 50\)

B
The question is this: 530.40 is what percent of 624?
Use the percent formula:
\(part = \frac{percent}{100}× whole\)
\(530.40= \frac{percent}{100}× 624 ⇒ 530.40 = \frac{percent ×624}{100}⇒53040 = percent ×624\)
\(⇒percent = \frac{53040}{624}= 85\)
530.40 is \(85 \%\) of 624. Therefore, the discount is: \(100\% – 85\% = 15\%\)

B
If the score of Mia was 60, then Ava’s score of Ava is 30. Since the score of Emma was half that of Ava, therefore, the score of Emma is 15.

D
If 17 balls are removed from the bag at random, there will be one ball in the bag.
The probability of choosing a brown ball is 1 out of 18. Therefore, the probability of not choosing a brown ball is 17 out of 18, and the probability of not having a brown ball after removing 17 balls is the same.

C
The weight of 12.2 meters of this rope is: \(12.2 × 600 \space g = 7320 \space g\)
\(1\space kg = 1000 \space g\) therefore,
\( 7320 \space g ÷ 1000 = 7.32 \space kg\)