Intelligent Math Puzzle – Challenge 92
Some Math puzzles like the following one stumped even the smartest people. Can You Solve It? The solution is also given.
Challenge:
If A and B are integers and \(\frac{1}{B}=\frac{1}{A}-\frac{1}{20}\) what is the value of A+B?
The Absolute Best Book to challenge your Smart Student!
The correct answer is 9.
\(\frac{1}{B} =\frac{1}{A} -\frac{ 1}{20}\)
Therefore, A is less than B. Why?
Plug in different values for A.
Let’s begin with 2. If A \(= 2 → \frac{1}{B} = \frac{ 1}{2} – \frac{ 1}{20} → \frac{ 1}{B} = \frac{ 9}{20} → 9B = 20\)
B is an integer. Therefore, B cannot be \(\frac{ 20}{9}\)
A \(= 3 → \frac{ 1}{B} = \frac{ 1}{3} – \frac{ 1}{20} → \frac{ 1}{B} = \frac{ 17}{60} → 17B = 60\)
A \(= 4 → \frac{ 1}{B} = \frac{ 1}{4} – \frac{ 1}{20} → \frac{ 1}{B} = \frac{4}{20} → 4B = 20 → B = 5\) Bingo!
A = 4 and B = 5 → A + B = 9The Best Books to Ace Algebra
$14.99Satisfied 1 Students$14.99Satisfied 92 Students$15.99Satisfied 125 Students
Related to This Article
More math articles
- Best Books for Students Preparing for the SAT Math Test
- Full-Length 7th Grade SBAC Math Practice Test-Answers and Explanations
- Full-Length 6th Grade PARCC Math Practice Test
- How to Find the Integral of Radicals
- Top 10 Tips to Create an ASTB Math Study Plan
- 8th Grade SBAC Math Worksheets: FREE & Printable
- How to Count Coins and Bills Up to $20
- How to Calculate the Areas of Triangles and Quadrilaterals
- Hands-On Learning: How to Represent Subtraction of Fractions with Unlike Denominators Using Everyday Objects
- Properties of the Horizontal Line
What people say about "Intelligent Math Puzzle – Challenge 92 - Effortless Math: We Help Students Learn to LOVE Mathematics"?
No one replied yet.