How to Add and Subtract Rational Expressions? (+FREE Worksheet!)

How to Add and Subtract Rational Expressions? (+FREE Worksheet!)

Adding and subtracting rational expressions follows the same logic as adding and subtracting ordinary fractions: you need a common denominator before you can combine the numerators. The key extra step is finding the least common denominator (LCD) of the algebraic expressions, and once you do, combining the numerators and simplifying is straightforward. This skill is essential in Algebra 1 and used extensively in higher-level algebra courses.

What Are Rational Expressions?

A rational expression is a fraction whose numerator and denominator are polynomials. Examples: \(\color{blue}{\frac{3}{(x + 1)}}\), \(\color{blue}{\frac{(x – 2)}{(x^{2} – 4)}}\), and \(\color{blue}{\frac{5}{x}}\). Adding and subtracting rational expressions is exactly like adding fractions — you need a common denominator first.

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How to Add and Subtract Rational Expressions

Case 1 — Same denominators

If the denominators are identical, simply add or subtract the numerators over the common denominator, then simplify.

Example: \(\color{blue}{\frac{2}{(x + 1)} + \frac{3}{(x + 1)} = \frac{(2 + 3)}{(x + 1)}}\) = \(\color{blue}{\frac{5}{(x + 1)}}\)

Case 2 — Different denominators

Find the LCD, build equivalent fractions with that LCD, then add or subtract the numerators.

Example: \(\color{blue}{\frac{1}{(x – 2)} + \frac{2}{(x + 3)}}\).
\(\color{blue}{\text{ LCD } = (x – 2)(x + 3)}\).
Rewrite: \(\color{blue}{\frac{(1(x + 3) + 2(x – 2))}{((x – 2)(x + 3))}}\)
= \(\color{blue}{\frac{(x + 3 + 2x – 4)}{((x – 2)(x + 3))}}\)
= \(\color{blue}{\frac{(3x – 1)}{((x – 2)(x + 3))}}\)

How to find the LCD

Factor each denominator. The LCD is the product of each distinct factor raised to its highest power. Always factor first.

Step-by-Step Summary

  1. Factor each denominator completely.
  2. Identify the LCD (product of all distinct factors at their highest powers).
  3. Rewrite each fraction as an equivalent fraction with the LCD.
  4. Add or subtract the numerators; keep the LCD as the denominator.
  5. Simplify the resulting numerator and reduce the fraction if possible.

Watch: Adding and Subtracting Rational Expressions with Unlike Denominators (Video Lesson)

The Organic Chemistry Tutor demonstrates how to add and subtract rational expressions with unlike denominators step by step:


Adding and Subtracting Rational Expressions – Worked Examples

Example 1: Simplify \(\color{blue}{\frac{2}{(x + 1)} + \frac{3}{(x + 1)}}\).

Same denominators: \(\color{blue}{\frac{(2 + 3)}{(x + 1)}}\) = \(\color{blue}{\frac{5}{(x + 1)}}\)

Example 2: Simplify \(\color{blue}{\frac{1}{(x + 2)} + \frac{1}{(x – 2)}}\).

\(\color{blue}{\text{ LCD } = (x + 2)(x – 2) = x}\)\(\color{blue}{^{2} – 4}\).
= \(\color{blue}{\frac{((x – 2) + (x + 2))}{(x^{2} – 4)}}\)
= \(\color{blue}{\frac{(2x)}{(x^{2} – 4)}}\) = \(\color{blue}{\frac{2x}{(x^{2} – 4)}}\)

Example 3: Simplify \(\color{blue}{\frac{3}{(x + 1)} – \frac{2}{(x – 1)}}\).

\(\color{blue}{\text{ LCD } = (x + 1)(x – 1)}\).
= \(\color{blue}{\frac{(3(x – 1) – 2(x + 1))}{((x + 1)(x – 1))}}\)
= \(\color{blue}{\frac{(3x – 3 – 2x – 2)}{((x + 1)(x – 1))}}\)
= \(\color{blue}{\frac{(x – 5)}{(x^{2} – 1)}}\)

Example 4: Simplify \(\color{blue}{\frac{1}{(x – 2)} + \frac{2}{(x + 3)}}\).

\(\color{blue}{\text{ LCD } = (x – 2)(x + 3)}\).
= \(\color{blue}{\frac{((x + 3) + 2(x – 2))}{((x – 2)(x + 3))}}\)
= \(\color{blue}{\frac{(x + 3 + 2x – 4)}{((x – 2)(x + 3))}}\)
= \(\color{blue}{\frac{(3x – 1)}{((x – 2)(x + 3))}}\)

More Practice: Adding and Subtracting Rational Expressions Video (Khan Academy)

Khan Academy explains the process of adding and subtracting rational expressions with additional examples and interactive practice:


Exercises for Adding and Subtracting Rational Expressions

  1. \(\color{blue}{\frac{4}{(x – 3)} + \frac{2}{(x – 3)}}\)
  2. \(\color{blue}{\frac{1}{(x + 5)} – \frac{1}{(x – 5)}}\)
  3. \(\color{blue}{\frac{3}{(x – 1)} – \frac{1}{(x + 2)}}\)
  4. \(\color{blue}{\frac{2}{(x + 4)} + \frac{3}{(x – 4)}}\)
  5. \(\color{blue}{\frac{x}{(x^{2} – 4)} + \frac{(x – 1)}{(x + 2)}}\)
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Answers

  1. Same denominator: \(\color{blue}{\frac{6}{(x – 3)}}\)
  2. \(\color{blue}{\text{ LCD } = (x + 5)(x – 5)}\): \(\color{blue}{\frac{((x – 5) – (x + 5))}{((x + 5)(x – 5))}}\) = −\(\color{blue}{\frac{10}{(x^{2} – 25)}}\) = −\(\color{blue}{\frac{10}{(x^{2} – 25)}}\)
  3. \(\color{blue}{\text{ LCD } = (x – 1)(x + 2)}\): \(\color{blue}{\frac{(3(x + 2) – (x – 1))}{((x – 1)(x + 2))} = \frac{(2x + 7)}{(x^{2} + x – 2)}}\) = \(\color{blue}{\frac{(2x + 7)}{((x – 1)(x + 2))}}\)
  4. \(\color{blue}{\text{ LCD } = (x + 4)(x – 4)}\): \(\color{blue}{\frac{(2(x – 4) + 3(x + 4))}{(x^{2} – 16)} = \frac{(5x + 4)}{(x^{2} – 16)}}\) = \(\color{blue}{\frac{(5x + 4)}{(x^{2} – 16)}}\)
  5. x² − \(\color{blue}{4 = (x + 2)(x – 2)}\); \(\color{blue}{\text{ LCD } = (x + 2)(x – 2)}\):
    \(\color{blue}{\frac{(x + (x – 1)(x – 2))}{((x + 2)(x – 2))} = \frac{(x + x^{2} – 3x + 2)}{(x^{2} – 4)}}\) = \(\color{blue}{\frac{(x^{2} – 2x + 2)}{(x^{2} – 4)}}\)
Original price was: $109.99.Current price is: $54.99.
Original price was: $109.99.Current price is: $54.99.

Want More Practice?

We haven’t published a worksheet built specifically for Adding and Subtracting Rational Expressions just yet. In the meantime, the free worksheets below cover closely related skills and concepts. If you’d like extra practice, download any that look helpful, complete the problems, and check your work — they’re a great way to reinforce what you learned on this page and strengthen the foundations this topic builds on:

Frequently Asked Questions

Why do I need a common denominator to add rational expressions?

You can only combine numerators when they are parts of the same “whole.” If the denominators differ, the fractions represent different units, and you cannot meaningfully add their tops. A common denominator converts everything to the same unit.

Do I always need to factor the denominators first?

Yes, as a best practice. Factoring reveals shared factors that you can use to build the simplest possible LCD, and it also reveals any common factors in the final answer that can be cancelled.

What domain restrictions apply?

Any x-value that makes any original denominator equal zero is excluded from the domain. State these restrictions alongside your simplified answer.

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