Top 10 5th Grade Georgia Milestones Assessment System Math Practice Questions
Start your 5th Grade Georgia Milestones Assessment System Math test prep journey right now with these sample 5th Grade Georgia Milestones Assessment System Math questions.
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D. 8 hours and 30 minutes
5- 50 is what percent of 40?
A. \(20 \%\)
B. \(25 \%\)
C. \(125 \%\)
D. \(150 \%\)
6- The perimeter of the trapezoid below is 52. What is its area? _________
7- The area of a circle is \(64π\). What is the circumference of the circle?
A. \(8 π\)
B. \(16 π\)
C. \(32 π\)
D. \(64 π\)
8- A rope weighs 800 grams per meter of length. What is the weight in kilograms of 12.2 meters of this rope? (1 kilograms = 1000 grams)
A. 0.0976
B. 0.976
C. 9.76
D. 9760
9- Solve.
\(\frac{1}{2} + \frac{4}{5} – \frac{3}{10} = ?\)
A. \(\frac{9}{10}\)
B. \(\frac{2}{10}\)
C. 1
D. 2
10- How many \(\frac{1}{4}\) cup servings are in a package of cheese that contains \(6 \frac{1}{2}\) cups altogether?_________
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Answers:
1- A
There are 65 cards in the bag, and 13 of them are white. Then, 13 out of 65 cards are white. You can write this as: \(\frac{13}{65}\).
To simplify this fraction, divide both numerator and denominator by 13. Then:
\(\frac{13}{65}=\frac{1}{5}\)
2- B
\(\frac{3}{11}\) means 3 is divided by 11. The fraction line means division or \(÷\). Therefore, we can write \(\frac{3}{11}\) as \(3 ÷ 11\).
3- A
Plug 20 for A in the equations. Only option A works.
\(A+20=40\)
\(20+20=40\)
4- D
50 miles: 1 hour
425 miles : \(425 ÷ 50 = 8.5\) hours
5- C
Use the percent formula:
\(part =\frac{percent}{100}× whole\)
\(50=\frac{percent}{100}× 40⇒ 50 = \frac{percent ×40}{100}⇒ 50 = \frac{percent ×4}{10}\)
Multiply both sides by 10.
500 = percent \(×4\), divide both sides by 4.
125 = percent
6- 104
First, find the missing side of the trapezoid. The perimeter of the trapezoid below is 52. Therefore, the missing side of the trapezoid (its height) is: \(52-12-18-14=52-44=8\)
Area of a trapezoid: \(A = \frac{1}{2} h (b_{1} + b_{2}) = \frac{1}{2} (8) (12 + 14) = 104\)
7- B
Use the area and circumference of a circle formula.
Area of a circle = \(πr^2 ⇒ 64π = πr^2 ⇒ r= 8\)
Circumference of a circle = \(2πr ⇒ C = 2×8×π ⇒ C =16π\)
8- C
1 meter of the rope = 800 grams 12.2 meter of the rope = \(12.2 × 800 =9,760 \)grams = 9.76 kilograms
9- C
\(\frac{1}{2} + \frac{4}{5} – \frac{3}{10} = \frac{(5×1)+(2×4)-(1×3)}{10} =\frac{10}{10}=1\)
10- 26
To solve this problem, divide \(6\frac{1}{2}\) by \(\frac{1}{4}\).
\(6\frac{1}{2}÷\frac{1}{4}=\frac{13}{2}÷\frac{1}{4}=\frac{13}{2}×\frac{4}{1}=26\)
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