Standard Form of a Circle
The equation of a circle is written using the radius and center of the circle.
[include_netrun_products_block from-products="product/6-virginia-sol-grade-3-math-practice-tests/" product-list-class="bundle-products float-left" product-item-class="float-left" product-item-image-container-class="p-0 float-left" product-item-image-container-size="col-2" product-item-image-container-custom-style="" product-item-container-size="" product-item-add-to-cart-class="btn-accent btn-purchase-ajax" product-item-button-custom-url="{url}/?ajax-add-to-cart={id}" product-item-button-custom-url-if-not-salable="{productUrl} product-item-container-class="" product-item-element-order="image,title,purchase,price" product-item-title-size="" product-item-title-wrapper-size="col-10" product-item-title-tag="h3" product-item-title-class="mt-0" product-item-title-wrapper-class="float-left pr-0" product-item-price-size="" product-item-purchase-size="" product-item-purchase-wrapper-size="" product-item-price-wrapper-class="pr-0 float-left" product-item-price-wrapper-size="col-10" product-item-read-more-text="" product-item-add-to-cart-text="" product-item-add-to-cart-custom-attribute="title='Purchase this book with single click'" product-item-thumbnail-size="290-380" show-details="false" show-excerpt="false" paginate="false" lazy-load="true"]
The equation of the circle is shown with the center and radius of the circle. With this information, we can sketch the graph of the circle.
Related Topics
Step by Step Guide to Write the Standard Form of a Circle
- The Standard form of a circle is \((x- h)^2+( y-k)^2= r^2\), where \(r\) is the radius and \((h, k)\) is the center. By knowing the center and radius of the circle we can write the standard form of a circle.
Standard form of a Circle – Example 1:
Write the standard form equation of circle with center: \((0, 5)\), radius: \(3\)
Solution:
The Standard form of a circle is \((x- h)^2+( y-k)^2= r^2\), where \(r\) is the radius and \((h, k)\) is the center.
In this case, the center is \((0, 5)\) and the radius is \(3\): \((h, k)=(0, 5), r=3\)
Then: \((x- 0)^2+( y-5)^2= 3^2 → x^2+( y-5)^2= 9 \)
Standard form of a Circle – Example 2:
Write the standard form equation of the circle \(x^2+y^2-6x+2y= 6\).
Solution:
The Standard form of a circle is \((x- h)^2+( y-k)^2= r^2\), where \(r\) is the radius and \((h, k)\) is the center.
Group \(x\)-variables and \(y\)-variables together: \((x^2-6x)+( y^2+2y)= 6\)
Convert \(x\) to square form: \((x^2-6x+9)+( y^2+2y)= 6+9 → (x-3)^2+( y^2+2y)=6+9\)
Convert \(y\) to square form: \((x-3)^2+( y^2+2y+1)= 6+9+1 → (x-3)^2+(y+1)^2=6+9+1\)
Then: \((x-3)^2+(y+1)^2=4^2\)
Exercises for Writing Standard form of a Circle
Write the standard form equation of each circle with the given information.
- \(\color{blue}{Center: (0, 4)}, \color{blue}{Radius: 2}\)
- \(\color{blue}{Center: (-1, 2)}\), \(\color{blue}{Radius: 5}\)
- \(\color{blue}{x^2+y^2-6x+8y=0}\)
- \(\color{blue}{x^2+y^2-2x+8y=0}\)
- \(\color{blue}{x^2+(y-4)^2=2^2}\)
- \(\color{blue}{(x+1)^2+(y-2)^2=5^2}\)
- \(\color{blue}{(x-5)^2+y^2=4^2}\)
- \(\color{blue}{(x-1)^2+(y+4)^2=5^2}\)
Related to This Article
More math articles
- 8th Grade Georgia Milestones Assessment System Math FREE Sample Practice Questions
- Top 10 CBEST Math Practice Questions
- Polynomial Identity
- Laptop Buying Guide: Essential Tips to Know Before You Buy
- 7th Grade Scantron Math Worksheets: FREE & Printable
- How to Convert Between Polar and Rectangular Coordinates
- The Ultimate 7th Grade LEAP Math Course (+FREE Worksheets)
- 6th Grade IAR Math Practice Test Questions
- The Best Standingff Desks for Online Teachersf
- How to Find Scalar Multiplication of Vectors?






















What people say about "Standard Form of a Circle - Effortless Math: We Help Students Learn to LOVE Mathematics"?
No one replied yet.