How to Find the Area and Circumference of Circles? (+FREE Worksheet!)
Learn how how to find the Area and Circumference of Circles when you have the radius or the diameter of the circle.
Watch this practice video for additional examples and reinforcement:
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A step-by-step guide to solving Circles
- In a circle, variable \(r\) is usually used for the radius and \(d\) for the diameter, and \(π\) is about \(3.14\).
- Area of a circle \(\color{blue}{=πr^2}\)
- Circumference of a circle \(\color{blue}{=2πr}\)

Circles – Example 1:
Find the area of the circle.
For education statistics and research
Use area formula: Area \(=πr^2\),
\(r=6\) \(\text{ in }\), then: Area \(=π(6)^2=36π\) For additional educational resources,.
\(π=3.14\), then: Area \(=36×3.14=113.04\) \(\text{ in }^2\) For additional educational resources,.
Circles – Example 2:
Find the Circumference of the circle.
For additional educational resources,.
Solution: For additional educational resources,.
Use Circumference formula: Circumference \(=2πr \)
\(r=9 \) \(\text{ cm }\), then: Circumference \(=2π(9)=18π \)
\(π=3.14\), then: Circumference \(=18×3.14=56.52\) \(\text{ cm }\) For additional educational resources,.
Circles – Example 3:
Find the area of the circle.
For additional educational resources,.
Solution: For additional educational resources,.
Use area formula: Area \(=πr^2\),
\(r=4\) \(\text{ in }\), then: Area \(=π(4)^2=16π\) For additional educational resources,.
\(π=3.14\), then: Area \(=16×3.14=50.24\) \(\text{ in }^2\) For additional educational resources,.
Circles – Example 4:
Find the Circumference of the circle.
For additional educational resources,.
Solution: For additional educational resources,.
Use Circumference formula: Circumference \(=2πr \)
\(r=6 \) \(\text{ cm }\), then: Circumference \(=2π(6)=12π \)
\(π=3.14\), then: Circumference \(=12×3.14=37.68\) \(\text{ cm }\) For additional educational resources,.
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Exercises for Solving Circles
Find the area and circumference of each circle. \((\pi=3.14)\)
Download Circles Worksheet

- \(\color{blue}{\text{ Area }: \ 50.24 \ \text{ in }^2, \ \text{ Circumference }: \ 25.12 \ \text{ in }}\)
- \(\color{blue}{\text{ Area }: \ 1,017.36 \ \text{ cm }^2, \ \text{ Circumference }: \ 113.04 \ \text{ cm }}\)
- \(\color{blue}{\text{ Area }: \ 78.5 \ m^2, \ \text{ Circumference }: \ 31.4 \ m}\)
- \(\color{blue}{\text{ Area }: \ 379.94 \ \text{ cm }^2, \ \text{ Circumference }: \ 69.08 \ \text{ cm }}\)
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