# How to Find the Center and the Radius of Circles? (+FREE Worksheet!)

To find the center and radius of a circle from its equation, you need to find the *equation* of the *circle* in is the *center*-*radius* form.

## Related Topics

- How to Find Arc Length and Sector Area
- How to Find Equation of a Circle
- How to Find the Area and Circumference of Circles

## Rules for Finding the Center and the Radius of Circles

To find the center and the radius of a circle using the equation of the circle:

- Write the equation of the circle in standard form: \((x- h)^2+( y-k)^2= r^2\),
- The center of the circle is at \(h,k\), and its radius is \(r\).

### Find the Center and the Radius of Circles **– Example 1:**

Identify the center and the radius of each circle.

\(x^2+ y^2-4x+3=0\)

**Solution:**

\((x- h)^2+( y-k)^2= r^2\) is the circle equation with a radius \(r\), centered at \(h,k\).

Rewrite \(x^2+ y^2-4x+3=0\) in the standard form:

\(x^2+ y^2-4x+3=0→(x-2)^2+(y-0)^2=1^2 \)

Then, the center is at: \((2,0)\) and \(r=1\)

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### Find the Center and the Radius of Circles **– Example 2:**

Identify the center and the radius of each circle.

\(8x+x^2+10y=8- y^2\)

**Solution:**

\((x- h)^2+( y-k)^2= r^2\) is the circle equation with a radius \(r\), centered at \(h,k\).

Rewrite the equation in standard form:

\(8x+x^2+10y=8- y^2→(x-(-4))^2+(y-(-5))^2=7^2 \)

Then, the center is at \((-4,-5)\) and the \(r=7\).

### Find the Center and the Radius of Circles **– Example 3:**

Identify the center and radius.

\(8x+x^2-2y=8- y^2 \)

**Solution: **

\((x- h)^2+( y-k)^2= r^2\) is the circle equation with a radius \(r\), centered at \(h,k\).

Rewrite \(8x+x^2-2y=8- y^2\) in the standard form:

\((x-(-4))^2+(y-1)^2=5^2\)

Then, the center is at \((-4,1)\) and \(r=5\)

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