How to Find the Center and the Radius of Circles? (+FREE Worksheet!)
- Write the equation of the circle in standard form: \((x- h)^2+( y-k)^2= r^2\),
- The center of the circle is at \(h,k\), and its radius is \(r\).
Find the Center and the Radius of Circles – Example 1:
\(x^2+ y^2-4x+3=0\)
Find the Center and the Radius of Circles: what to notice and how to work it
What to notice first
Common student mistake
Key formulas and cues
A reliable path
- Match the formIdentify the conic by its equation pattern.
- Read featuresFind the center, vertex, radius, axes, foci, or asymptotes.
- Sketch from anchorsPlot key points first, then draw the curve.
Worked examples
Circle center and radius
- Compare to circle standard form.
- The center is (4, -1).
- The radius is the square root of 25.
Parabola direction
- The x part is squared.
- The parabola opens up or down.
- The positive coefficient means it opens up.
Try one before moving on
Find the Center and the Radius of Circles: pop-up practice
Solution:
\((x- h)^2+( y-k)^2= r^2\) is the circle equation with a radius \(r\), centered at \(h,k\).
Rewrite \(x^2+ y^2-4x+3=0\) in the standard form:
\(x^2+ y^2-4x+3=0→(x-2)^2+(y-0)^2=1^2 \)
Then, the center is at: \((2,0)\) and \(r=1\)
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Find the Center and the Radius of Circles – Example 2:
Identify the center and the radius of each circle.
\(8x+x^2+10y=8- y^2\)
Solution:
\((x- h)^2+( y-k)^2= r^2\) is the circle equation with a radius \(r\), centered at \(h,k\).
Rewrite the equation in standard form:
\(8x+x^2+10y=8- y^2→(x-(-4))^2+(y-(-5))^2=7^2 \)
Then, the center is at \((-4,-5)\) and the \(r=7\).
Find the Center and the Radius of Circles – Example 3:
Identify the center and radius.
\(8x+x^2-2y=8- y^2 \)
Solution:
\((x- h)^2+( y-k)^2= r^2\) is the circle equation with a radius \(r\), centered at \(h,k\).
Rewrite \(8x+x^2-2y=8- y^2\) in the standard form:
\((x-(-4))^2+(y-1)^2=5^2\)
Then, the center is at \((-4,1)\) and \(r=5\)
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