How to Find Domain and Range of Radical Functions

How to Find Domain and Range of Radical Functions

There are several different methods to identify the Domain and Range of Radical Functions. In this blog post, you will learn how to find the Domain and Range of Radical Functions.

Related Topics

Rules for Finding Domain and Range of Radical Functions

  • To find the domain of the function, find all possible values of the variable inside radical.
  • Remember that having a negative number under the square root symbol is not possible. (For cubic roots, we can have negative numbers)
  • To find the range, plugin the minimum and maximum values of the variable inside the radical.

Examples

Domain and Range of Radical Functions – Example 1:

Find the domain and range of the radical function. \(y=\sqrt{x-3}\)

Solution:

For domain: Find non-negative values for radicals: \(x-3≥0\)
Domain of functions: \(\sqrt{f(x)} →f(x)≥0\), Then solve \(x-3≥0→x≥3\)
Domain of the function\( y=\sqrt{x-3}: x≥3\)
For range: The range of a radical function of the form \(c\sqrt{ax+b}+k\) is:
\(f(x)≥k\)
For the function \(y=\sqrt{x-3}\), the value of k is 0. Then: \(f(x)≥0\) Range of the function \(y=\sqrt{x-3}: f(x)≥0\)

Domain and Range of Radical Functions – Example 2:

Find the domain and range of the radical function. \(y=\sqrt{x-8}+5\)

Solution:

For domain: Find non-negative values for radicals: \(x-8≥0\)
Then solve for \(x: x-8≥0→x≥8\)
Domain: \(x≥8\)
For range: the range of a radical function of the form \(c\sqrt{ax+b}+k\) is \(f(x)≥k\)
\(k=5\), Then: \(f(x)≥5\)

Domain and Range of Radical Functions – Example 3:

Find the domain and range of the radical function. \(y=\sqrt{2x+4}+9\)

Solution:

For domain: Find non-negative values for radicals: \(2x+4≥0\)
Then solve for \(x: 2x+4≥0→x≥-2\)
Domain: \(x≥-2\)
For range: the range of a radical function of the form \(c\sqrt{ax+b}+k\) is \(f(x)≥k\)
\(k=9\), Then: \(f(x)≥9\)

Domain and Range of Radical Functions – Example 4:

Find the domain and range of the radical function. \(y=3\sqrt{2x-10}+6\)

Solution:

For domain: Find non-negative values for radicals: \(2x-10≥0\)
Then solve for \(x: 2x-10≥0→x≥5\)
Domain: \(x≥5\)
For range: the range of a radical function of the form \(c\sqrt{ax+b}+k\) is \(f(x)≥k\)
\(k=6\), Then: \(f(x)≥6\)

Exercises for Domain and Range Radical Functions

Identify the Domain and Range

  1. \(\color{blue}{y=\sqrt{x-1}}\)
  2. \(\color{blue}{y=2\sqrt{x+3}}\)
  3. \(\color{blue}{y=\sqrt{x-5}}\)
  4. \(\color{blue}{y=\sqrt{x+4}+2}\)

Sketch the graph of the function

5. \(\color{blue}{y=\sqrt{x}-2}\)

6. \(\color{blue}{y=3\sqrt{x}-1}\)

  1. \(\color{blue}{x≥1,y≥0}\)
  2. \(\color{blue}{x≥-3,y≥0}\)
  3. \(\color{blue}{x≥5,y≥0}\)
  4. \(\color{blue}{x≥-4,y≥2}\)

5. \(\color{blue}{y=\sqrt{x}-2}\)

6. \(\color{blue}{y=3\sqrt{x}-1}\)

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