# Algebra Puzzle – Challenge 58

This math puzzle practices a wide variety of math skills. You need to use all the basic operator skills you can think of.

## Challenge:

Three times of Michael’s money equals \(\frac{2}{3}\) of Jackson’s money. If the sum of their money is $2200, how much money does Michael have?

**A-** 200

**B-** 400

**C-** 1000

**D-** 1600

**E-** 1800

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The correct answer is B.

Let M be Michael’s money and J be Jackson’s money. Therefore:

M + J = 2200 and 3M \(= \frac{2}{3} J →M = \frac{2}{9} J\)

Replace the value of M in the first equation with its value in the second equation.

\(\frac{2}{9} J + J = 2200→ J = 1800\)

\(M = \frac{2}{9} J → M = \frac{2}{9} (1800) = 400\)

Michael has $400.

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