Algebra Puzzle – Challenge 58
This math puzzle practices a wide variety of math skills. You need to use all the basic operator skills you can think of.
Challenge:
Three times of Michael’s money equals \(\frac{2}{3}\) of Jackson’s money. If the sum of their money is $2200, how much money does Michael have?
A- 200
B- 400
C- 1000
D- 1600
E- 1800
The Absolute Best Book to Challenge Your Smart Student!
$11.99
Satisfied 123 Students
The correct answer is B.
Let M be Michael’s money and J be Jackson’s money. Therefore:
M + J = 2200 and 3M \(= \frac{2}{3} J →M = \frac{2}{9} J\)
Replace the value of M in the first equation with its value in the second equation.
\(\frac{2}{9} J + J = 2200→ J = 1800\)
\(M = \frac{2}{9} J → M = \frac{2}{9} (1800) = 400\)
Michael has $400.
The Best Books to Ace Algebra
$14.99
Satisfied 1 Students
$14.99
Satisfied 92 Students
$15.99
Satisfied 125 Students
Related to This Article
More math articles
- How to Identify Independent and Dependent Events?
- A Comprehensive Collection of Free ASVAB Math Practice Tests
- TExES Core Subjects Math- Test Day Tips
- How to Divide Rational Expressions? (+FREE Worksheet!)
- The Ultimate 6th Grade PARCC Math Course (+FREE Worksheets)
- Unlocking Trigonometric Secrets: A Comprehensive Guide to Double-Angle and Half-Angle Formulas
- The Butterfly Effect in Mathematics: Small Changes, Big Impact
- How to Find the Area and Perimeter of the Semicircle?
- How To Create a Distraction-Free Study Environment: 10 Tips
- What are the four Branches of Mathematics?
What people say about "Algebra Puzzle – Challenge 58 - Effortless Math: We Help Students Learn to LOVE Mathematics"?
No one replied yet.