Algebra Puzzle – Challenge 58
Algebra Puzzle - Challenge 58 is a multiple-choice math challenge from Effortless Math. Read the problem, choose from the answer options below, then open the solution to see the full step-by-step working and check your reasoning against it.
This math puzzle practices a wide variety of math skills. You need to use all the basic operator skills you can think of.
Challenge:
Three times of Michael’s money equals (frac{2}{3}) of Jackson’s money. If the sum of their money is $2200, how much money does Michael have?
A- 200
B- 400
C- 1000
D- 1600
E- 1800
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The correct answer is B.
Let M be Michael’s money and J be Jackson’s money. Therefore:
M + J = 2200 and 3M (= frac{2}{3} J →M = frac{2}{9} J)
Replace the value of M in the first equation with its value in the second equation.
(frac{2}{9} J + J = 2200→ J = 1800)
(M = frac{2}{9} J → M = frac{2}{9} (1800) = 400)
Michael has $400.
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