Taking the HiSET Math test? Try the following FREE HiSET Math sample questions. Reviewing practice questions is the best way to brush up on your Math skills and prepare for the HiSET Math test. Here, we walk you through solving 10 common HiSET Math practice problems covering the most important math topics on the HiSET test.

These HiSET Math practice questions are designed to be similar to those found on the real HiSET Math test. They will assess your level of preparation and will give you a better idea of what to study on your exam.

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## 10 Sample **HiSET** Math Practice Questions

1- Which of the following could be the product of two consecutive prime numbers?

A. 2

B. 10

C. 14

D. 15

E. 20

2- Sophia purchased a sofa for $530.40. The sofa is regularly priced at $624. What was the percent discount Sophia received on the sofa?

A. \(12\%\)

B. \(15\%\)

C. \(20\%\)

D. \(25\%\)

E. \(40\%\)

3- The score of Emma was half as that of Ava and the score of Mia was twice that of Ava. If the score of Mia was 60, what is the score, Emma?

A. 12

B. 15

C. 20

D. 30

E. 40

4- A bag contains 18 balls: two green, five black, light blue, a brown, a red, and one white. If 17 balls are removed from the bag at random, what is the probability that a brown ball has been removed?

A. \(\frac{1}{9}\)

B. \(\frac{1}{6}\)

C. \(\frac{16}{17}\)

D. \(\frac{17}{18}\)

E. \(\frac{1}{2}\)

5- The average of five consecutive numbers is 38. What is the smallest number?

A. 38

B. 36

C. 34

D. 12

E. 8

6- How many tiles of 8 cm\(^2\) is needed to cover a floor of dimension 6 cm by 24 cm?

☐A. 6

☐B. 12

☐C. 18

☐D. 24

☐E. 36

7- A rope weighs 600 grams per meter in length. What is the weight in kilograms of 12.2 meters of this rope? (1 kilograms \(=\) 1000 grams)

A. 0.0732

B. 0.732

C. 7.32

D. 7320

E. 73200

8- A chemical solution contains \(4\%\) alcohol. If there are 24 ml of alcohol, what is the volume of the solution?

A. 240 ml

B. 480 ml

C. 600 ml

D. 1200 ml

E.2400 ml

9-The average weight of 18 girls in a class is 60 kg and the average weight of 32 boys in the same class is 62 kg. What is the average weight of all the 50 students in that class?

A. 60

B. 61.28

C. 61.68

D. 61.90

E. 62.20

10- The price of a laptop is decreased by \(10\%\) to $360. What is its original price?

A. $320

B. $380

C. $400

D. $450

E. $500

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## Answers:

1- **D**

Some of prime numbers are: \(2, 3, 5, 7, 11, 13\)

Find the product of two consecutive prime numbers:

\(2 × 3 = 6\) (not in the options)

\(3 × 5 = 15\) (bingo!)

\(5 × 7 = 35\) (not in the options)

2- **B**

The question is this: 530.40 is what percent of 624?

Use percent formula:

\(part =\frac{percent}{100}× whole\)

\(530.40 =\frac{percent}{100}× 624\)

\(530.40 =\frac{percent× 624}{100}\)

\(⇒53040 = percent ×624 \)

\(percent = \frac{53040}{624}= 85\)

530.40 is \(85 \%\) of 624. Therefore, the discount is: \(100\% – 85\% = 15\%\)

3-** B**

If the score of Mia was 60, therefore the score of Ava is 30. Since, the score of Emma was half as that of Ava, therefore, the score of Emma is 15.

4- **D**If 17 balls are removed from the bag at random, there will be one ball in the bag.

The probability of choosing a brown ball is 1 out of 18. Therefore, the probability of not choosing a brown ball is 17 out of 18 and the probability of having not a brown ball after removing 17 balls is the same.

5- **B**

Let \(x\) be the smallest number. Then, these are the numbers:

\(x, x+1, x+2, x+3, x+4\)

\(average = \frac{sum \space of \space terms}{number \space of \space terms}\)

\(38 = \frac{x+(x+1)+(x+2)+(x+3)+(x+4)}{5}\)

\(38=\frac{5x+10}{5}\)

\(⇒ 190 = 5x+10 ⇒ 180 = 5x ⇒ x=36\)

6- **C**

The area of the floor is: \(6 \)cm \(× 24\) cm \(= 144\) cm

The number is tiles needed \(= 144 ÷ 8 = 18\)

7- **C**

The weight of 12.2 meters of this rope is: \(12.2 × 600 g = 7320 g\)

\(1 kg = 1000 g\), therefore, \(7320 g ÷ 1000 = 7.32 kg\)

8- **C**

\(4\%\) of the volume of the solution is alcohol. Let \(x\) be the volume of the solution.

Then: \(4\%\) of \(x = 24\) ml \(⇒ 0.04 x = 24 ⇒ x = 24 ÷ 0.04 = 600\)

9- **B**

\(average =\frac{sum \space of \space terms}{number \space of \space terms}\)

The sum of the weight of all girls is: \(18 × 60 = 1080\) kg

The sum of the weight of all boys is: \(32 × 62 = 1984\) kg

The sum of the weight of all students is: \(1080 + 1984 = 3064\) kg

\(average =\frac{3064}{50}= 61.28\)

10- **C**

Let \(x\) be the original price.

If the price of a laptop is decreased by \(10\%\) to $360, then: \(90 \%\) of \(x=360⇒ 0.90x=360 ⇒ x=360÷0.90=400\)

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