FREE 8th Grade SBAC Math Practice Test
FREE 8th Grade SBAC Math Practice Test: work through realistic questions in the same format and difficulty as the real test, then check every answer against a full step-by-step solution so you can see where you lost marks and what to review next.
The Absolute Best Book to Ace 8th Grade SBAC Math Test
Getting ready for SBAC (Smarter Balanced Assessment Consortium) math in grade 8? The 20 questions below are written for 8th graders and cover linear equations and functions, slope, systems of equations, the Pythagorean theorem, volume, exponents and scientific notation, and data analysis. Each question has a worked solution, and the numbers differ from the other grade 8 sets on this site, so you can practice with fresh problems.
These are original practice questions aligned to grade 8 math skills, not official released test items. Use them to find the topics you need to review before test day.
20 practice questions for 8th Grade SBAC Math
Answer one question at a time. Press Submit to see right away whether you were correct, along with the worked solution. Your score appears after the last question, with a list of the ones to review.
Use the formula for the area of circles.
Area \(= πr^2 ⇒ 64 π = πr^2 ⇒ 64 = r^2 ⇒ r = 8\)
The radius of the circle is 8. Now, use the circumference formula:
Circumference\( = 2πr = 2π (8) = 16 π\)
Compare each mark:
In Algebra Joe scored 20 out of 25 in Algebra. It means Joe scored \(80\%\) of the total mark.
\(\frac{20}{25}=\frac{x}{100}⇒x= 80%\)
Joe scored 30 out of 40 in science. It means Joe scored \(75\%\) of the total mark.
\(\frac{30}{40}=\frac{x}{100}⇒x= 75%\)
Joe scored 68 out of 80 in mathematics that it means \(85\%\) of the total mark.
\(\frac{68}{80}=\frac{x}{100}⇒x= 85%\)
Therefore, his score in mathematics is higher than his other scores.
Write the proportion and solve for the missing number.
\(\frac{32}{12}=\frac{6}{x}→ 32x=6×12=72 \)
\(32x=72→x=\frac{72}{32}=2.25\)
To find the discount, multiply the number by (\(100\% –\) rate of discount).
Therefore, for the first discount we get: \((200) (100\% – 15\%) = (200) (0.85)\)
For the next \(15\%\) discount: \((200) (0.85) (0.85)\)
When a point is reflected over \(x\) axis, the \((y)\) coordinate of that point changes to \((-y)\) while its \(x\) coordinate remains the same.
\(C (7, 9) → C’ (7, -9)\)
\(13<-3x-2<22\)→ Add 2 to all sides. \(13+2<-3x-2+2<22+2\)
\(→15<-3x<24\)→ Divide all sides by \(- 3\). (Remember that when you divide all sides of an inequality by a negative number, the inequality sign will be swapped. < becomes >)
\(\frac{15}{-3} > \frac{-3x}{3} >\frac{24}{-3} \)
\(-8 < x < -5\)
Quiz complete
Best 8th Grade SBAC Math Prep Resource for 2027
Answers and explanations
Every worked solution opens in the quiz box as soon as you submit that question, so you can compare your method with the solution while it is fresh. Press Try again on the last screen to work through the set a second time.
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