Top 10 TABE Math Practice Questions
Start your TABE Math test prep journey right now with these sample TABE Math questions.
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ofa is decreased by \(15\% \) to \($476\). What was its original price?
A. \($480\)
B. \($520\)
C. \($560\)
D. \($600\)
7- Right triangle ABC has two legs of lengths \(9 cm\) AB and \(12 cm\) AC. What is the length of the third side BC?
A. \(6 cm\)
B. \(8 cm\)
C. \(14 cm\)
D. \(15 cm\)
8- If \(40\%\) of a class are girls, and \(25\%\) of girls play tennis, what percent of the class play tennis?
A. \(10\%\)
B. \(15\%\)
C. \(20\%\)
D. \(40\%\)
9- The area of a circle is less than \(36 π\). Which of the following can be the circumference of the circle?
A. \(10 π\)
B. \(12 π\)
C. \(24 π\)
D. \(36 π\)
10- Which of the following values for \(x\) and \(y\) satisfy the following system of equations?
\(\begin{cases}x+4y=10 \\ 5x+10y=10\end{cases}\)
A. \(x=3,y=2\)
B. \(x=2,y−3\)
C. \(x=−6,y=4\)
D. \(x=4,y=−2\)
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Answers:
1- C
Let \(x\) be the number. Write the equation and solve for \(x.(24-x)÷x=3\) Multiply both sides by \(x. (24-x) =3x\), then add \(x\) both sides. \(24=4x\), now divide both sides by \(4. x=6\)
2- A
The sum of supplement angles is \(180\). Let \(x\) be that angle. Therefore, \(x+9x =180,10x=180\), divide both sides by \(10: x=18\)
3- C
The average speed of john is: \(150÷6=25\) km, The average speed of Alice is: \(160÷4=40\) km.Write the ratio and simplify. \(25∶40 ⇒ 5:8\)
4- C
\($7×10=$70\), Petrol use: \(10×2=20\) liters. Petrol cost: \(20×$1=$20\)
Money earned: \($70-$20=$50\)
5- C
average \(=\frac{sum \ of \ terms}{number \ of \ terms}=\frac{12+ 13+7+21+22}{5} = \frac{75}{5} =15\)
6- C
Let \(x\) be the original price. If the price of the sofa is decreased by \(15\%\) to \($476\), then: \(85\%\) of \(x=476 ⇒ 0.85x=476 ⇒ x=476÷0.85=560\)
7- D
Use Pythagorean Theorem: \(a^2+b^2=c^2, 9^2+12^2= c^2 ⇒ 81+144=c^2⇒ 225=c^2⇒c=15\)
8- A
The percent of girls playing tennis is: \(40\%×25\% =0.40×0.25=0.10=10\%\)
9- A
The area of the circle is less than \(12 π\). Use the formula of areas of circles. Area \(=πr^2 ⇒ \)
\(36 π> πr^2⇒ 36>r^2⇒ r<6\). The radius of the circle is less than \(6\). Let’s put \(6\) for the radius. Now, use the circumference formula: Circumference \(=2πr=2π (6)=12 π\)
Since the radius of the circle is less than \(6\). Then, the circumference of the circle must be less than \(12 π\). Only choice A is less than \(12 π\).
10- C
\(\begin{cases}x+4y=10 \\ 5x+10y=10\end{cases}\rightarrow\) Multiply the top equation by \(-5\) then,
\(\begin{cases}-5x-20y=-50 \\ 5x+10y=10\end{cases}\rightarrow\) Add two equations
\(-10y=-40→y=4\) , plug in the value of y into the first equation
\(x+4y=10→x+4(4)=10→x+16=10\)
Subtract \(16\) from both sides of the equation. Then: \(x+16=10→x=-6\)
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