Top 10 SSAT Middle-Level Math Practice Questions

Top 10 SSAT Middle-Level Math Practice Questions is a multiple-choice math challenge from Effortless Math. Read the problem, choose from the answer options below, then open the solution to see the full step-by-step working and check your reasoning against it.

B. (234) cm(^2)

C. (216) cm(^2)

D. (130) cm(^2)

E. (108) cm(^2)

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Answers:

2- D
(2×0.4=0.8), all choices provided are equal to (0.8) except option D. (frac{5}{15}×3=1)

3- C
Sara has M books. Mary has (6) more books than Sara. Then, Mary has (M+6 ) books. If Mary gives Sara (4) books, Mary will have: (M+6-4=M+2)

4- E
If (frac{x}{2}=30), then (frac{3x}{2}) is (3) times (frac{x}{2}). The answer is (90).

5- D
(frac{1}{6}) of (40) is (6.66). Let’s review the choices provided:
A. ( 0.3×6=1.8)
B. ( 0.3×5=1.5)
C ( 0.2×30=6)
D ( 0.2×35=7)
E ( 0.2×39.5=7.9)
Option D is the closest to (6.66)

6- B
The diagonal of the square is (8). Let (x) be the side.
Use Pythagorean Theorem: (a^2+b^2=c^2)
(x^2 +x^2 = 8^2 ⇒ 2x^2 = 8^2 ⇒ 2x^2 = 64 ⇒x^2 = 32 ⇒x= sqrt{32})
The area of the square is: (sqrt{32}×sqrt{32}=32)

7- B
The sum of supplement angles is (180). Let (x ) be that angle. Therefore, (x+5x=180)
(6x=180), divide both sides by (6: x=30)

8- B
Use the formula for Percent of Change: (frac{New Value-Old Value}{Old Value}×100% )
(frac{28-44}{44}×100%≈-36%) (negative sign here means that the new price is less than old price)

9- B
One liter (=1,000 ) cm(^3 → 6) liters (=6,000) cm(^3 ), (6,000=25×5×h→h=frac{6,000}{125}=48) cm

10- A
The perimeter of the trapezoid is (64).
Therefore, the missing side (height) is (= 64-18- 12-14 = 20)
Area of the trapezoid: A (= frac{1}{2} h (b_{1}+b_{2 })= frac{1}{2} (10) (12 + 14)=260)

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