Preparing your student for the SSAT Middle Level Math test? The best way to prepare your student for the SSAT Middle-Level Math test is to work through as many SSAT Middle-Level Math practice questions as possible. Here are the top 10 SSAT Middle-Level Math practice questions to help your student reviews the most important SSAT Middle-Level Math concepts. These SSAT Middle-Level Math practice questions are designed to cover mathematics concepts and topics that are found on the actual test. The questions have been fully updated to reflect the latest 2021 SSAT Middle-Level guidelines. Answers and full explanations are provided at the end of the post.

Help your student starts his/her SSAT Middle Level Math test prep journey right now with these sample SSAT Middle Level Math questions.

## The Absolute Best Book** to Ace the SSAT Middle Level** **Math** Test

## SSAT Middle Level Math Practice Questions

1- If \(30\) percent of a number is \(60\), then \(20\) percent of the same number is …

A. 12

B. 18

C. 25

D. 30

E. 40

2- Which of the following is NOT equal to \(2×0.4\)?

A. \( 4×0.2\)

B. \( 1×0.8\)

C. \( \frac{16}{8}×\frac{4}{10}\)

D. \(\frac{5}{15}×3\)

E.\( 0.8×1\)

3- Sara has M books. Mary has \(6\) more books than Sara. If Mary gives Sara \(4\) books, how many books will Mary have, in terms of \(M\)?

A. \(M\)

B. \(M+1\)

C. \(M+2\)

D. \(M+6\)

E.\(M-6\)

4- If \(\frac{x}{2}=30\), then \(\frac{3x}{2}=\)?

A. 10

B. 20

C. 30

D. 45

E. 90

5- Which of the following is closest to \(\frac{1}{6}\) of \(40\)?

A. \( 0.3×6\)

B. \( 0.3×5\)

C. \( 0.2×30\)

D. \( 0.2×35\)

E. \( 0.2×39.5\)

6- What is the area of a square whose diagonal is \(8\)?

A. 16

B. 32

C. 36

D. 64

E. 80

7- An angle is equal to one fifth of its supplement. What is the measure of that angle?

A. 20

B. 30

C. 45

D. 60

E. 150

8- A \($44\) shirt now selling for \($28\) is discounted by approximately what percent?

A. \( 20\%\)

B. \( 36\%\)

C. \( 40\%\)

D. \( 60\%\)

E.\( 80\%\)

9- \(6\) liters of water are poured into an aquarium that’s \(25\) cm long, \(5\) cm wide, and \(60\) cm high. How many centimeters will the water level in the aquarium rise due to this added water? \((1) liter of water (=1,000) cm(^3)\)

A. 80

B. 48

C. 20

D. 10

E. 8

10- The perimeter of the trapezoid below is 64 cm. What is its area?

A. \(260\) cm\(^2\)

B. \(234\) cm\(^2\)

C. \(216\) cm\(^2\)

D. \(130\) cm\(^2\)

E. \(108\) cm\(^2\)

## Best ** SSAT Middle Level** Math Prep Resource for 2021

## Answers:

1- **E**

If \(30\) percent of a number is \(60\), then the number is: \(30\%\) of \(x=60→0.3x=60→x=\frac{60}{0.3}=\frac{600}{3}=200, 20\) percent of \(200\) is:\(20\%\) of \(200=\frac{20}{100}×200=40\)

2- **D**

\(2×0.4=0.8\), all choices provided are equal to \(0.8\) except option D. \(\frac{5}{15}×3=1\)

3- **C**

Sara has M books. Mary has \(6\) more books than Sara. Then, Mary has \(M+6 \) books. If Mary gives Sara \(4\) books, Mary will have: \(M+6-4=M+2\)

4- **E**

If \(\frac{x}{2}=30\), then \(\frac{3x}{2}\) is \(3\) times \(\frac{x}{2}\). The answer is \(90\).

5- **D**

\(\frac{1}{6}\) of \(40\) is \(6.66\). Let’s review the choices provided:

A. \( 0.3×6=1.8\)

B. \( 0.3×5=1.5\)

C \( 0.2×30=6\)

D \( 0.2×35=7\)

E \( 0.2×39.5=7.9\)

Option D is the closest to \(6.66\)

6- **B**

The diagonal of the square is \(8\). Let \(x\) be the side.

Use Pythagorean Theorem: \(a^2+b^2=c^2\)

\(x^2 +x^2 = 8^2 ⇒ 2x^2 = 8^2 ⇒ 2x^2 = 64 ⇒x^2 = 32 ⇒x= \sqrt{32}\)

The area of the square is: \(\sqrt{32}×\sqrt{32}=32\)

7- **B**

The sum of supplement angles is \(180\). Let \(x \) be that angle. Therefore, \(x+5x=180\)

\(6x=180\), divide both sides by \(6: x=30\)

8- **B**

Use the formula for Percent of Change: \(\frac{New \ Value-Old \ Value}{Old Value}×100\% \)

\(\frac{28-44}{44}×100\%≈-36\%\) (negative sign here means that the new price is less than old price)

9- **B**

One liter \(=1,000 \) cm\(^3 → 6\) liters \(=6,000\) cm\(^3 \), \(6,000=25×5×h→h=\frac{6,000}{125}=48\) cm

10- **A**

The perimeter of the trapezoid is \(64\).

Therefore, the missing side (height) is \(= 64-18- 12-14 = 20\)

Area of the trapezoid: A \(= \frac{1}{2} h (b_{1}+b_{2 })= \frac{1}{2} (10) (12 + 14)=260\)

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