Top 10 OAR Math Practice Questions
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>C. 44
D. 35
8- A swimming pool holds 2,000 cubic feet of water. The swimming pool is 25 feet long and 10 feet wide. How deep is the swimming pool?_______
9- The area of a circle is \(64 π\). Which of the following is the circumference of the circle?
A. 8\(\pi\)
B. 12\(\pi\)
C. 16\(\pi\)
D. 64\(\pi\)
10- What is the value of \(3^6 \) ?______
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Answers:
1- D
Plug in the value of \(x\) and \(y\).
\(x=3\) and \(y=-2\)
\((5(x-2y)+(2-x)^2)=(5(3-2(-2))+(2-3)^2)=(5(3+4)+(-1)^2)= (35)+1=36\)
2- D
The equation of a line in slope intercept form is: \(y=mx+b\)
Solve for y.
\(4x-2y=12 {\Rightarrow} -2y=12-4x {\Rightarrow} y=(12-4x){\div}(-2) {\Rightarrow} y=2x-6\)
The slope of this line is 2.
The product of the slopes of two perpendicular lines is -1.
Therefore, the slope of a line that is perpendicular to this line is:
\(m_{1} {\times} m_{2} = -1 {\Rightarrow} 2 {\times} m_{2} = -1 {\Rightarrow} m_{2} = \frac{-1}{2}\)
3- D
Use the FOIL method.
\((2x+2y)(2x-y) = 4x^2-2xy+4xy-2y^2=4x^2+2xy-2y^2\)
4- D
To solve absolute value equations, write two equations.
\(x-10\) could be positive 3, or negative 3. Therefore,
\(x-10=3 \Rightarrow x=13\)
\(x-10=-3 \Rightarrow x=7\)
Find the product of solutions: \(7 \times 13 = 91\)
5- C
Use PEMDAS (order of operation):
\([6 {\times} (- 24) + 8] – (- 4) + [4 × 5] {\div} 2 \)
\( [- 144 + 8] – (- 4) + [20] {\div} 2 =
[- 144 + 8] – (- 4) + 10 \)
\([- 136] – (- 4) + 10 = [- 136] + 4 + 10 = – 122\)
6- D
Solving Systems of Equations by Elimination
Multiply the first equation by (-2), then add it to the second equation.
\({-2(2x+5y= 11) \ 4x-2y=-14} {\Rightarrow} {-4x-10y= -22 \ 4x-2y=-14} {\Rightarrow} {-12y= -36} {\Rightarrow} {y= 3}\)
Plug in the value of y into one of the equations and solve for x.
\(2x+5(3)= 11 {\Rightarrow} 2x+15= 11 {\Rightarrow} 2x= -4 {\Rightarrow} x= -2\)
7- B
Write the numbers in order:
2, 19, 27, 28, 35, 44, 67
The median is the number in the middle. So, the median is 28
8- 8
Use the formula of rectangle prism volume.
\(V = (length) (width) (height) {\Rightarrow} 2000 = (25) (10) (height) {\Rightarrow} height = 2000 {\div} 250 = 8\)
9- C
The area of the circle is \(16 π\). Use the formula of areas of circles.
\(Area = πr^2 ⇒ 64 π> πr^2⇒ 64 > r^2⇒ r < 8\)
The radius of the circle is 8. Let’s put 8 for the radius. Now, use the circumference formula:
\(Circumference =2πr=2π (8)=16π\)
10- 729
\((3^6 ) = 3 × 3 × 3 × 3 × 3 × 3 = 729\)
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