Imagine that your student has passed the 6th Grade Georgia Milestones Assessment System Math exam with satisfaction and an excellent score! This dream is not out of reach! The realization of this dream is possible only with sufficient study and enough practice. In this article, we have provided more practicing conditions for your 6th Grade student. We have prepared the top 10 6th Grade Georgia Milestones Assessment System Math test questions along with their solutions for your 6th Grade students. Help your students start their GMAS Math test prep journey right now with these sample Georgia Milestones Assessment System Math questions.

Make sure to follow some of the related links at the bottom of this post to get a better idea of what kind of mathematics questions students need to practice.

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## 6th Grade Georgia Milestones Assessment System Math Practice Questions

1- Which expression is equivalent to \(5(12x-16)\)?

A. \(-20\)

B. \(-20x\)

C. \(60x – 16\)

D. \(60x – 80\)

2- To produce a special concrete, for every 13 kg of cement, 3 liters of water is required. Which of the following ratios is the same as the ratio of cement to liters of water?

A. 91: 21

B. 14: 4

C. 39: 6

D. 9: 39

3- What is the value of \(x\) in the following equation: \(-60=115-x\)

A. 175

B. \(-175\)

C. 55

D. \(-55\)

4- Which of the following graphs represents the following inequality?

\(-8≤5x-8≤2\)

A.

B.

C.

D.

5- The ratio of boys to girls in a school is 4:5. If there are 765 students in the school, how many boys are in the school?

A. 612

B. 510

C. 425

D. 340

6- Martin earns $20 an hour. Which of the following inequalities represents the amount of time Martin needs to work per day to earn at least $100 per day?

A. \(20t≥100\)

B. \(20t≤100\)

C. \(20+t≥100\)

D. \(20+t≤100\)

7- \((55+5)÷12\) is equivalent to …

A. \(60÷3.4\)

B. \( \frac{55}{12}+5\)

C. \((2×2×3×5)÷(3×4)\)

D. \( (2×2×3×5)÷3+4\)

8- What is the value of the expression \(6(2x-3y)+(3-2x)^2\), when \(x=2 \) and \(y=-1\)?

A. \(-23\)

B. 41

C. 43

D. 49

9- Round \(\frac{215}{7}\) to the nearest tenth.

A. 31

B. 30.8

C. 30.7

D. 30

10- A chemical solution contains \(6\%\) alcohol. If there is 45 ml of alcohol, what is the volume of the solution?

A. 270 ml

B. 420 ml

C. 750 ml

D. 1,200 ml

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## Answers:

1- **D**

\(5(12x-16)=(5×12x)-(5×16)=(5×12)x-(5×16)=60x-80\)

2- **A**

\(91 : 21 = 13 : 3\)

\(13×7=91\)

And \( 3×7=21\)

3- **A**

\(-60 = 115 – x\)

First, subtract 115 from both sides of the equation. Then:

\(-60 – 115=115 – 115- x→-175 = – x\)

Multiply both sides by \((-1)\):

\(→x = 175\)

4- **B**

\(-8≤5x-8<2 →\) (add 8 all sides)\(-8+8≤5x-8+8<2+8 →0≤5x<10→\) (divide all sides by 5) \(0≤x<2\)

5- **D**

The ratio of boy to girls is 4:5. Therefore, there are 4 boys out of 9 students. To find the answer, first divide the total number of students by 9, then multiply the result by 4.

\(765 ÷ 9 = 85 ⇒ 85 × 4 = 340\)

6- **A**

For one hour he earns $20, then for t hours he earns $20t. If he wants to earn at least $100, therefor, the number of working hours multiplied by 20 must be equal to 100 or more than 100.

\(20t≥100\)

7- **C**

\((55+5)÷(12)=(60)÷(12)\)

The prime factorization of 60 is: \(2×2×3×5 \)

The prime factorization of 12 is: \( 3×4 \)

Therefore: \((60)÷(12)=(2×2×3×5)÷(3×4)\)

8- **C**

Plug in the value of \(x\) and \(y\) and use order of operations rule.

\(x=2\) and \(y=-1\)

\(6(2x-3y)+(3-2x)^2=6(2(2)-3(-1))+(3-2(2))^2=6(4+3)+(-1)^2 = 42+1=43\)

9- **C**

\(\frac{215}{7} ≅ 30.71 ≅ 30.7\)

10- **C**

\(6\%\) of the volume of the solution is alcohol. Let \(x\) be the volume of the solution.

Then: \(6\% \space of \space x = 45 \space ml ⇒ 0.06 x = 45 ⇒ x = 45 ÷ 0.06 = 750\)

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