Top 10 CLEP College Algebra Practice Questions

Top 10 CLEP College Algebra Practice Questions is a multiple-choice math challenge from Effortless Math. Read the problem, choose from the answer options below, then open the solution to see the full step-by-step working and check your reasoning against it.

B. ( y = 5x)

C. ( y≥x)

D. ( y+4x=z)

E. ( y>x)

9- What is the solution to the following inequality?
(|x-10|≤3)

A. (x≥13 ∪ x≤7)

B. ( 7≤x≤13)

C. ( x≥13 )

D. ( x≤7)

E. Set of real numbers

10- Two-third of 15 is equal to (frac{2}{5}) of what number?

A. 12

B. 20

C. 25

D. 60

E. 90

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Answers:

2- D
Here we can substitute 8 for (x) in the equation. Thus, (y-3=2(8+5), y-3=26)
Adding 3 to both sides of the equation: (y=26+3, y=29)

3- D
Use Pythagorean Theorem: (a^2+b^2=c^2⇒5^2+12 ^2=c^2⇒169=c^2⇒c=13)

4- E
The ratio of boys to girls is 2:3. Therefore, there are 2 boys out of 5 students. To find the answer, first, divide the total number of students by 5, then multiply the result by 2.
(500÷5=100 ⇒100 × 2=200)

5- E
Use FOIL (First, Out, In, Last).((7x+2y)(5x+2y)= )
(35x^2+14xy+10xy+4y^2=)
(35x^2+ 24xy+4y^2)

6- E
Use distributive property: (5x(4+2y)=20x+10xy)

7- E
(y=5ab+3b^3). Plug in the values of a and b in the equation: (a=2) and (b=3).
(y=5 (2)(3)+3 (3)^3=30+3(27)=30+81=111)

8- D
(x) and (z) are colinear. (y) and (5x) are colinear. Therefore,
(x+z=y+5x),subtract (x) from both sides,then,(z=y+4x)

9- B
(|x-10|≤3→-3≤x-10≤3→-3+10≤x-10+10≤3+10→7≤x≤13)

10- C
Let (x) be the number. Write the equation and solve for (x). (frac{2}{3} ×15= frac{2}{5}). (x⇒frac{2×15}{3}=frac{2x}{5 }), use cross multiplication to solve for (x). (5×30=2x×3⇒150=6x⇒x=25)

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Official source: the full list of CLEP exams, what each one covers and how colleges award credit for them are published by the College Board at clep.collegeboard.org.