How to Find the Polar Form of Complex Numbers?
The polar form of complex numbers is another way to display complex numbers. Here, you will learn more about finding the polar form of complex numbers.
[include_netrun_products_block from-products="product/6-virginia-sol-grade-3-math-practice-tests/" product-list-class="bundle-products float-left" product-item-class="float-left" product-item-image-container-class="p-0 float-left" product-item-image-container-size="col-2" product-item-image-container-custom-style="" product-item-container-size="" product-item-add-to-cart-class="btn-accent btn-purchase-ajax" product-item-button-custom-url="{url}/?ajax-add-to-cart={id}" product-item-button-custom-url-if-not-salable="{productUrl} product-item-container-class="" product-item-element-order="image,title,purchase,price" product-item-title-size="" product-item-title-wrapper-size="col-10" product-item-title-tag="h3" product-item-title-class="mt-0" product-item-title-wrapper-class="float-left pr-0" product-item-price-size="" product-item-purchase-size="" product-item-purchase-wrapper-size="" product-item-price-wrapper-class="pr-0 float-left" product-item-price-wrapper-size="col-10" product-item-read-more-text="" product-item-add-to-cart-text="" product-item-add-to-cart-custom-attribute="title='Purchase this book with single click'" product-item-thumbnail-size="290-380" show-details="false" show-excerpt="false" paginate="false" lazy-load="true"]
Complex numbers can be represented in polar form, which is a different approach from rectangular form. Complex numbers are typically represented as \(z = x+iy\), where \((x, y)\) are the rectangular coordinates.
Related Topics
- Identities of Complex Numbers
- How to Find Distance and Midpoint of Complex Numbers
- How to Solve the Complex Plane
Step-by-step guide to the polar form of complex numbers
Complex numbers are expressed in polar form as the combination of the modulus \(r\) and the complex number’s argument \(θ\). With coordinates of \((x,y)\), we can express the complex number in the manner of \(\color{blue}{z = r cos θ +i\ r sin θ= r ( cos θ + i\ sin θ )}\).
The polar form is represented with the help of polar coordinates of real and imaginary numbers in the coordinate system. Complex number \(A = x+i y\) in two-dimensional coordinate system:
- In this image above, we have:
\(\color{blue}{cos\ θ=\frac{x}{r}}\) ⇒ \(\color{blue}{x=r cos\ θ }\)
\(\color{blue}{sin\ θ=\frac{y}{r}}\) ⇒ \(\color{blue}{y=r sin\ θ }\)
- And using Pythagoras’ theorem, we have:
\(\color{blue}{r^2=x^2+y^2}\) ⇒ \(\color{blue}{r=\sqrt{(x^2+y^2)}}\)
\(\color{blue}{tan\ θ=\frac{y}{x}}\) ⇒ \(\color{blue}{θ=tan^{-1}(\frac{y}{x})}\)
- For example, the horizontal and vertical axes are known as the real and imaginary axes.
- In the complex number polar form, \(r\) is the length of the vector, and \(θ\) is the angle it makes with the real axis.
- A point with coordinates \(A\) exists \((x, y)\).
- As you can see, \(r\) is the distance from \((0,0)\) to point \(A\).
- The line connecting \(A\) with the origin produces a \(90\)-degree angle with a positive \(x\)-axis.
- As you can see, the polar coordinates \((r, θ)\) and the rectangle coordinates \((x, y)\) are both listed here \((x, y)\).
Complex-number polar form equation
With coordinates of \((x,y)\), we can express the complex number in the manner of \(z = r cos θ +i\ r sin θ = r ( cos θ + i\ sin θ )\). The abbreviated polar form of a complex number is \(z=r\ cis θ \), where \(r=\sqrt{(x^2+y^2)}\), and \( θ =tan^{-1}\frac{y}{x}\).
The polar form of a complex number has the following components:
- The absolute value of a complex number is represented by the symbol \(r\).
- Angle \(θ\) – The complex number argument is called the angle.
The Polar Form of Complex Numbers – Example 1:
Write the complex number in polar form. \(5+3i\)
First, find the absolute value of \(r\) by using this formula: \(\color{blue}{r=|z|=\sqrt{(x^2+y^2)}}\)
\(r=\sqrt{(5^2)+(3)^2} =\sqrt{25+9}=\sqrt{34}\)
\(r=\sqrt{34}≈5.83\)
Then, find the argument \(θ\) by using this formula: \(\color{blue}{θ=tan^{-1}(\frac{y}{x})}\).
\( θ =tan^{-1}(\frac{3}{5})=arctan(\frac{3}{5})=0.54\)
Now, write the polar form by using this formula: \(\color{blue}{z =r ( cos θ + i\ sin θ )}\).
\(z=5.83(cos(0.54)+i\sin(0.54))\)
The Polar Form of Complex Numbers – Example 2:
Write the complex number in polar form. \(3+4i\)
First, find the absolute value of \(r\) by using this formula: \(\color{blue}{r=|z|=\sqrt{(x^2+y^2)}}\)
\(r=\sqrt{(3^2)+(4)^2} =\sqrt{9+16}=\sqrt{25}\)
\(r=\sqrt{25} = 5\)
Then, find the argument \(θ\) by using this formula: \(\color{blue}{θ=tan^{-1}(\frac{y}{x})}\).
\( θ =tan^{-1}(\frac{4}{3})=arctan(\frac{4}{3})=0.92\).
Now, write the polar form by using this formula: \(\color{blue}{z =r ( cos θ + i\ sin θ )}\).
\(z=5(cos(0.92)+i\sin(0.92))\)
Exercises for the Polar Form of Complex Numbers
Write the complex number in the polar form.
- \(\color{blue}{5i}\)
- \(\color{blue}{-3+3i}\)
- \(\color{blue}{2+i}\)
- \(\color{blue}{3+7i}\)
- \(\color {blue}{z=5(cos(\frac{π}{2})+i sin(\frac{π}{2}))}\)
- \(\color {blue}{z=3\sqrt{2}(cos(\frac{-π}{4})+i sin(\frac{-π}{4}))}\)
- \(\color {blue}{z=\sqrt{5}(cos(0.46)+i sin(0.46))}\)
- \(\color {blue}{z=\sqrt{58}(cos(1.16)+i sin(1.16))}\)
Related to This Article
More math articles
- ALEKS Math Placement Review and FAQs
- 6th Grade RISE Math Worksheets: FREE & Printable
- Multiplying by 10, 100, and 1,000 for 4th Grade
- Order of Decimals, Mixed Numbers and Fractions
- Algebra 1 Worksheets: FREE & Printable
- Top 10 SSAT Middle-Level Math Practice Questions
- Cracking the Code: How Math is Empowering Students to Solve Real-World Problems in the Digital Age
- How to Balance the Scales: Inequalities with Addition and Subtraction of Mixed Numbers
- 3rd Grade NDSA Math Worksheets: FREE & Printable
- How to Unlock the Secrets of Algebra 1: Mastering the Basics with the ‘Grade 9 Algebra 1 for Beginners’ Comprehensive Solution Guide

























What people say about "How to Find the Polar Form of Complex Numbers? - Effortless Math: We Help Students Learn to LOVE Mathematics"?
No one replied yet.