TExES Core Math FREE Sample Practice Questions

3- B
The area of the square is 595.36. Therefore, the side of the square is a square root of the area.
\(\sqrt{595.36}=24.4\)
Four times the size of the square is the perimeter:\(4 \times 24.4 = 97.6\)

4- A
The width of the rectangle is twice its length. Let \(x\) be the length. Then, width \(=2x\)
Perimeter of the rectangle is (2 (width + length) \(= 2(2x+x)=60 {\Rightarrow} 6x=60 {\Rightarrow} x=10\)
The length of the rectangle is 10 meters.

5- D
average \(= \frac{sum \space of \space terms}{number \space of \space terms} {\Rightarrow} (average \space of \space 6 \space numbers) \space 12 = \frac{sum \space of \space terms}{6} ⇒\) sum of 6 numbers is
\(12 {\times} 6 = 72\)
(average of 4 numbers) 10 \(= \frac{sum \space of \space terms}{4}{\Rightarrow}\) sum of 4 numbers is \(10 {\times} 4 = 40\)
sum of 6 numbers \(-\) sum of 4 numbers = sum of 2 numbers
\(72 – 40 = 32\)
average of 2 numbers \(= \frac{32}{2} = 16 \)

6- C
Let \(x\) be the number. Write the equation and solve for \(x\).
\(40\%\) of \(x=4{\Rightarrow} 0.40 x=4 {\Rightarrow} x=4 {\div}0.40=10\)

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7- C
First, find the sum of five numbers.
average \(=\frac{ sum \space of \space terms }{ number \space of \space terms } ⇒ 24 = \frac{ sum \space of \space 5 \space numbers }{5}
⇒\) sum of 5 numbers \(= 24 × 5 = 120\)
The sum of 5 numbers is 120. If a sixth number that is 42 is added to these numbers, then the sum of 6 numbers is 162.
\(120 + 42 = 162\)
average \(=\frac{ sum \space of \space terms }{ number \space of \space terms } = \frac{162}{6}=27\)

8- C
The ratio of boy to girls is 4:7.
Therefore, there are 4 boys out of 11 students.
To find the answer, first, divide the total number of students by 11, then multiply the result by 4.
\(44 {\div} 11 = 4 {\Rightarrow} 4 {\times} 4 = 16\)
There are 16 boys and \(28 (44 – 16)\) girls. So, 12 more boys should be enrolled to make the ratio 1:1

9- 2
Solve for \(y\).
\(4x-2y=6 {\Rightarrow} -2y=6-4x {\Rightarrow} y=2x-3\)
The slope of the line is 2.

10- A
Let \(x\) be the number of new shoes the team can purchase. Therefore, the team can purchase \(120 x\).
The team had $20,000 and spent $14000. Now the team can spend on new shoes $6000 at most.
Now, write the inequality:
\(120x+14,000 {\leq}20,000\)

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